Tính biểu thức sau: (4^9x36+64^4):(100x16^4)
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\(A=\left(4^9\cdot36+64^4\right)\div\left(16^4\cdot100\right)\)
\(A=\left[4^9\cdot4\cdot9+\left(4^3\right)^4\right]\div\left[\left(4^2\right)^4\cdot25\cdot4\right]\)
\(A=\left(4^{10}\cdot9+4^{4\cdot3}\right)\div\left[4^{2\cdot4}\cdot25\cdot4\right]\)
\(A=\left(4^{10}\cdot9+4^{12}\right)\div\left(4^8\cdot25\cdot4\right)\)
\(A=\left(4^{10}\cdot9+4^{10}\cdot4^2\right)\div\left(4^8\cdot25\cdot4\right)\)
\(A=\left(4^{10}\cdot9+4^{10}\cdot16\right)\div\left(4^8\cdot25\cdot4\right)\)
\(A=4^{10}\cdot\left(9+16\right)\div\left(4^8\cdot25\cdot4\right)\)
\(A=4^{10}\cdot25\div\left(4^8\cdot25\cdot4\right)\)
\(A=\frac{4^{10}\cdot25}{4^8\cdot25\cdot4}\)
\(A=\frac{4^2\cdot1}{1\cdot1\cdot4}\)
\(A=4\)
\(B=72^3\cdot54^2\div108^4\)
Ta lần lượt phần tích \(72,54,108\) ra thừa số nguyên tố.
\(72=2^3\cdot3^2\).
\(54=2\cdot3^3\)
\(108=2^2\cdot3^3\)
\(\Rightarrow B=\left(2^3\cdot3^2\right)^3\cdot\left(2\cdot3^3\right)^2\div\left(2^2\cdot3^3\right)^4\)
\(B=\left(2^3\right)^3\cdot\left(3^2\right)^3\cdot2^2\cdot\left(3^3\right)^3\div\left[\left(2^2\right)^4\cdot\left(3^3\right)^4\right]\)
\(B=2^{3\cdot3}\cdot3^{2\cdot3}\cdot2^2\cdot3^{3\cdot2}\div\left(2^{2\cdot4}\cdot3^{3\cdot4}\right)\)
\(B=2^9\cdot3^6\cdot2^2\cdot3^6\div\left(2^8\cdot3^{12}\right)\)
\(B=\left(2^9\cdot2^2\div2^8\right)\cdot\left(3^6\cdot3^6\div3^{12}\right)\)
\(B=2^{9+2-8}\cdot3^{6+6-12}\)
\(B=2^3\cdot1\)
\(B=8\)
a. 64 x 4 + 18 x 4 + 9 x 8
= 64 x 4 + 18 x 4 + 9 x 2 x 4
= 64 x 4 + 18 x 4 + 18 x 4
= 4 x (64 + 18 + 18)
= 4 x 100
= 400
\(\sqrt{64}-\sqrt{169}+\sqrt{9}=8-13+3=-2\)
\(4\sqrt{3}+\sqrt{27}-\sqrt{75}=4\sqrt{3}+3-5\sqrt{3}=\sqrt{3}\left(4+3-5\right)=2\sqrt{3}\)
ta có : \(\frac{4^{17}+64}{4^{16}+16}=\frac{2^{34}+2^6}{2^{32}+2^4}=\frac{2^6\left(2^{28}+1\right)}{2^4\left(2^{28}+1\right)}=2^2=4\)
Ta có: \(\frac{4^{17}+64}{4^{16}+16}\) = \(\frac{2^{34}+2^6}{2^{32}+2^4}\) = \(\frac{2^6\left(2^{28}+1\right)}{2^4\left(2^{28}+1\right)}\) = \(\frac{2^6}{2^4}\) = \(\frac{64}{16}\) = 4
( 417 + 64 ) : ( 416 + 16 )
= ( 417 + 43 ) : (416 + 42)
= 420 : 418
= 42
đổi 42 = 16
Đáp số :.........
\(1-\frac{1}{2}-\frac{1}{4}-\frac{1}{8}-\frac{1}{16}-\frac{1}{32}\)\(-\frac{1}{64}\)
\(=1-\frac{32}{64}-\frac{16}{64}-\frac{8}{64}-\frac{4}{64}\)\(-\frac{2}{64}-\frac{1}{64}\)
\(=1-\left(\frac{32}{64}-\frac{16}{64}-\frac{8}{64}-\frac{4}{64}-\frac{2}{64}-\frac{1}{64}\right)\)
\(=1-\frac{1}{64}\)
\(=\frac{64}{64}-\frac{1}{64}\)
\(=\frac{63}{64}\)
40 nhé
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