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a: \(\left(2345+45\right)-2345\)
\(=2345+45-2345\)
\(=45+\left(2345-2345\right)\)
=45+0
=45
b: \(\left(-2010\right)-\left(119-2010\right)\)
\(=-2010-119+2010\)
\(=\left(-2010+2010\right)-119\)
=0-119
=-119
c: \(\left(18+29\right)+\left(158-18-29\right)\)
\(=18+29+158-18-29\)
\(=158+\left(18-18\right)+\left(29-29\right)\)
=158+0+0
=158
d: \(126+\left(-20\right)+2004+\left(-106\right)\)
\(=126-20+2004-106\)
\(=\left(126-20-106\right)+2004\)
=0+2004
=2004
e: \(\left(-199\right)+\left(-200\right)+\left(201\right)\)
\(=-199-200+201\)
\(=-199+\left(201-200\right)\)
=-199+1
=-198
f: \(99+\left(-100\right)+101\)
\(=\left(99+101\right)-100\)
=200-100
=100
g: \(217+\left[43+\left(-217\right)+\left(-23\right)\right]\)
\(=217+43-217-23\)
\(=\left(217-217\right)+\left(43-23\right)\)
=0+20
=20
a) (2345-45)+2345
= 2300 + 2345
= 4645
b) (-2010)-(119-2010)
= -2010-119+2010
= (2010-2010)-199
= -199
c) (18+29)+(158-18-29)
= 18+29+158-18-29
= (18-18)+(29-29)+158
= 158
d) 126+(-20)+2004+(-106)
= 126 -20 + 2004 - 106
= (126-20-106) +2004
= 2004
e) (-199)+(-200)+(-201)
= -(199+200+201)
= -600
g) 217+ [43+(-217)+(-23)]
= 217+ 43 - 217 + 23
= (217-217)+(43-23)
= 20
-Học tốt-
1: \(78+22+18\)
\(=\left(78+22\right)+18\)
=100+18
=118
2: \(94+563+\left(106-563\right)-\left(-70\right)\)
\(=94+563+106-563+70\)
\(=\left(94+106\right)-\left(563-563\right)+70\)
=100-0+70
=170
3: \(25\cdot154-25+47\cdot25\)
\(=25\left(154-1+47\right)\)
\(=25\cdot200=5000\)
4: \(\left[5^{29}+5^{30}\left(16-11\right)\right]:5^{29}\)
\(=\left(5^{29}+5^{30}\cdot5\right):5^{29}\)
\(=\dfrac{5^{29}\cdot1+5^{29}\cdot5^2}{5^{29}}\)
\(=1+5^2=26\)
8: \(25\cdot2^3-\left(9-14\right)+\left(29-34+20\right)\)
\(=25\cdot8-\left(-5\right)+\left(-5\right)+20\)
\(=200+5-5+20\)
=220
zời ơi bỏ chữ thể hiện đi còn ghi vào nữa
= -29
bn nhóm lại từng nhóm
\(A=\frac{5.\left(2^2.3^2\right)^9.\left(2^2\right)^6-2.\left(2^2.3\right)^{14}.3^4}{5.2^{28}.3^{18}-7.2^{29}.3^{18}}\)
\(=\frac{5.2^{18}.3^{18}.2^{12}-2.2^{28}.3^{14}.3^4}{2^{28}.3^{18}.\left(5-7.2\right)}\)\(=\frac{5.2^{30}.3^{18}-2^{29}.3^{18}}{2^{28}.3^{18}.\left(5-14\right)}\)
\(=\frac{2^{29}.3^{18}.\left(5.2-1\right)}{2^{28}.3^{18}.\left(-9\right)}=\frac{2.9}{-9}=-2\)
Vậy A=-2
123+456=
18 + 4924 + 3833 + 29
= 4942 + 3833 + 29
= 8775 + 29
= 8804