2/x+1 - 3/x+2 = 1/3x+3
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15 tháng 4 2020
R(x) = 2x2 + 3x - 1
- M(x) = -x3 + x2
x3 + x2 + 3x - 1
Vậy R(x) - M(x) = x3 + x2 + 3x - 1
NL
Nguyễn Lê Phước Thịnh
CTVHS
11 tháng 3 2023
a: =>9x^2+12x+4-9x^2+12x-4=5x+38
=>24x=5x+38
=>19x=38
=>x=2
e: =>x^3+1-2x=x^3-x
=>-2x+1=-x
=>-x=-1
=>x=1
f: =>x^3-6x^2+12x-8+9x^2-1=x^3+3x^2+3x+1
=>12x-9=3x+1
=>9x=10
=>x=10/9
b: \(\Leftrightarrow3x^2-12x+12+9x-9=3x^2+3x-9\)
=>-3x+3=3x-9
=>-6x=-12
=>x=2
NL
Nguyễn Lê Phước Thịnh
CTVHS
16 tháng 6 2023
1: \(=6x^2+2x-15x-5-x^2+6x-9+4x^2+20x+25-27x^3-27x^2-9x-1\)
=-27x^3-18x^2+4x+10
2: =4x^2-1-6x^2-9x+4x+6-x^3+3x^2-3x+1+8x^3+36x^2+54x+27
=7x^3+37x^2+46x+33
5:
\(=25x^2-1-x^3-27-4x^2-16x-16-9x^2+24x-16+\left(2x-5\right)^3\)
\(=8x^3-60x^2+150-125+12x^2-x^3+8x-60\)
=7x^3-48x^2+8x-35
26 tháng 3 2020
a) (3x + 1)^2 - 2(3x + 1)(3x - 5) + (3x - 5)^2
= 9x^2 + 6x + 1 - 18x^2 + 24x + 10 + 9x^2 - 30x + 25
= 36
b) (3x^2 - y)^2
= 9x^4 - 6x^2y + y^2
c) (3x + 5)^2 + (3x - 5)^2 - (3x + 2)(3x - 2)
= 9x^2 + 30x + 25 + 9x^2 - 30x + 25 - 9x^2 + 4
= 9x^2 + 54
d) 2x(2x - 1)^2 - 3x(x + 3)(x - 3) - 4x(x + 1)^2
= 8x^3 - 8x^2 + 2x - 3x^2 + 27x - 4x^3 - 8x^2 - 4x
= x^3 - 16x^2 + 25x
e) (x - 2)(x^2 + 2x + 4) - (x + 1)^2 + 3(x - 1)(x + 1)
= x^3 - 8 - x^2 - 2x - 1 + 3x^2 - 2
= x^3 + 2x^2 - 2x - 12
f) (x^4 - 5x^2 + 25)(x^2 + 5) - (2 + x^2)^2 + 3(1 + x^2)^2
= x^6 + 125 - 4 - 4x^2 - x^2 + 3 + 6x^2 + 3x^4
= x^6 + 2x^4 + 2x^2 + 124
10 tháng 11 2021
\(A=2x^3+3x^2-3-5x^2-5x=2x^3-2x^2-5x-3\\ B=125-150x+60x^2-8x^3-25+9x^2=-8x^3+69x^2-150x+100\\ C=\left(3x+1-2x+1\right)\left(3x+1+2x-1\right)=5x\left(x+2\right)=5x^2+10x\\ D=\left(2x+1-3+x\right)^2=\left(3x-2\right)^2=9x^2-12x+4\\ E=x^3-6x^2+12x-8-x^3+x+6x^2-18x=-5x-8\\ F=x^3-3x^2+3x-1-3+3x^2-x^3+1-3x=-3\)
ĐK: \(x \neq - 1 , \textrm{ }\textrm{ } x \neq - 2\)
\(\frac{2}{x + 1} - \frac{3}{x + 2} = \frac{1}{3 x + 3}\) \(\Leftrightarrow \frac{2}{x + 1} - \frac{3}{x + 2} = \frac{1}{3 \left(\right. x + 1 \left.\right)}\)
\(\Leftrightarrow 6 \left(\right. x + 2 \left.\right) - 9 \left(\right. x + 1 \left.\right) = x + 2\)
\(\Leftrightarrow 6 x + 12 - 9 x - 9 = x + 2\)
\(\Leftrightarrow - 3 x + 3 = x + 2\)
\(\Leftrightarrow - 4 x = - 1\)
\(\Leftrightarrow x = \frac{1}{4}\)
Vậy \(x = \frac{1}{4}\).
ĐKXĐ: x+1≠0
=> x≠-1
x+2≠0
=> x≠-2
\(\frac{2}{x+1}-\frac{3}{2+2}=\frac{1}{3x+3}\)
\(\frac{6\left(x+2\right)}{3\left(x+1\right)\left(x+2\right)}-\frac{9\left(x+1\right)}{3\left(x+1\right)\left(x+2\right)}=\frac{\left(x+2\right)}{3\left(x+1\right)\left(x+2\right)}\)
\(6\left(x+2\right)-9\left(x+1\right)=x+2\)
\(6x+12-9x-9=x+2\)
\(-3x+3=x+2\)
\(-3x-x=-3+2\)
\(-4x=-1\)
\(x=\frac14\)
vậy x=\(\frac14\)