\(\frac{3}{4} + \frac{9}{5} \left(\left(\right. \frac{3}{2} - \frac{2}{3} \left.\right)\right)^{2} = \frac{3}{4} + \frac{9}{5} \left(\left(\right. \frac{5}{6} \left.\right)\right)^{2} = \frac{3}{4} + \frac{9}{5} \cdot \frac{25}{36} = \frac{3}{4} + \frac{5}{4} = 2\)

b) \(\frac{- 22}{25}+\left(\right.\frac{22}{7}-0,12\left.\right);=\frac{- 22}{25}+\left(\right.\frac{22}{7}-\frac{12}{100}\left.\right)=\frac{- 88}{100}+\frac{22}{7}+\frac{- 12}{100}=\left(\right.\frac{- 88}{100}+\frac{- 12}{100}\left.\right)+\frac{22}{7}=-1+\frac{22}{7}=\frac{15}{7}\)