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\(a\frac25+x=7--1,62=\frac25+x=8,62=x=8,62-\frac25=x=8,22,\) \(\frac{23}{5}-x=\) \(\frac{-1}{5}+\frac12=\frac{23}{5}-x=\frac{3}{10}=x=\frac{23}{5}-\frac{3}{10}=\frac{43}{10},\frac{-4}{7}-x=\frac35-2x=2x-x=\frac{-4}{7}-\frac35=x=\frac{41}{35}\) \(\frac57-\frac{1}{13}+0.25=\frac72-x=\frac{323}{364}=\frac72-x=\frac{1597}{364}\)
\(a\frac25+x=7--1,62=\frac25+x=8,62=x=8,62-\frac25=x=8,22,\) \(\frac{23}{5}-x=\) \(\frac{-1}{5}+\frac12=\frac{23}{5}-x=\frac{3}{10}=x=\frac{23}{5}-\frac{3}{10}=\frac{43}{10},\frac{-4}{7}-x=\frac35-2x=2x-x=\frac{-4}{7}-\frac35=x=\frac{41}{35}\) \(\frac57-\frac{1}{13}+0.25=\frac72-x=\frac{323}{364}=\frac72-x=\frac{1597}{364}\)
\(a\frac25+x=7--1,62=\frac25+x=8,62=x=8,62-\frac25=x=8,22,\) \(\frac{23}{5}-x=\) \(\frac{-1}{5}+\frac12=\frac{23}{5}-x=\frac{3}{10}=x=\frac{23}{5}-\frac{3}{10}=\frac{43}{10},\frac{-4}{7}-x=\frac35-2x=2x-x=\frac{-4}{7}-\frac35=x=\frac{41}{35}\) \(\frac57-\frac{1}{13}+0.25=\frac72-x=\frac{323}{364}=\frac72-x=\frac{1597}{364}\)
\(a\frac25+x=7--1,62=\frac25+x=8,62=x=8,62-\frac25=x=8,22,\) \(\frac{23}{5}-x=\) \(\frac{-1}{5}+\frac12=\frac{23}{5}-x=\frac{3}{10}=x=\frac{23}{5}-\frac{3}{10}=\frac{43}{10},\frac{-4}{7}-x=\frac35-2x=2x-x=\frac{-4}{7}-\frac35=x=\frac{41}{35}\) \(\frac57-\frac{1}{13}+0.25=\frac72-x=\frac{323}{364}=\frac72-x=\frac{1597}{364}\)
\(a\frac25+x=7--1,62=\frac25+x=8,62=x=8,62-\frac25=x=8,22,\) \(\frac{23}{5}-x=\) \(\frac{-1}{5}+\frac12=\frac{23}{5}-x=\frac{3}{10}=x=\frac{23}{5}-\frac{3}{10}=\frac{43}{10},\frac{-4}{7}-x=\frac35-2x=2x-x=\frac{-4}{7}-\frac35=x=\frac{41}{35}\) \(\frac57-\frac{1}{13}+0.25=\frac72-x=\frac{323}{364}=\frac72-x=\frac{1597}{364}\)
\(a\frac25+x=7--1,62=\frac25+x=8,62=x=8,62-\frac25=x=8,22,\) \(\frac{23}{5}-x=\) \(\frac{-1}{5}+\frac12=\frac{23}{5}-x=\frac{3}{10}=x=\frac{23}{5}-\frac{3}{10}=\frac{43}{10},\frac{-4}{7}-x=\frac35-2x=2x-x=\frac{-4}{7}-\frac35=x=\frac{41}{35}\) \(\frac57-\frac{1}{13}+0.25=\frac72-x=\frac{323}{364}=\frac72-x=\frac{1597}{364}\)
\(a\frac25+x=7--1,62=\frac25+x=8,62=x=8,62-\frac25=x=8,22,\) \(\frac{23}{5}-x=\) \(\frac{-1}{5}+\frac12=\frac{23}{5}-x=\frac{3}{10}=x=\frac{23}{5}-\frac{3}{10}=\frac{43}{10},\frac{-4}{7}-x=\frac35-2x=2x-x=\frac{-4}{7}-\frac35=x=\frac{41}{35}\) \(\frac57-\frac{1}{13}+0.25=\frac72-x=\frac{323}{364}=\frac72-x=\frac{1597}{364}\)
\(a\frac25+x=7--1,62=\frac25+x=8,62=x=8,62-\frac25=x=8,22,\) \(\frac{23}{5}-x=\) \(\frac{-1}{5}+\frac12=\frac{23}{5}-x=\frac{3}{10}=x=\frac{23}{5}-\frac{3}{10}=\frac{43}{10},\frac{-4}{7}-x=\frac35-2x=2x-x=\frac{-4}{7}-\frac35=x=\frac{41}{35}\) \(\frac57-\frac{1}{13}+0.25=\frac72-x=\frac{323}{364}=\frac72-x=\frac{1597}{364}\)
\(a\frac25+x=7--1,62=\frac25+x=8,62=x=8,62-\frac25=x=8,22,\) \(\frac{23}{5}-x=\) \(\frac{-1}{5}+\frac12=\frac{23}{5}-x=\frac{3}{10}=x=\frac{23}{5}-\frac{3}{10}=\frac{43}{10},\frac{-4}{7}-x=\frac35-2x=2x-x=\frac{-4}{7}-\frac35=x=\frac{41}{35}\) \(\frac57-\frac{1}{13}+0.25=\frac72-x=\frac{323}{364}=\frac72-x=\frac{1597}{364}\)
\(a\frac25+x=7--1,62=\frac25+x=8,62=x=8,62-\frac25=x=8,22,\) \(\frac{23}{5}-x=\) \(\frac{-1}{5}+\frac12=\frac{23}{5}-x=\frac{3}{10}=x=\frac{23}{5}-\frac{3}{10}=\frac{43}{10},\frac{-4}{7}-x=\frac35-2x=2x-x=\frac{-4}{7}-\frac35=x=\frac{41}{35}\) \(\frac57-\frac{1}{13}+0.25=\frac72-x=\frac{323}{364}=\frac72-x=\frac{1597}{364}\)