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mình mở rồi
55
six seven
thắng này m động nhầm người rồi
hay
tốt lắm
Ta có thể rút gọn các hạng tử tương tự: 2x−2x+x2∶3x2−3x4=x2∶3x2−3x42 x minus 2 x plus x squared colon 3 x squared minus 3 x to the fourth power equals x squared colon 3 x squared minus 3 x to the fourth power2𝑥−2𝑥+𝑥2∶3𝑥2−3𝑥4=𝑥2∶3𝑥2−3𝑥4 Giả sử dấu ":" là phép chia, ta có: x2∶3x2=x23x2=13x squared colon 3 x squared equals the fraction with numerator x squared and denominator 3 x squared end-fraction equals one-third𝑥2∶3𝑥2=𝑥23𝑥2=13 Vậy biểu thức trở thành: 13−3x4one-third minus 3 x to the fourth power13−3𝑥4 Step 2: Phân tích thành nhân tử Biểu thức cần phân tích là 13−3x4one-third minus 3 x to the fourth power13−3𝑥4.
Ta có thể viết lại biểu thức như sau: 13−3x4=3(19−x4)one-third minus 3 x to the fourth power equals 3 open paren one-nineth minus x to the fourth power close paren13−3𝑥4=319−𝑥4 Sử dụng công thức hiệu hai bình phương a2−b2=(a−b)(a+b)a squared minus b squared equals open paren a minus b close paren open paren a plus b close paren𝑎2−𝑏2=(𝑎−𝑏)(𝑎+𝑏), với a=13a equals one-third𝑎=13và b=x2b equals x squared𝑏=𝑥2: 3(19−x4)=3((13)2−(x2)2)=3(13−x2)(13+x2)3 open paren one-nineth minus x to the fourth power close paren equals 3 open paren open paren one-third close paren squared minus open paren x squared close paren squared close paren equals 3 open paren one-third minus x squared close paren open paren one-third plus x squared close paren319−𝑥4=3132−(𝑥2)2=313−𝑥213+𝑥2 Tiếp tục phân tích hạng tử đầu tiên sử dụng công thức hiệu hai bình phương, với a=13a equals the fraction with numerator 1 and denominator the square root of 3 end-root end-fraction𝑎=13√và b=xb equals x𝑏=𝑥: 3(13−x2)(13+x2)=3((13)2−x2)(13+x2)3 open paren one-third minus x squared close paren open paren one-third plus x squared close paren equals 3 open paren open paren the fraction with numerator 1 and denominator the square root of 3 end-root end-fraction close paren squared minus x squared close paren open paren one-third plus x squared close paren313−𝑥213+𝑥2=3⎝⎜⎜⎛13√2−𝑥2⎠⎟⎟⎞13+𝑥2 =3(13−x)(13+x)(13+x2)equals 3 open paren the fraction with numerator 1 and denominator the square root of 3 end-root end-fraction minus x close paren open paren the fraction with numerator 1 and denominator the square root of 3 end-root end-fraction plus x close paren open paren one-third plus x squared close paren=313√−𝑥13√+𝑥13+𝑥2 Answer: Kết quả phân tích đa thức là 3(13−x)(13+x)(13+x2)3 open paren the fraction with numerator 1 and denominator the square root of 3 end-root end-fraction minus x close paren open paren the fraction with numerator 1 and denominator the square root of 3 end-root end-fraction plus x close paren open paren one-third plus x squared close paren3(13√−𝑥)(13√+𝑥)(13+𝑥2).
