x:2+5=45:9
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a) (-37 - 17) . (-9) + 35 . (-9 - 11)
=-54*(-9)+35*(-20)
=486+(-700)
=-214
b) (-25) . (75 - 45) - 75 . ( 45 - 25)
=(-25)*30-75*20
=-750-1500
=-2250
\(\frac{2}{3}x\frac{4}{y}=\frac{4}{45}:\frac{1}{5}\)\(=\frac{4}{15}\)
\(\frac{4}{y}=\frac{4}{15}:\frac{2}{3}\)\(=\frac{2}{5}\)
y=4:\(\frac{2}{5}\) y=10
\(\frac{3}{4}x\frac{y}{5}=\frac{15}{4}\)
\(\frac{y}{5}=\frac{15}{4}:\frac{3}{4}=5\)
y=5x5=25
\(\frac{7}{x}+\frac{4}{5.9}+\frac{4}{9.13}+...+\frac{4}{41.45}=\frac{29}{45}\)
\(\Rightarrow\frac{7}{x}+\left(\frac{4}{5.9}+\frac{4}{9.13}+...+\frac{4}{41.45}\right)=\frac{29}{45}\)
\(\Rightarrow\frac{7}{x}+\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+...+\frac{1}{41}-\frac{1}{45}\right)=\frac{29}{45}\)
\(\Rightarrow\frac{7}{x}+\left(\frac{1}{5}-\frac{1}{45}\right)=\frac{29}{45}\)
\(\Rightarrow\frac{7}{x}+\frac{8}{45}=\frac{29}{45}\)
\(\Rightarrow\frac{7}{x}=\frac{29}{45}-\frac{8}{45}\)
\(\Rightarrow\frac{7}{x}=\frac{7}{15}\)
\(\Rightarrow x=15\)
Vậy x = 15
_Chúc bạn học tốt_
a, 5(x – 7) = 0
x – 7 = 0
x = 7
b, 95 – 5(x+2) = 45
5(x+2) = 40
x+2 = 8
x = 6
c, 6 2 x + 2 3 + 40 = 100
6(2x+8) = 60
2x+8 = 10
x = 1
d, 3(3x+9)+6 = 96
3(3x+9) = 90
3x+9 = 30
3x = 27
x = 9
e, 2 6 + 5 + x = 3 4
5+x = 81–64
5+x = 17
x = 12
\(\left(\frac{5}{12}-\frac{5}{7}-\frac{22}{45}+\frac{7}{12}-\frac{23}{45}\right).\left|x\right|-9=-2\)
\(\left(\frac{12}{12}-\frac{5}{7}-\frac{45}{45}\right).\left|x\right|=-2+9\)
\(\left(1-\frac{5}{7}-1\right).\left|x\right|=7\)
\(\frac{-5}{7}.\left|x\right|=7\)
\(\left|x\right|=7:\left(\frac{-5}{7}\right)\)
\(\left|x\right|=\frac{-49}{5}\)
\(\Rightarrow x\in\varnothing\) vì trị tuyệt đối của 1 số luôn dương
-45 x 65 - 45 x 30 - 45 x 3
= -45 x (65 + 30 + 3)
= -45 x 98
= -230
a) -5x (-9) = -11\(\Rightarrow-5\chi=\frac{11}{9}\Rightarrow\chi=\frac{11}{9}:\left(-5\right)\Rightarrow\chi=\frac{11}{9}.\frac{-1}{5}\Rightarrow\chi=\frac{-11}{45}\)b) 25 - (x + 5 ) = -415 - ( 15-415)\(\Rightarrow25-\left(\chi+5\right)=-415-15+415\)
\(\Rightarrow25-\left(\chi+5\right)=\left(-415+415\right)-15\)
\(\Rightarrow25-\left(\chi+5\right)=-15\Rightarrow\chi+5=25+15\)
\(\Rightarrow\chi+5=40\Rightarrow\chi=35\)
HTDT
x : 2 + 5 = 45 : 9
x : 2 + 5 = 5
x : 2 = 5 - 5
x : 2 = 0
x = 0 . 2
x = 0
Vậy x = 0
3