hlo mn nha
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b: Xét ΔABH vuông tại H có
\(AB^2=AH^2+HB^2\)
hay AH=12(cm)
Xét ΔAHB vuông tại H có
\(\sin\widehat{B}=\cos\widehat{C}=\dfrac{AH}{AB}=\dfrac{12}{13}\)
\(\cos\widehat{B}=\sin\widehat{C}=\dfrac{5}{13}\)
\(\tan\widehat{B}=\cot\widehat{C}=\dfrac{12}{5}\)
\(\cot\widehat{B}=\tan\widehat{C}=\dfrac{5}{12}\)
2 she had got the price of the contest, she would be happy now
3 I had gone to the concert last night ,I would be tired
4 John had finished all his homework, he could see a movie now
5 we had listened to my mother, we wouldn't be in trouble right now
Ex5
1 you arrive at the offcie earlier than I do, please turn on the air-conditioner
2 Were it not snowy, the children would go to school
3 he not died so young, he would be a famous musician
4 Were I you, I would take care of my car
5 not very bad-tempered, his wife would give him soon are marrage
6 Had she not got married at such an early age, he would be at university
Câu 36: -6(x+7)=96
=>x+7=-16
=>x=-16-7
=>x=-23
=>Chọn D
Câu 35: B
Câu 34: -5-x=-11
=>x+5=11
=>x=11-5
=>x=6
=>Chọn A
câu 33: B
câu 32: A
Câu 31: C
Câu 30: A
Câu 29: B
Câu 28: A
Câu 22: A
Câu 23: A
Câu 24: B
Câu 25: A
Câu 26: C
Câu 27: D
Câu 10: D
Câu 11: B
Câu 12: A
Câu 13:A
Câu 15: D
Câu 16: C
Câu 17: C
câu 18: B
Câu 19: A
Câu 20: D
Câu 21: B






câu 9 sẽ kco nhé mn, mn giúp mình hoàn thiện xong nhanh nha, mn có thể làm bnhieu câu trở lên cũng đc nha 




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