Đào Mạnh Hưng

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ta có: \(\mid 5 x - 1 \mid =\) \(2 x - 4\)
\(\Rightarrow \left[\right. 5 x - 1 = 2 x - 4 \\ 5 x - 1 = - 2 x - 4\)
\(\Rightarrow \left[\right. 5 x - 2 x = 1 - 4 \\ 5 x + 2 x = 1 - 4\)
\(\Rightarrow \left[\right. 3 x = - 3 \\ 7 x = - 3\)
\(\Rightarrow \left[\right. x = \left(\right. - 3 \left.\right) : 3 \\ x = \left(\right. - 3 \left.\right) : 7\)
\(\Rightarrow \left[\right. x = - 1 \\ x = - \frac{3}{7}\)

nhớ tick cho mk nhé

Bước |5x−1|=2x−4the absolute value of 5 x minus 1 end-absolute-value equals 2 x minus 4|5𝑥−1|=2𝑥−4 |5x−1|=2x−4the absolute value of 5 x minus 1 end-absolute-value equals modified 2 x with boxed outline minus 4|5𝑥−1|=2𝑥−4 Chuyển biến sang vế trái và đổi dấu của nó |5x−1|-2x=-4the absolute value of 5 x minus 1 end-absolute-value modified negative 2 x with boxed outline equals negative 4|5𝑥−1|−2𝑥=−4 Bước |5x−1|−2x=-4the absolute value of 5 x minus 1 end-absolute-value minus 2 x equals negative 4|5𝑥−1|−2𝑥=−4 |5x−1|−2x=-4modified the absolute value of 5 x minus 1 end-absolute-value minus 2 x equals negative 4 with boxed outline|5𝑥−1|−2𝑥=−4 Tách phương trình ra làm 222trường hợp Bước 5x−1−2x=-4,5x−1≥0−(5x−1)−2x=-4,5x−1<02 lines; Line 1: 5 x minus 1 minus 2 x equals negative 4 comma 5 x minus 1 is greater than or equal to 0; Line 2: negative open paren 5 x minus 1 close paren minus 2 x equals negative 4 comma 5 x minus 1 is less than 0 end-lines;5𝑥−1−2𝑥=−4,5𝑥−1≥0−(5𝑥−1)−2𝑥=−4,5𝑥−1<0 5x−1−2x=-4,5x−1≥0−(5x−1)−2x=-4,5x−1<02 lines; Line 1: modified 5 x minus 1 minus 2 x equals negative 4 with boxed outline comma 5 x minus 1 is greater than or equal to 0; Line 2: negative open paren 5 x minus 1 close paren minus 2 x equals negative 4 comma 5 x minus 1 is less than 0 end-lines;5𝑥−1−2𝑥=−4,5𝑥−1≥0−(5𝑥−1)−2𝑥=−4,5𝑥−1<0 Giải phương trình xx𝑥 x=-1,5x−1≥0−(5x−1)−2x=-4,5x−1<02 lines; Line 1: modified x equals negative 1 with boxed outline comma 5 x minus 1 is greater than or equal to 0; Line 2: negative open paren 5 x minus 1 close paren minus 2 x equals negative 4 comma 5 x minus 1 is less than 0 end-lines;𝑥=−1,5𝑥−1≥0−(5𝑥−1)−2𝑥=−4,5𝑥−1<0 Bước x=-1,5x−1≥0−(5x−1)−2x=-4,5x−1<02 lines; Line 1: x equals negative 1 comma 5 x minus 1 is greater than or equal to 0; Line 2: negative open paren 5 x minus 1 close paren minus 2 x equals negative 4 comma 5 x minus 1 is less than 0 end-lines;𝑥=−1,5𝑥−1≥0−(5𝑥−1)−2𝑥=−4,5𝑥−1<0 x=-1,5x−1≥0−(5x−1)−2x=-4,5x−1<02 lines; Line 1: x equals negative 1 comma modified 5 x minus 1 is greater than or equal to 0 with boxed outline; Line 2: negative open paren 5 x minus 1 close paren minus 2 x equals negative 4 comma 5 x minus 1 is less than 0 end-lines;𝑥=−1,5𝑥−1≥0−(5𝑥−1)−2𝑥=−4,5𝑥−1<0 Giải bất phương trình tìm xx𝑥 