Dear Sir or Madam,

I am writing to enquire about the tour guide training courses at SGV Vocational School, which I recently read about online. I have always been passionate about traveling and learning about different cultures, so I am very interested in joining your program and would like to receive more detailed information.

First of all, I would like to ask about the length of the course. Although the advertisement states that the courses are available throughout the year, I would like to know how long each course lasts and how many classes are held per week.

Secondly, I would be grateful if you could provide more information about the tuition fees. I understand that the fees are described as affordable, but I would like to know the exact cost and whether there are any additional charges for materials, uniforms, or study trips.

Finally, I am also interested in the internship opportunities offered by your school. Could you please let me know which travel agencies or companies cooperate with the school and whether students are supported in finding a job after completing the course? I look forward to receiving your reply.

Yours faithfully,

Thao.

a)Áp dụng định luật Hooke ở trạng thái cân bằng:

Fđh​=P => k⋅Δl=m⋅g

\(\Delta l=\frac{m \cdot g}{k}=\frac{0 , 5 \cdot9 , 8}{100}=\frac{4 , 9}{100}=0,049\text{m}=4,9\text{cm}\)

b)Ta có:

Δlmax =10cm = Δl + A

=> A = Δlmax - Δl = 10-4,9 = 5,1cm

c)

Δl' = 4,9+6 = 10,9cm = 0,109m

=> F =k.Δl = 100.0,109 = 109 N\(\)

a)Gọi T1 là chu kì quay của Trái Đất quanh Mặt Trời

Ta có:

T1 = 365,25 ngày = 365,25.24.3600 = 31557600 s

R = 6400km = 6,4.\(10^6\)

r = 150 triệu km = 150.\(10^9\) m

ω1 = 2π/T=2π/365,25 = \(2.10^{-7}\) rad/s

v1​=ω1​(r+R)=30001 m/s

b)T2 là chu kì quay của Trái Đất quay mình nó

T2 = 24 giờ = 86400 s

ω2 = 2π/T2 =7,27.\(10^{-5}\) rad/s

v2 = ω2.R = 465 m/s

c)R' = 6400.cos 30= 6400.\(\frac{\sqrt3}{2}\) m

T3 = 24 giờ = 86400 s

ω3 = \(\frac{2\pi}{T3}\) =\(7,27.10^{-5}\) rad/s

v3 = ω3.R' = 402m/s

Đổi: 500g = 0,5kg; 300g = 0,3kg

Chọn chiều dương là chiều chuyển động của 2 viên bi

a) \(\) m1v1+m2v2= (m1+m2)v

<=> 0,5.4+0,3.v2 = (0,5+0,3)*3

<=>v2= 1,33m/s

b)Theo đề bài, ta có:

p2 = √ \(p^2+p1^2\)

Mà: p=(m1​+m2​)v=(0,5+0,3).3=2,4 kg.m/s

\(p_1=m_1\text{v}_1=0,5.4=2\) kg.m/s

=>p2 = 3,12 kg.m/s

=>v2 =p2/m2 = 3,12/0,3 = 10,4m/s\(\)