x + x + 1 + x + 2 + .........+  x + 99 = 5450

100x + ( 1 + 2 + ..... + 99 ) = 5450

100x + 4950 = 5450

100x = 500

x = 5

vậy: x = 5

bạn tk mk nha! đúng 100%.

x + (x + 1) + (x + 2) + .... + (x + 99) = 5450

<=> x + x + 1 + x + 2 + .... + x + 99 = 5450

<=> ( x + x + ... + x ) + ( 1 + 2 + ... + 99 ) = 5450

<=> 100x + 99.100/2 = 5450

<=> 100x + 4950 = 5450

<=> 100x = 500

=> x = 5

Vậy x = 5

=>(x+x+x+...+x)+(1+2+3+...+99)=5450(100 số hạng x)

=>100x+4950=5450

=>100x=5450-4950

=>100x=500

=>x=5

 Vậy x=5

co the do hon khong

3 . ( 5^x -1 ) - 2 = 70

3 . ( 5^x -1 )       = 70 + 2

3 . ( 5^x -1 )       = 72

      5^x -1           = 72 : 3

      5^x -1           = 24 

      5^x               = 24 + 1

       5^x              = 25

       5^x              = 5²

=>  x = 2

a, \(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+90\right)=5450\)

\(\left(x+x+x+...+x\right)+\left(1+2+3+...+90\right)=5450\)

\(91x+4095=5450\)

\(91x=1355\)

\(x=\frac{1355}{91}\)

b, \(2^x+2^{x+1}+2^{x+2}=960-2^{x+3}\)

\(2^x+2^x.2+2^x.2^2+2^x.2^3=960\)

\(2^x\left(1+2+2^2+2^3\right)=960\)

\(2^x.15=960\)

\(2^x=64=2^6\)

\(\Rightarrow x=6\)

a)    1 + 2 + 3 + ....... + x = 1275

<=> ( x + 1 ) . x : 2 = 1275

        ( x + 1 ) . x   = 1275 .2

          ( x + 1 ) . x = 2550

           ( x + 1 ) . x = 51 . 50

          ( x + 1 ) . x = ( 50 + 1 ) . 50

<=> x = 50

b)      ( x + 1 ) +( x + 2 ) +..... +( x + 99 ) = 6138

           x + 1 + x + 2 + .........+ x + 99 = 6138

            99x + ( 1 + 2 + .......... + 99  ) = 6138

                                       99x + 4950 = 6138

                                          99x          = 1188

                                                  x      = 1188 : 99

                                                  x      = 12

c)    x . 1 + x . 2 + ......... + x . 99 = 495

             x. ( 1 + 2 + ...... + 99 ) = 495

              x . 4950 = 495

              x            = 495 : 4950

                 x         = 1/10

a: \(\left(1-\frac12\right)\times\left(1-\frac13\right)\times\ldots\times\left(1-\frac{1}{99}\right)\)

\(=\frac12\times\frac23\times\ldots\times\frac{98}{99}\)

\(=\frac{1}{99}\)

b: \(\left(x+\frac12\right)+\left(x+\frac16\right)+\left(x+\frac{1}{12}\right)+\left(x+\frac{1}{20}\right)+\cdots+\left(x+\frac{1}{90}\right)=\frac{99}{10}\)

=>\(\left(x+\frac{1}{1\times2}\right)+\left(x+\frac{1}{2\times3}\right)+\cdots+\left(x+\frac{1}{9\times10}\right)=\frac{99}{10}\)

=>\(9\times x+1-\frac12+\frac12-\frac13+\cdots+\frac19-\frac{1}{10}=\frac{99}{10}\)

=>\(9\times x+1-\frac{1}{10}=\frac{99}{10}\)

=>\(9\times x=\frac{99}{10}+\frac{1}{10}-1=\frac{100}{10}-1=10-1=9\)

=>x=1

x+(x+1)+(x+2)+......+(x+99)=100x+99.100/2=100x+4550=5450

=>100x=900=>x=9. Vậy: x=9

\(b,2^x+2^{x+2}=960-2^{x+3}\Leftrightarrow2^x+2^{x+2}+2^{x+3}=960\)

\(\Leftrightarrow2^x\left(1+4+8\right)=960\Leftrightarrow2^x.13=960\Rightarrow2^x=960:13\Rightarrow\left(\text{có sai đề ko?}\right)\)

1A, x+(x+1)+(x+2)+...+(x+99)=5450

     (x+x+x+x+...+x)+(1+2+3+4+...+99)=5450

      x*100+4950=5450

      x*100            =5450-4950

       x*100            =500

       x                    =500:100

       x                     = 5

Vậy x = 5

Học tốt nha~

a) \(\frac{x-1}{99}+\frac{x-2}{98}+\frac{x-3}{97}+\frac{x-4}{96}=4\)

\(\Rightarrow\frac{x-1}{99}-1+\frac{x-2}{98}-1+\frac{x-3}{97}-1+\frac{x-3}{96}-1=4-4\)

\(\Rightarrow\frac{x-100}{99}+\frac{x-100}{98}+\frac{x-100}{97}+\frac{x-100}{96}=0\)

\(\Rightarrow\left(x-100\right)\left(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{96}\right)=0\)

\(\Rightarrow x-1=0\) ( vì \(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{96}\ne0\) )

Vậy x = 1

b) \(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}=3\)

\(\Rightarrow\frac{x+1}{99}+1+\frac{x+2}{98}+1+\frac{x+3}{97}+1=3-3\)

\(\Rightarrow\frac{x+100}{99}+\frac{x+100}{98}+\frac{x+100}{97}=0\)

\(\Rightarrow\left(x+100\right).\left(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}\right)=0\)

Vì \(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}\ne0\)

=> x + 100 = 0

=> x           = -100

c) \(\frac{x-1}{99}+\frac{x-2}{49}+\frac{x-4}{32}=6\)

\(\Rightarrow\frac{x-1}{99}-1+\frac{x-2}{49}-2+\frac{x-4}{32}-3=6-6\)

\(\Rightarrow\frac{x-100}{99}+\frac{x-100}{49}+\frac{x-100}{32}=0\)

\(\Rightarrow\left(x-100\right)\left(\frac{1}{99}+\frac{1}{49}+\frac{1}{32}\right)=0\)

Vì \(\frac{1}{99}+\frac{1}{49}+\frac{1}{32}\ne0\)

=> x - 100 = 0

=> x           = 100

Chúc bạn học tốt

có người khác trả lời trước rồi nên chị ko trả lời đâu nhé em trai

cau 1 :

Tu dau bai ta co:

 X x 50 + ( 100 + 2 ) x 50 : 2 = 2700

 X x 50 + 2550 = 2700

X x 50 = 2700 - 2550

X x 50 = 150

X = 150 : 50

X = 3

Bai 2 

1 ) ( 99 + 0 ) x 100 : 2 = 4950

2 ) ( 99 + 1 ) x 99 : 2 = 4950

3 )    day tren co so cac so hang la :

              ( 99 - 1 ) : 2 + 1 = 50 ( so )

Vay tong la : ( 99 + 1 ) x 50 : 2 = 2500

lik e cho minh nha moi nguoi