1 I had the gate painted by my nephew last week

2 She will have her car washed by Peter tomorrow

3 They have the story told by her again

4 John gets his shirt cleaned by his sister

5 Anne had had her compossition typed by a friend

6 Rick will have his hair cut by a barber

7 I will get a new dress made by the dressmaker

8 He had his car repaired by a mechanic

9 She often get the heater maintained by the technician

10 They had the shiplifter arrested by the police

11 Are you going to have your shoes repaired by the showmaker

12 I must have my teeth checked by the dentist

13 She will have her dog examined by a veterinary 

14 We had this phootograph taken by a man when.....

15 The greens had their carpet cleaned by a carpet cleaner

pascal hả

ờ ờ tớ không biết nhé 

từ :))

Học gì mà đề như thế này

MK..........................................................................................ngu hóa

bắt tay nào =.= 

từ đợi làm tí

alo

a: Ta có: \(25x^2\left(x-y\right)-x+y\)

\(=\left(x-y\right)\left(25x^2-1\right)\)

\(=\left(x-y\right)\left(5x-1\right)\left(5x+1\right)\)

b: Ta có: \(16x^2\left(z^2-y^2\right)-z^2+y^2\)

\(=\left(z^2-y^2\right)\left(16x^2-1\right)\)

\(=\left(z-y\right)\left(z+y\right)\left(4x-1\right)\left(4x+1\right)\)

c: Ta có: \(x^3+x^2y-x^2z-xyz\)

\(=x^2\left(x+y\right)-xz\left(x+y\right)\)

\(=x\left(x+y\right)\left(x-z\right)\)

đề bài là j

Ta có: 4x²+x=0

    ⇔ x(4x+1)=0

   \(\Leftrightarrow\left\{{}\begin{matrix}x=0\\4x+1=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0\\x=-\dfrac{1}{4}\end{matrix}\right.\)

tinh thần đoàn kết giúp cta chiến thắng giặc ngoại xâm

Vd hiện tại:giúp bạn chép bài khi bị ốm,giúp đỡ bạn học yếu hơn mik....

mong là đúng

a, \(\left\{{}\begin{matrix}35x-28y=21\\35x-45y=40\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}17y=-19\\x=\dfrac{3+4y}{5}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=-\dfrac{19}{17}\\x=-\dfrac{13}{17}\end{matrix}\right.\)

b, Đặt x;y khác 0 

Đặt 1/x = t ; 1/y = u 

\(\left\{{}\begin{matrix}t-8u=18\\5t+4u=51\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}5t-40u=90\\5t+4u=51\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}-44u=39\\t=18+8u\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}u=-\dfrac{39}{44}\\t=\dfrac{120}{11}\end{matrix}\right.\)

Theo cách đặt y = -44/39 ; x = 11/120 (tm)

\(a,\\ \Leftrightarrow\left\{{}\begin{matrix}35x-28y=21_{\left(1\right)}\\35x-45y=40_{\left(2\right)}\end{matrix}\right.\\ Lấy\left(1\right)-\left(2\right),ta.đc:\\ -17y=19\Leftrightarrow y=\dfrac{-19}{17}\\ Thay.vào.\left(1\right):\\ 35x-28.\dfrac{-19}{17}=21\Leftrightarrow x=\dfrac{-5}{17}\) 

Vậy ......

\(b,\\ \Leftrightarrow\left\{{}\begin{matrix}\dfrac{1}{x}=18+\dfrac{1}{y}\\5.\left(18+\dfrac{1}{y}\right)+\dfrac{4}{y}=51\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}\dfrac{1}{x}=18+\dfrac{1}{y}\\\dfrac{9}{y}=-39\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{1}{x}=18-\dfrac{13}{3}\\\dfrac{1}{y}=\dfrac{-13}{3}\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}\dfrac{1}{x}=\dfrac{41}{3}\\\dfrac{1}{y}=\dfrac{-13}{3}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{3}{41}\\y=\dfrac{-3}{13}\end{matrix}\right.\)