x=-1,x≥15−(5x−1)−2x=-4,5x−1<02 lines; Line 1: x equals negative 1 comma modified x is greater than or equal to one-fifth with boxed outline; Line 2: negative open paren 5 x minus 1 close paren minus 2 x equals negative 4 comma 5 x minus 1 is less than 0 end-lines;𝑥=−1,𝑥≥15−(5𝑥−1)−2𝑥=−4,5𝑥−1<0 Bước x=-1,x≥15−(5x−1)−2x=-4,5x−1<02 lines; Line 1: x equals negative 1 comma x is greater than or equal to one-fifth; Line 2: negative open paren 5 x minus 1 close paren minus 2 x equals negative 4 comma 5 x minus 1 is less than 0 end-lines;𝑥=−1,𝑥≥15−(5𝑥−1)−2𝑥=−4,5𝑥−1<0 x=-1,x≥15−(5x−1)−2x=-4,5x−1<02 lines; Line 1: x equals negative 1 comma x is greater than or equal to one-fifth; Line 2: modified negative open paren 5 x minus 1 close paren minus 2 x equals negative 4 with boxed outline comma 5 x minus 1 is less than 0 end-lines;𝑥=−1,𝑥≥15−(5𝑥−1)−2𝑥=−4,5𝑥−1<0 Giải phương trình xx𝑥 x=-1,x≥15x=57,5x−1<02 lines; Line 1: x equals negative 1 comma x is greater than or equal to one-fifth; Line 2: modified x equals five-sevenths with boxed outline comma 5 x minus 1 is less than 0 end-lines;𝑥=−1,𝑥≥15𝑥=57,5𝑥−1<0 Bước x=-1,x≥15x=57,5x−1<02 lines; Line 1: x equals negative 1 comma x is greater than or equal to one-fifth; Line 2: x equals five-sevenths comma 5 x minus 1 is less than 0 end-lines;𝑥=−1,𝑥≥15𝑥=57,5𝑥−1<0 x=-1,x≥15x=57,5x−1<02 lines; Line 1: x equals negative 1 comma x is greater than or equal to one-fifth; Line 2: x equals five-sevenths comma modified 5 x minus 1 is less than 0 with boxed outline end-lines;𝑥=−1,𝑥≥15𝑥=57,5𝑥−1<0 Giải bất phương trình tìm xx𝑥 x=-1,x≥15x=57,x<152 lines; Line 1: x equals negative 1 comma x is greater than or equal to one-fifth; Line 2: x equals five-sevenths comma modified x is less than one-fifth with boxed outline end-lines;𝑥=−1,𝑥≥15𝑥=57,𝑥<15 Bước x=-1,x≥15x=57,x<152 lines; Line 1: x equals negative 1 comma x is greater than or equal to one-fifth; Line 2: x equals five-sevenths comma x is less than one-fifth end-lines;𝑥=−1,𝑥≥15𝑥=57,𝑥<15 x=-1,x≥15x=57,x<152 lines; Line 1: modified x equals negative 1 comma x is greater than or equal to one-fifth with boxed outline; Line 2: x equals five-sevenths comma x is less than one-fifth end-lines;𝑥=−1,𝑥≥15𝑥=57,𝑥<15 Tìm phần giao ∅x=57,x<152 lines; Line 1: modified the empty set with boxed outline; Line 2: x equals five-sevenths comma x is less than one-fifth end-lines;∅𝑥=57,𝑥<15 Bước ∅x=57,x<152 lines; Line 1: the empty set; Line 2: x equals five-sevenths comma x is less than one-fifth end-lines;∅𝑥=57,𝑥<15 ∅x=57,x<152 lines; Line 1: the empty set; Line 2: modified x equals five-sevenths comma x is less than one-fifth with boxed outline end-lines;∅𝑥=57,𝑥<15 Tìm phần giao ∅∅2 lines; Line 1: the empty set; Line 2: modified the empty set with boxed outline end-lines;∅∅ Bước