\(1,=x\left(x^2-2x+1-y^2\right)=x\left[\left(x-1\right)^2-y^2\right]=x\left(x-y-1\right)\left(x+y-1\right)\\ 2,=\left(x+y\right)^3\\ 3,=\left(2y-z\right)\left(4x+7y\right)\\ 4,=\left(x+2\right)^2\\ 5,Sửa:x\left(x-2\right)-x+2=0\\ \Leftrightarrow\left(x-2\right)\left(x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=2\end{matrix}\right.\)

4x²z + 8xyz + 4y²z

= z(4x² + 8xy + 4y²)

= \(z\left[\left(2x\right)^2+2.2x.2y+\left(2y\right)^2\right]\)

= z(2x + 2y)²

Cảm ơn b 

\(\left(x+y+z\right)^3-x-y-z\\ =\left(x+y+z\right)^3-\left(x+y+z\right)\\ =\left(x+y+z\right)\left(\left(x+y+z\right)^2-1\right)\\ =\left(x+y+z\right)\left(x+y+z-1\right)\left(x+y+z+1\right)\)

Ta có

4x( 2y - z ) + 7y( z - 2y ) = 4x( 2y - z ) - 7y( 2y - z ) = ( 2y - z )( 4x - 7y ).

Chọn đáp án B.

4y(2x-z)+7x(z-2x)

=4y(2x-z)-7x(2x-z)

=(2x-z)(4y-7)

\(=\left(4y-7x\right)\left(2x-z\right)\)

Ta có 4x( 2y - z ) + 7y( z - 2y ) = 4x( 2y - z ) - 7y( 2y - z ) = ( 2y - z )( 4x - 7y ).

Chọn đáp án B.

\(=3^2-z^2=\left(3-z\right)\left(3+z\right)\)

\(2\left(x-z\right)+xy-yz\)

\(=2\left(x-z\right)+y\left(z-z\right)\)

\(=\left(x-z\right)\left(2+y\right)\)

sao chép à bạn :)))