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AI responses may include mistakes. Answers may be inaccurate or misleading. Double-check for accuracy. Learn more Thank you Your feedback helps Google improve. See our Privacy Policy. Share more feedbackReport a problemClose Positive feedback Negative feedback Thank you Your feedback helps Google improve. See our Privacy Policy. Share more feedbackReport a problemClose Thank you Your feedback helps Google improve. See our Privacy Policy. Share more feedbackReport a problemCloseCâu 6:Thực hiện phép nhân -2x(x2 + 3x - 4) ta được:A.-2x3
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Vietnam Yên Bình, Tam Điệp, Ninh Bình - Based on your places (Home) HelpSend feedbackPrivacyTerms Google apps Search Labs Google Account liễu đặng danglieulk@gmail.com NegativeTa có thể rút gọn các hạng tử tương tự: 2x−2x+x2∶3x2−3x4=x2∶3x2−3x42 x minus 2 x plus x squared colon 3 x squared minus 3 x to the fourth power equals x squared colon 3 x squared minus 3 x to the fourth power2𝑥−2𝑥+𝑥2∶3𝑥2−3𝑥4=𝑥2∶3𝑥2−3𝑥4 Giả sử dấu ":" là phép chia, ta có: x2∶3x2=x23x2=13x squared colon 3 x squared equals the fraction with numerator x squared and denominator 3 x squared end-fraction equals one-third𝑥2∶3𝑥2=𝑥23𝑥2=13 Vậy biểu thức trở thành: 13−3x4one-third minus 3 x to the fourth power13−3𝑥4 Step 2: Phân tích thành nhân tử Biểu thức cần phân tích là 13−3x4one-third minus 3 x to the fourth power13−3𝑥4.
Ta có thể viết lại biểu thức như sau: 13−3x4=3(19−x4)one-third minus 3 x to the fourth power equals 3 open paren one-nineth minus x to the fourth power close paren13−3𝑥4=319−𝑥4 Sử dụng công thức hiệu hai bình phương a2−b2=(a−b)(a+b)a squared minus b squared equals open paren a minus b close paren open paren a plus b close paren𝑎2−𝑏2=(𝑎−𝑏)(𝑎+𝑏), với a=13a equals one-third𝑎=13và b=x2b equals x squared𝑏=𝑥2: 3(19−x4)=3((13)2−(x2)2)=3(13−x2)(13+x2)3 open paren one-nineth minus x to the fourth power close paren equals 3 open paren open paren one-third close paren squared minus open paren x squared close paren squared close paren equals 3 open paren one-third minus x squared close paren open paren one-third plus x squared close paren319−𝑥4=3132−(𝑥2)2=313−𝑥213+𝑥2 Tiếp tục phân tích hạng tử đầu tiên sử dụng công thức hiệu hai bình phương, với a=13a equals the fraction with numerator 1 and denominator the square root of 3 end-root end-fraction𝑎=13√và b=xb equals x𝑏=𝑥: 3(13−x2)(13+x2)=3((13)2−x2)(13+x2)3 open paren one-third minus x squared close paren open paren one-third plus x squared close paren equals 3 open paren open paren the fraction with numerator 1 and denominator the square root of 3 end-root end-fraction close paren squared minus x squared close paren open paren one-third plus x squared close paren313−𝑥213+𝑥2=3⎝⎜⎜⎛13√2−𝑥2⎠⎟⎟⎞13+𝑥2 =3(13−x)(13+x)(13+x2)equals 3 open paren the fraction with numerator 1 and denominator the square root of 3 end-root end-fraction minus x close paren open paren the fraction with numerator 1 and denominator the square root of 3 end-root end-fraction plus x close paren open paren one-third plus x squared close paren=313√−𝑥13√+𝑥13+𝑥2 Answer: Kết quả phân tích đa thức là 3(13−x)(13+x)(13+x2)3 open paren the fraction with numerator 1 and denominator the square root of 3 end-root end-fraction minus x close paren open paren the fraction with numerator 1 and denominator the square root of 3 end-root end-fraction plus x close paren open paren one-third plus x squared close paren3(13√−𝑥)(13√+𝑥)(13+𝑥2).
