X=2^30+3^30+4^30
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Ta có:\(2^{30}=\left(2^3\right)^{10}=8^{10}< 9^{10}=\left(3^2\right)^{10}=3^{20}\)
\(3^{30}=3^{20}.3^{10}< 3^{20}.4^{10}=3^{20}.\left(2^2\right)^{10}=3^{20}.2^{20}=\left(3.2\right)^{20}=6^{20}\)
\(4^{30}=4^{20}.4^{10}=4^{20}.\left(2^2\right)^{10}=4^{20}.2^{20}=\left(4.2\right)^{20}=8^{20}\)
nên \(2^{30}+3^{30}+4^{30}< 3^{20}+6^{20}+8^{20}\)
a) 86 – 16 = 70 
b) 23 x 2 – 1 = 23 
c) 250 : 5 + 5 = 25 
d) 40 + 80 : 4 = 30 
e) 80 + 4 : 2 = 42 
f) 70 + 30 : 2 = 50 
g) 90 + 30 x 3 = 180 
h) 70 + 30 : 2 = 85 
Bài 3:
a: \(S=1+5^2+5^4+\cdots+5^{200}\)
=>25S=\(5^2+5^4+5^6+\cdots+5^{202}\)
=>25S-S=\(5^2+5^4+\cdots+5^{202}-1-5^2-\cdots-5^{200}\)
=>24S=\(5^{202}-1\)
=>\(S=\frac{5^{202}-1}{24}\)
b: \(4^{30}=\left(2^2\right)^{30}=2^{60}=2^{30}\cdot2^{30}=8^{10}\cdot4^{15}\)
\(3\cdot24^{10}=3\cdot3^{10}\cdot8^{10}=8^{10}\cdot3^{11}\)
mà \(4^{15}>3^{11}\)
nên \(4^{30}>3\cdot24^{10}\)
=>\(2^{30}+3^{30}+4^{30}>3\cdot24^{10}\)
Bài 2:
a: |2x-3|>5
=>\(\left[\begin{array}{l}2x-3>5\\ 2x-3<-5\end{array}\right.\Rightarrow\left[\begin{array}{l}2x>8\\ 2x<-2\end{array}\right.\Rightarrow\left[\begin{array}{l}x>4\\ x<-1\end{array}\right.\)
c: |3x-1|<=7
=>-7<=3x-1<=7
=>-6<=3x<=8
=>\(-2\le x\le\frac83\)
d: \(\left|3x-5\right|+\left|2x+3\right|=7\) (1)
TH1: \(x<-\frac32\)
=>2x+3<0; 3x-5<0
(1) sẽ trở thành: -2x-3-3x+5=7
=>-5x+2=7
=>-5x=5
=>x=-1(loại)
TH2: -3/2<=x<5/3
=>2x+3>=0; 3x-5<0
(1) sẽ trở thành: 2x+3-3x+5=7
=>-x+8=7
=>-x=-1
=>x=-1(nhận)
TH3: x>=5/3
=>2x+3>0; 3x-5>=0
(1) sẽ trở thành: 2x+3+3x-5=7
=>5x-2=7
=>5x=9
=>x=9/5(nhận)
5 x 6 = 30 2 x 6 = 12 3 x 6 = 18 4 x 6 = 24
6 x 5 = 30 6 x 2 = 12 6 x 3 = 18 6 x 4 = 24
a) 2x-30=-14
2x=(-14)+30
2x=16
x=16:2
x=8
b) 230-4*(x+5)=30
4*(x+5)=230-30
4*(x+5)=200
x+5=200:4
x+5= 50
x=50-5
x=45
\(2^{30}< 24^{30}\)
\(3^{30}< 24^{30}\)
\(4^{30}< 24^{30}\)
\(\Rightarrow2^{30}+3^{30}+4^{30}< 24^{30}+24^{30}+24^{30}\)
\(\Rightarrow2^{30}+3^{30}+4^{30}< 3.24^{30}\)
a) 87 + 92 – 32 = 179 – 32
= 147
b) 138 – 30 – 8 = 108 - 8
= 100
c) 30 x 2 : 3 = 60 : 3
= 20
d) 80 : 2 x 4 = 40 x 4
= 160







