còn 3 câu sau thì sao vậy bn

Bạn nên viết đề bằng công thức toán (biểu tượng $\sum$ góc trái khung soạn thảo) để mọi người hiểu đề của bạn hơn.

\(\left(\dfrac{3}{5}\right)^{10}\cdot\left(\dfrac{5}{3}\right)^{10}-\dfrac{13^4}{39^4}+2014^0\)

=1-(1/3)^4+1

=4/3-1/81

=107/81

1) \(\Rightarrow x^2\left(x^{2004}-1\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x^{2004}=1\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=0\\x=1\\x=-1\end{matrix}\right.\)

2) \(\Rightarrow\left(x-5\right)^4\left[\left(x-5\right)^2-1\right]=0\)

\(\Rightarrow\left[{}\begin{matrix}x-5=0\\\left(x-5\right)^2=1\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=5\\x-5=1\\x-5=-1\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=5\\x=6\\x=4\end{matrix}\right.\)

\(\left(\dfrac{9}{4}\right)^{x-6}=\left(\dfrac{27}{8}\right)^{x-2}\)

\(\Leftrightarrow\left[\left(\dfrac{3}{2}\right)^2\right]^{x-6}=\left[\left(\dfrac{3}{2}\right)^3\right]^{x-2}\)

\(\Leftrightarrow\left(\dfrac{3}{2}\right)^{2x-12}=\left(\dfrac{3}{2}\right)^{3x-6}\)

\(\Leftrightarrow2x-12=3x-6\)

\(\Leftrightarrow-12+6=3x-2x\)

\(\Leftrightarrow x=-6\)

Vậy ............

P/S : Lần sau gỗ bằng công thức toán nhs bn :)

uk bn

(1/5)mũ 2 .n=(1/5)mũ 15

=>n=(1/5)mũ 13

(\(\frac{1}{5}\))² .n = (\(\frac{1}{125}\))³ - n

<=> \(\frac{1}{25}\)n +n = \(\frac{1}{5^9}\)

<=> \(\frac{26}{25}\)n = \(\frac{1}{5^9}\)

<=> n = \(\frac{1}{5^9}\): \(\frac{26}{25}\)= \(\frac{1}{2031250}\)

a, \(\left(x+\frac{4}{3}y^2\right)^2\)

\(=x^2+\frac{8}{3}xy^2+\frac{16}{9}y^4\)

b, \(\left(2x-3y\right)^2\)

\(=4x^2-12xy+9y^2\)

c, \(\left(x^2+2x\right)\left(2x-x^2\right)\)

\(=\left(2x+x^2\right)\left(2x-x^2\right)\)

\(=4x^2-x^4\)

d, \(\left(x+\frac{1}{2}\right)^3\)

\(=x^3+\frac{3}{2}x^2+\frac{3}{4}x+\frac{1}{8}\)

e, \(\left(2x-\frac{6}{5}y\right)^3\)

\(=8x^3-\frac{72}{5}x^2y+\frac{216}{25}xy^2-\frac{216}{125}y^3\)

Ta có :

\(\frac{1}{243^9}=\frac{1}{\left(81.3\right)^9}=\frac{1}{81^9.27^3}>\frac{1}{81^9.81^3}=\frac{1}{81^{11}}>\frac{1}{8^{12}}>\frac{1}{8^{13}}\)

\(\Rightarrow\frac{1}{243^9}>\frac{1}{83^{13}}\)

mình chắc chắn luôn

-https://olm.vn/hoi-dap/detail/77727486175.html

\(\left(\frac{1}{2}\right)^{40}=\left(\frac{1}{2}\right)^{10\cdot4}=\left(\frac{1}{16}\right)^{10}\)

Mà ta có

\(\left(\frac{1}{32}\right)^{10}< \left(\frac{1}{16}\right)^{10}\)

\(\Rightarrow\left(\frac{1}{2}\right)^{40}>\left(\frac{1}{32}\right)^{10}\)

a)\(x^{15}=x\Rightarrow x\in\left\{0;1\right\}\)                                            d)Là ý b

b)\(\left(2x+1\right)^3=125\\ \left(2x+1\right)^3=5^3\Rightarrow2x+1=5\\ 2x=4\\ x=2\)                       e)\(\left(x-3\right)^2=25\\ \Rightarrow\left(x-3\right)^2=5^2\\ \Rightarrow\hept{\begin{cases}x-3=5\Rightarrow x=8\\x-3=-5\Rightarrow x=-2\end{cases}}\)

c)\(\left(x-5\right)^4=\left(x-5\right)^6\\ \Rightarrow x-5\in\left\{0;1\right\}\Rightarrow x\in\left\{5;6\right\}\)