\(142-\left[50-\left(2^3×10-2^3×5\right)\right]\)

\(=142-\left[50-\left(8×10-8×5\right)\right]\)

\(=142-\left[50-\left(80-40\right)\right]\)

\(=142-\left[50-40\right]\)

\(=142-10\)

\(=132\)

142-[50-(8 x 10 - 8 x5)]

142-{50-[8 x(10-5)}

142-{50-8 x 5}

142-{50-40}

142-10

132

có ai giải giúp mình ko mình đang gấp huhu

2^x x 16 = 128 

2^x          = 128 : 16

2 ^x        = 8

2^x         = 2³

3^x : 9 = 27 

3^x      = 27 x 9

3^x      =243

3^x      = 3⁵

[ 2^x + 1 ]³ = 27

2^x3 + 1³   = 27

2^x3 +1      = 27

2^x3           = 27 - 1

2^x3           = 26

\(3^{x-2}=27\)

=>\(3^{x-2}=3^3\)

=>\(x-2=3\)

=>\(x=5\)

<=>x-2=3

<=>x=5

=9x2^25-2^2x2^26/2^24x5^2-2^27x3

=9x2^25-2^28/2^24x5^2-2^27x3

=2^25x(9-2^3)/2^24x(5^2-2^3x3)

=2^25/2^24

=2^1=2

3⁷ x 27⁵ x 81³ = 3⁷ x 3¹⁵ x 3¹² = 3^7+15+12 = 3³⁴

36⁵ : 18⁵ = (36 : 18)⁵ = 2⁵ = 32

24 x 5⁵ + 5² x 5³ = 24 x 5⁵ + 5⁵ = 5⁵ x (24 + 1) = 5⁵ x 25  = 5⁵ x 5² = 5⁷

125⁴ : 5⁸ = 125⁴ : (5²)⁴ = 125⁴ : 25⁴ = (125 : 25)⁴ = 6⁴

tk cho cj nha

TL ;

helu kni do di mn

ht

a) \(\left(2x+1\right)^3=27\)

\(\Leftrightarrow2x+1=3\)

\(\Leftrightarrow x=1\)

b) \(\left(2x-1\right)^3=125\)

\(\Leftrightarrow2x-1=5\)

\(\Leftrightarrow x=3\)

c) \(\left(x+1\right)^4=\left(2x\right)^4\)

\(\Leftrightarrow x+1=2x\)

\(\Leftrightarrow x=1\)

d) \(\left(2x-1\right)^5=x^5\)

\(\Leftrightarrow2x-1=x\)

\(\Leftrightarrow x=1\)

a. ( 2x + 1 )³ = 27

<=> ( 2x + 1 )³ = 3³

<=> 2x + 1 = 3

<=> 2x = 2

<=> x = 1

b. ( 2x - 1 )³ = 125

<=> ( 2x - 1 )³ = 5³

<=> 2x - 1 = 5

<=> 2x = 6

<=> x = 3

c. ( x + 1 )⁴ = 2x⁴

<=> x + 1 = 2x

<=> x = 1

d. ( 2x - 1 )⁵ = x⁵

<=> 2x - 1 = x

<=> x = 1

\(\frac{1}{6^{x}}.42^{x}=343\)

=> \(\frac{1}{6^3}.42^3=7^3\)

=> \(\frac{42^{x}}{6^{x}}=343\)

=> \(\left(\frac{42}{6}\right)^{x}=343\)

=> \(7^{x}=7^3\)

=> \(x=3\)

Vậy : \(x=3\)

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