26C 27A 28A 29C 30D

31 she is a teacher

32 she is tall

33 is coming

34 to sit

35 is going to have

36 is fatter than her mother

37 is this book

38 oranges would you like

39 go fishing

40 fly to Hong Kong

26 C

27 A

28 A

29 C

30 D

31 She is a teacher

32 She is tall

33 is coming

34 to sit

35 is going to have

36 My father is fatter than my mother

37 How much is this book?

38 How many oranges would you like?

39 Let's go fishing

40 Lam always flies to Hong Kong

- Trọng phú khinh bần ( không nên )

- Ăn chắc mặc bền

- Tốt gỗ hơn tốt nước sơn

- Nâu sồng nào quản khen chê

Khó thì cho sạch, rách thì cho thơm

- Xấu người đẹp nết còn hơn đẹp người

- Áo vải cơm rau

- Bớt mồm bớt miệng

Sống giản dị
- Trọng phú khinh bần ( không nên)
- Áo vải cơm rau.
- Bớt mồm bớt miệng.
- Sống đơn giản sống lâu trăm tuổi.
- Ăn chắc mặc bền.
-Tốt gỗ hơn tốt nước sơn
Xấu người đẹp nết còn hơn đẹp người.
- Nâu sồng nào quản khen chê
Khó thì cho sạch, rách thì cho thơm.
- Hay quần hay áo hay hơi
Mà chẳng hay người là của bỏ đi.

Yes, it will(câu tr lời đầy đủ), nhưng nếu bạn muốn nó ngắn gọn thì dùng Yes cũng đc, ko sai

Yes, it will

bằng 1220 nha

=1220 nha nhớ cho milk 1 k nhé

Hello, My name is An, they call me Angel. I am 14 years old. I come from Can Tho. I’m in 8th grade and I'm in class 8A5. I’m very interested in learning English. There are four of us in my family, and I am the first child. Nice/glad/pleased to meet you.

My name is An and I’m a Vietnamese. I am twenty-four years old. I live in Ho Chi Minh city in the south of Vietnam.

I have a big family with six people. I have two sisters and a brother. My sisters are older and my brother is younger than me. My father is a teacher at a secondary school. He has worked for 35 years in the field and he is my biggest role model in life. My mother is a housewife. She is nice and she is really good at cooking. I love my family so much.
I’m a generous and easy-going person but when it comes to work I’m a competitive perfectionist. I’m also an optimistic and outgoing person so I have many friends and other social relationships. I enjoy reading, writing and doing math. I decided to become a Civil Engineer because I have always been fascinated by bridges, buildings, and skyscrapers. A degree in Civil Engineering enables me to achieve my goals and also gives me an opportunity to make a difference in the community.

Five years from now, I want to become a project manager of a construction project. As a project manager, my primary goals are managing people, set budgets, and making decisions of all kinds. I also want to speak English fluently so I can work with people from different countries.

món gì mới giải được

môn gì mới giải được chứ

100% qua dễ

bằng 100 phần trăm

2 + 9 + 29 = 40 

x= 2

y=9

2+9+29=40

a/ \(\lim\limits_{x\rightarrow3}\dfrac{\sqrt[3]{x^2-1}-2}{x-3}+\lim\limits_{x\rightarrow3}\dfrac{2-\sqrt[4]{1+5x}}{x-3}\)

\(=\lim\limits_{x\rightarrow3}\dfrac{x^2-1-8}{\left(x-3\right)\left(\sqrt[3]{\left(x^2-1\right)^2}+2.\sqrt[3]{x^2-1}+4\right)}+\lim\limits_{x\rightarrow3}\dfrac{16-1-5x}{\left(x-3\right)\left(\sqrt[4]{\left(1+5x\right)^3}+2\sqrt[3]{\left(1+5x\right)^2}+4.\sqrt[3]{1+5x}+8\right)}\)

\(=\lim\limits_{x\rightarrow3}\dfrac{\left(x-3\right)\left(x+3\right)}{\left(x-3\right)\left(\sqrt[3]{\left(x^2-1\right)^2}+2.\sqrt[3]{x^2-1}+4\right)}+\lim\limits_{x\rightarrow3}\dfrac{-5\left(x-3\right)}{\left(x-3\right)\left(\sqrt[4]{\left(1+5x\right)^3}+2\sqrt[3]{\left(1+5x\right)^2}+4\sqrt[3]{1+5x}+8\right)}\)

\(=\dfrac{3+3}{\sqrt[3]{\left(3^2-1\right)^2}+2.\sqrt[3]{3^2-1}+4}-\dfrac{5}{\sqrt[4]{\left(1+5.3\right)^3}+2\sqrt[3]{\left(1+5.3\right)^2}+4.\sqrt[3]{1+5.3}+8}=\dfrac{11}{32}\)

\(\Rightarrow a^2+b^2=1145\)

40/ 

\(L=\lim\limits_{x\rightarrow0}\dfrac{af\left(x\right)+b^n-b^n}{f\left(x\right)\left[\sqrt[n]{\left(af\left(x\right)+b^n\right)^{n-1}}+b.\sqrt[n]{\left(af\left(x\right)+b^n\right)^{n-2}}+....+b^{n-1}\right]}\)

\(L=\lim\limits_{x\rightarrow0}\dfrac{a}{\sqrt[n]{\left(af\left(x\right)+b^n\right)^{n-1}}+b.\sqrt[n]{\left(af\left(x\right)+b^n\right)^{n-2}}+...+b^{n-1}}\)

\(L=\lim\limits_{x\rightarrow0}\dfrac{a}{b^{n-1}+b^{n-1}++...+b^{n-1}}=\dfrac{a}{nb^{n-1}}\)