Câu 1)

1/5*x=4/6

x=4/6/1/5

x=10/3

Câu 3)x/6*5/8=5/12

x/6=5/12/5/8

x/6=2/3

x/6=4/6

Vây x=4

Câu 3)

5/9/3/x=5/27

3/x=5/9/5/27

3/x=3

Vây x=1

câu 1 10/3

câu 2 4/6

câu 3 3/1

minh lm duoc k cho minh nha

cau 1

=1/2.3+1/3.4+1/4.5+1/5.61/6.7+1/7.8+1/8.9

=1/1-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9

=1/1-1/9

=8/9

vi 8/9>1/2

nen 1/2.3+1/3.4+1/4.5+.....+1/8.9>1/2

Bài 1: đặt 5 câu với "has been to"

1. She has been to Paris twice.

2. They have been to the beach for vacation.

3. He has been to Japan for a business trip.

4. We have been to that restaurant before.

5. The team has been to the championship finals multiple times.

Bài 2: đặt 5 câu với "have gone to"

1. They have gone to the movies to watch the latest blockbuster.

2. We have gone to the park to have a picnic.

3. She has gone to the gym to work out.

4. He has gone to the store to buy groceries.

5. They have gone to the concert to see their favorite band perform.

 Bài 1: Sử dụng "Has Been to"

1. She has been to Paris three times in the last year.
2. My brother has been to the new museum downtown.
3. The cat has been to the vet for its annual check-up.
4. He has been to every continent except Antarctica.
5. Our teacher has been to many international conferences.
 Bài 2: Sử dụng "Have Gone to"
1. They have gone to the beach for the weekend.
2. My parents have gone to the market; they'll be back soon.
3. We have gone to see the latest movie at the cinema.
4. The students have gone to the library to study for their exams.
5. My friends have gone to a concert in the city center.

Thắng được 25 điểm nên chắc chắn đúng 5 câu.

10 câu còn lại được 0 điểm nên có 5 câu đúng và 5 câu sai.

Vậy có 10 câu đúng, 5 câu sai

có 10 câu đúng, 5 câu sai

ủa bạn trả lời làm màu à

bài 5 ở cuối cùng í ( bài 5 \(\ne\) câu 5 nha !)

Chọn đáp án: B. Các câu 1 – 2 – 4 – 6 – 8

Chọn C

6)  \(\dfrac{8^6}{256}=\dfrac{\left(2^3\right)^6}{2^8}=\dfrac{2^{18}}{2^8}=2^{10}=1024\)

7) \(\left(\dfrac{1}{2}\right)^{15}.\left(\dfrac{1}{4}\right)^{20}=\left(\dfrac{1}{2}\right)^{15}.\left[\left(\dfrac{1}{2}\right)^2\right]^{20}=\left(\dfrac{1}{2}\right)^{15}.\left(\dfrac{1}{2}\right)^{40}=\left(\dfrac{1}{2}\right)^{55}=\dfrac{1}{2^{55}}\)

8)  \(\left(\dfrac{1}{9}\right)^{25}\div\left(\dfrac{1}{3}\right)^{30}=\left(\dfrac{1}{3}\right)^{50}\div\left(\dfrac{1}{3}\right)^{30}=\left(\dfrac{1}{3}\right)^{20}=\dfrac{1}{3^{20}}\)

9)\(\left(\dfrac{1}{16}\right)^3\div\left(\dfrac{1}{8}\right)^2=\left(\dfrac{1}{2}\right)^{12}\div\left(\dfrac{1}{2}\right)^6=\left(\dfrac{1}{2}\right)^6=\dfrac{1}{64}\)

10)  \(\dfrac{27^2.8^5}{6^2.32^3}=\dfrac{3^6.2^{15}}{3^2.2^2.2^{15}}=\dfrac{3^4}{2^2}=\dfrac{81}{4}\)

câu1

(x-3)(y-5)=7=1.7=7.1=-7.(-1)=(-1)(-7)

nếu x-3=1;y-5=7 thì x=1+3=4;y=12

nếu x-3=7;y-5=1 thì x=10;y=6

nếu....

vậy...

câu 2

(x-1)(xy-5)=5 

=>x-1;xy-5 \(\in\) Ư(5) mà (x-1)(xy-5)=5.1=1.5=-5.(-1)=(-1)(-5)

ta có bảng sau

vậy...

làm giúp e ạ