`4 / 15 . 1 / 3 . 15 / 20`

`= [ 4 . 1 . 15 ] / [ 15 . 3 . 20 ]`

`= [ 4 . 1 . 15 ] / [ 15 . 3 . 4 . 5 ]`

`= 1 / [ 3 . 5 ]`

`= 1 / 15`

\(=\left(\dfrac{4}{15}.\dfrac{15}{20}\right).\dfrac{1}{3}=\dfrac{60}{300}.\dfrac{1}{3}=\dfrac{60}{900}=\dfrac{1}{15}\)

\(3.\left(-5\right)^2+2.\left(-15\right)-20=3.25-2.15-20=75-30-20=25\)

#)Giải :

      1,25 : 15/20 + 25% - 5/6

=    5/4 : 3/4 + 1/4 - 5/6

=    5/3 + 1/4 - 5/6

=    23/12 - 5/6

=    13/12

       #~Will~be~Pens~#

1,25 : \(\frac{15}{20}\)+ 25% - \(\frac{5}{6}\)

= \(\frac{5}{4}\): \(\frac{3}{4}\)+\(\frac{1}{4}\)- \(\frac{5}{6}\)

= \(\frac{5}{4}\)x\(\frac{4}{3}\)+\(\frac{1}{4}\)-\(\frac{5}{6}\)

= \(\frac{5}{3}\)+\(\frac{1}{4}\)-\(\frac{5}{6}\)

= \(\frac{20+3}{12}\)-\(\frac{5}{6}\)

= \(\frac{23}{12}\)-\(\frac{5}{6}\)

= \(\frac{23-10}{12}\)

= \(\frac{13}{12}\)

a) Mẫu số chung = BCNN(11, 7) = 77

Thừa số phụ: 77: 11= 7; 77:7 = 11.

Ta có:

\(\begin{array}{l}\frac{7}{{11}} + \frac{5}{7} = \frac{{7.7}}{{11.7}} + \frac{{5.11}}{{7.11}}\\ = \frac{{49}}{{77}} + \frac{{55}}{{77}} = \frac{{104}}{{77}}\end{array}\).

b) Mẫu số chung = BCNN(20, 15)= 60 

Thừa số phụ: 60:20 = 3; 60:15 = 4

Ta có:

\(\begin{array}{l}\frac{7}{{20}} - \frac{2}{{15}} = \frac{{7.3}}{{20.3}} - \frac{{2.4}}{{15.4}}\\ = \frac{{21}}{{60}} - \frac{8}{{60}} = \frac{{13}}{{60}}\end{array}\).

\(20\frac{15}{16}.16\frac{8}{9}-20\frac{15}{16}.12\frac{8}{9}\)

\(=20\frac{15}{16}.\left(16\frac{8}{9}-12\frac{8}{9}\right)\)

\(=20\frac{15}{16}.4\)

\(=83\frac{3}{4}\)

\(5^{20}:\left(5^{15}.6+5^{15}.9\right)\)

\(=5^{20}:5^{15}.\left(6+9\right)\)

\(=5^5.15\)

\(=\)\(46875\)

#include <bits/stdc++.h>
using namespace std;
char a;
int main()
{
    cin>>a;
    if (a=='S') cout<<"50";
    else cout<<"600";
    return 0;
}

=\(\left[\dfrac{\left(0,4.2\right)^5}{\left(0,4\right)^6}+\dfrac{2^9.2^6.3^8}{\left(3.2\right)^6.2^9}\right]=\left[\dfrac{\left(0,4\right)^5.2^5}{\left(0,4\right)^6}+\dfrac{2^6.3^8}{3^6.2^6}\right]\)

=\(\left[\dfrac{2^5}{0,4}+3^2\right]\)

=\(\left[80+9\right]=89\)

\(\left[\dfrac{\left(2.0,4\right)^5}{0,4,0,4^5}+\dfrac{2^{15}.3^8}{3^6.2^6.2^9}\right]\div\dfrac{3^{20}.5^{30}}{3^{15}.5^{30}}\)

\(=\left[\dfrac{2^5.0.4^5}{0,4.0,4^5}+\dfrac{2^{15}.3^8}{3^6.2^{15}}\right]\div3^5\)

\(=\left[\dfrac{2^5}{0,4}+3^2\right]\div243\)

\(=80+\left(3^5\div3^2\right)\)

\(=80+3^3\)

\(=80+27\)

\(=107\)

\(a,\dfrac{3}{5}+\dfrac{1}{5}.\dfrac{-17}{9}=\dfrac{3}{5}-\dfrac{17}{45}=\dfrac{27}{45}-\dfrac{17}{45}=\dfrac{10}{45}=\dfrac{2}{9}\\ b,\left(-\dfrac{4}{15}-\dfrac{18}{19}\right)-\left(\dfrac{20}{19}+\dfrac{11}{15}\right)=-\dfrac{4}{15}-\dfrac{18}{19}-\dfrac{20}{19}-\dfrac{11}{15}=\left(-\dfrac{4}{15}-\dfrac{11}{15}\right)-\left(\dfrac{18}{19}+\dfrac{20}{19}\right)=-1-2=-3\)

\(a,=\dfrac{3}{5}+\left(-\dfrac{17}{45}\right)=\dfrac{2}{9}\)

\(b,=-\dfrac{4}{15}-\dfrac{18}{19}-\dfrac{20}{19}-\dfrac{11}{15}=-3\)

a.2/9
b.-3

a.2/9 b.(-3)