=> (x+2020)/5=(x+2020)/6=(x+2020)/3+(x+2020)/2

=>(x+2020)(1/5+1/6)=(x+2020)(1/3+1/2)

Với x+2020=0=>x=-2020

Với x+2020 khác 0=>1/5+1/6=1/3+1/2 ,vô lí 

Vậy x=-2020

cong 1 vao tung hang tu (vd 3/2013) roi dc tong 2016

\(\frac{x+3}{2013}+1+\)\(\frac{x+4}{2012}+1+\frac{x+5}{2011}+1\)=\(\frac{x+1}{2015}+1+\frac{x+2}{2014}+1+\frac{x}{2016}+1\)

 \(\Rightarrow\frac{x+2016}{2013}+\frac{x+2016}{2012}+\frac{x+2016}{2011}=\frac{x+2016}{2014}+\frac{x+2016}{2016}\)

\(\Rightarrow\left(2016+x\right)\left(\frac{1}{2013}+\frac{1}{2012}+\frac{1}{2011}+\frac{1}{2015}+\frac{1}{2014}+\frac{1}{2016}=0\right)\)

Vì 1/2016+...+1/2011>0 nên (x+2016)=0

suy ra x= -2016

nếu đúng xin kết bạn

ch

toán lớp 1 khó thế

\(Q=\frac{2014}{2015}\times3+\frac{2014}{2015}\times\frac{5}{6}-\frac{2014}{2015}\times\frac{10}{12}\)

\(Q=\frac{2014}{2015}\times\left(3+\frac{5}{6}-\frac{10}{12}\right)\)

\(Q=\frac{2014}{2015}\times3\)

\(Q=\frac{6042}{2015}\)

Q=2014/2015x(3 +5/6 - 10/12)

Q= 2014/2015x 3

Q= 6042/2015

Vì \(\frac{x}{2}+\frac{x}{4}+\frac{x}{2014}=\frac{x}{3}+\frac{x}{5}+\frac{x}{2015}\)

\(\Rightarrow x\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{2014}\right)=x\left(\frac{1}{3}+\frac{1}{5}+\frac{1}{2015}\right)\)

Mà \(\frac{1}{2}+\frac{1}{4}+\frac{1}{2014}\ne\frac{1}{3}+\frac{1}{5}+\frac{1}{2015}\)

\(\Rightarrow x=0\)

\(X=0\)

các bạn giúp mk với nhá

giúp mình với

\(\frac{3+5+7+...+2015}{2+4+6+...+2014}+x=1\)

\(\frac{\left(3+2015\right).\left[\left(2015-3\right):2+1\right]:2}{\left(2+2014\right).\left[\left(2014-2\right):2+1\right]:2}+x=1\)

\(\frac{1016063}{1015056}+x=1\)

\(x=1-\frac{1016063}{1015056}\)

\(x=-\frac{1}{1008}\)

Giải:

\(B=\left(5+10+15+...+2015\right)\times\left(20142014\times2015-20152015\times2014\right)\) 

\(B=\left(5+10+15+...+2015\right)\times\left(10001\times2014\times2015-10001\times2015\times2014\right)\)

\(B=\left(5+10+15+...+2015\right)\times0\) 

\(B=0\) 

Chúc em học tốt!

B = (5+10+15+.........+2015) x (20142014 x 2015-20152015 x 2014)