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AI responses may include mistakes. Answers may be inaccurate or misleading. Double-check for accuracy. Learn more Thank you Your feedback helps Google improve. See our Privacy Policy. Share more feedbackReport a problemClose Positive feedback Negative feedback Thank you Your feedback helps Google improve. See our Privacy Policy. Share more feedbackReport a problemClose Thank you Your feedback helps Google improve. See our Privacy Policy. Share more feedbackReport a problemCloseCâu 6:Thực hiện phép nhân -2x(x2 + 3x - 4) ta được:A.-2x3
OLM https://olm.vn › cau-hoi OLM https://olm.vn › cau-hoi · Translate this page Nov 23, 2021 — Bai 1: Tìm x ( Phân tích đa thức thành nhân tử)a, x.(8x-2)-8x2+12=0b,x.(4x-5)-(2x+1)2=0c,(5-2x).(2x+7)=(2x-5).(2x+5)d,64x2-49=0e,(x2+6x+9).(x2+ ...Read more bài 1:a) (2x3 - x2 + 5x) - OLM Aug 12, 2023 PHÂN TÍCH THÀNH NHÂN TỬA) X2-2X+3B) X2-3X+6C) X4+ ... Jan 2, 2017 More results from olm.vn
Phân tích đa thức thành nhân tử: a. 2x^2 - 3x - 2 b. 4x(x
khoahoc.vietjack.com https://khoahoc.vietjack.com › ph... khoahoc.vietjack.com https://khoahoc.vietjack.com › ph... · Translate this page Aug 19, 2025 — Phân tích đa thức thành nhân tử: a. 2x2 - 3x - 2 b. 4x(x - 2) + 3(2 - x) c. 27x3 + 8 d. x2 + 2x - y2 + 1. 4.6(1,375)
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8 cách phân tích đa thức thành nhân tử cực hay
Nghệ Ngữ https://nghengu.vn › toán Nghệ Ngữ https://nghengu.vn › toán · Translate this page Jan 22, 2026 — Phân tích đa thức thành nhân tử là nội dung vô cùng quan trọng trong chương trình môn Toán lớp 8 học kì 1. Đây là dạng bài thường gặp trong ...Read more
Phân Tích Nhân Tử 2x^3+3x^2-3x-2
Mathway https://www.mathway.com › Alge... Mathway https://www.mathway.com › Alge... · Translate this page Vì cả hai số hạng đều là các số lập phương, nên ta phân tích thành thừa số bằng công thức hiệu của hai lập phương, a3−b3=(a−b)(a2+ab+b2) a 3 - b 3 = ( a - b ) ...Read more
Phân tích đa thức thành nhân tử 3) 6a^2b-9ab^2+15a^3b^3 b) ...
Gauth https://www.gauthmath.com › B-i-... Gauth https://www.gauthmath.com › B-i-... · Translate this page 4. Phân tích các đa thức sau thành nhân tử: a 8x3-1 . b x3+27y3; c x3-y6. 5. Phân tích các đa thức sau thành nhân tử: a 4x3-16x; b x4-y4; c xy2+x2y+ 1/4 y3; d ...
Phân tích đa thức thành nhân tử
WordPress.com https://nguyenduyphuc.files.wordpress.com › ph... WordPress.com https://nguyenduyphuc.files.wordpress.com › ph... PDF Trong chuyên đề này ta sẽ hệ thống lại các dạng toán và các phương pháp phân tích đa thức thành nhân tử và giải một số bài tập về phân tích.Read more 7 pages
Phân tích đa thức thành nhân tử: 2x^2 + 3x - 2
Hoidap247.com https://hoidap247.com › cau-hoi Hoidap247.com https://hoidap247.com › cau-hoi · Translate this page Feb 4, 2024 — Đáp án: 2x²+ 3x - 2 = 2x²+4x- x -2 = (2x²+4x)+( -x -2) = 2x( x+2) - (x+2) = (2x-1)(x+2)
Phân tích đa thức thành nhân tử bằng phương pháp hệ số ...
Hoc24 https://hoc24.vn › tim-kiem › q=Ph... Hoc24 https://hoc24.vn › tim-kiem › q=Ph... · Translate this page Phân tích đa thức thành nhân tử bằng phương pháp hệ số bất định (đồng nhất hệ số) a) 3x4−5x3−18x2−3x 53x^4-5x^3-18x^2-3x 5 b) 2x4 3x3 2x2 3x−32x^4 3x^3 2x^2 ...
Bài tập phân tích đa thức thành phân tử
ThuVienDeThi.com https://thuviendethi.com › bai-tap-... ThuVienDeThi.com https://thuviendethi.com › bai-tap-... · Translate this page Bài tập phân tích đa thức thành nhân tử Bài 1: Phân tích các đa thức sau thành nhân tử: a) x2 - y2 - 2x + 2y b) 2x + 2y - x2 - xy c) 3a2 - 6ab + 3b2 - 12c2 ...
Toán 9 - Phân Tích Đa TH C | PDF
Scribd https://www.scribd.com › document Scribd https://www.scribd.com › document · Translate this page Tài liệu trình bày các phương pháp phân tích đa thức thành nhân tử, bao gồm phương pháp đặt nhân tử chung, sử dụng hằng đẳng thức, nhóm nhiều hạng tử và ...