a: 5x-9=5+3x

=>5x-3x=5+9

=>2x=14

=>\(x=\frac{14}{2}=7\)

b: \(2^3+0,5x=1,5\)

=>0,5x+8=1,5

=>0,5x=1,5-8=-6,5

=>\(x=-6,5:0,5=-13\)

c: \(\left(5x+1\right)^2=\frac{36}{49}\)

=>\(\left[\begin{array}{l}5x+1=\frac67\\ 5x+1=-\frac67\end{array}\right.\Rightarrow\left[\begin{array}{l}5x=\frac67-1=\frac17\\ 5x=-\frac67-1=-\frac{13}{7}\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac17:5=\frac{1}{35}\\ x=-\frac{13}{7}:5=-\frac{13}{35}\end{array}\right.\)

d: \(\left(-\frac{3}{81}\right)^{x}=-27\)

=>\(\left(-\frac{1}{27}\right)^{x}=-27\)

=>\(x=-1\)

e: \(2^{x-1}=16\)

=>\(2^{x-1}=2^4\)

=>x-1=4

=>x=4+1=5(nhận)

\(\left(\dfrac{3}{2}\right)^{x+2}=\dfrac{81}{16}\)

\(\left(\dfrac{3}{2}\right)^x.\left(\dfrac{3}{2}\right)^2=\dfrac{81}{16}\)

\(\left(\dfrac{3}{2}\right)^x=\dfrac{81}{16}:\dfrac{9}{4}=\dfrac{9}{4}\)

\(\left(\dfrac{3}{2}\right)^x=\left(\dfrac{3}{2}\right)^2\)

⇔\(x=2\)

a: Ta có: \(\left(\dfrac{3}{2}\right)^{x+2}=\dfrac{81}{16}\)

\(\Leftrightarrow x+2=4\)

hay x=2

b: Ta có: \(2^{x^2-5x}=1\)

\(\Leftrightarrow x\left(x-5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=5\end{matrix}\right.\)

a, \(4\left(18-5x\right)-12\left(3x-7\right)=15\left(2x-16\right)-6\left(x+14\right)\)

\(\Rightarrow72-20x-36x+84=30x-240-6x-84\)

\(\Rightarrow-20x-36x-30x+6x=-240-84-72-84\)

\(\Rightarrow-80x=-480\Rightarrow x=6\)

b, \(5\left(3x+5\right)-4\left(2x-3\right)=5x+3\left(2x+12\right)+1\)

\(\Rightarrow15x+25-8x+12=5x+6x+36+1\)

\(\Rightarrow15x-8x-5x-6x=36+1-25-12\)

\(\Rightarrow-4x=0\Rightarrow x=0\)

c, \(2\left(5x-8\right)-3\left(4x-5\right)=4\left(3x-4\right)+11\)

\(\Rightarrow10x-16-12x+15=12x-16+11\)

\(\Rightarrow10x-12x-12x=-16+11+16-15\)

\(\Rightarrow-14x=-4\Rightarrow x=\dfrac{2}{7}\)

d, \(5x-3\left\{4x-2\left[4x-3\left(5x-2\right)\right]\right\}=182\)

\(\Rightarrow5x-3\left[4x-2\left(4x-15x+6\right)\right]=182\)

\(\Rightarrow5x-3\left(4x-8x+30x-12\right)=182\)

\(\Rightarrow5x-12x+24x-90x+36=182\)

\(\Rightarrow-73x=182-36\)

\(\Rightarrow-73x=146\Rightarrow x=-2\)

Chúc bạn học tốt!!!

A.5x. (5^3)^2=625

5x= 1/25

x=125

tìm x nha bạn

3,26 + 4/5 =?

làm nhanh lên giúp mình nhé

3,26+4/5=3,26+0,8=3,34

K cho mình cái

cậu nói thế nghe dễ quá hen

\(\frac{x+3}{12}+\frac{2x+46}{16}=\frac{3x+9}{36}+\frac{5x+81}{6}\Leftrightarrow\frac{2\left(x+3\right)}{24}+\frac{\frac{3}{2}\left(2x+46\right)}{\frac{3}{2}.16}=\frac{\frac{2}{3}\left(3x+9\right)}{\frac{2}{3}.36}+\frac{4\left(5x+81\right)}{4.6}\)

\(\Leftrightarrow\frac{2\left(x+3\right)}{24}+\frac{3x+69}{24}=\frac{2x+6}{24}+\frac{20x+324}{24}\)\(\Leftrightarrow2x+6+3x+69=2x+6+20x+324\Leftrightarrow17x=-255\Leftrightarrow x=-\frac{255}{17}\)Vậy \(x=-\frac{255}{17}\)

\(4x\left(x^2-5x+3\right)=4x^3-20x^2+12x\)

=> Chọn A