nnhanh len giumm

ban kia lam dung roi do 

k tui nha

thanks

\(A=2^0+2^1+2^2+...+2^{21}\)

\(2A=2^1+2^2+2^3+...+2^{22}\)

\(2A-A=\left(2^1+2^2+2^3+...+2^{22}\right)-\left(2^0+2^1+2^2+...+2^{21}\right)\)

\(A=2^{22}-1\)

\(2^{22}-1=2^{2n}-1\)

\(2^{2\times11}-1=2^{2n}-1\)

n = 11

câu 1: 11

câu 2: 0,125

câu 3: -1;0;1

câu 4: -2,5

x = 1/8 = 0,125

mk thi rùi 300đ

x= 0,125

gtln la 4032 khi x = 3

ban giai thich cho minh voi

\(\left(x-y\right)^2+4xy=100\)

=>\(x^2-2xy+y^2+4xy=100\)

=>\(x^2+2xy+y^2=100\)

=>\(\left(x+y\right)^2=100\)

=>x+y=10 hoặc x+y=-10

P=xy<=\(\frac{\left(x+y\right)^2}{4}=\frac{100}{4}=25\)

Dấu '=' xảy ra khi x=y

TH1: x+y=10

mà x=y

nên \(x=y=\frac{10}{2}=5\)

TH2: x+y=-10

mà x=y

nên \(x=y=\frac{-10}{2}=-5\)

\(x^2+2xy+6x+6y+2y^2+8=0\\ \Leftrightarrow\left(x+y\right)^2+6\left(x+y\right)+y^2=-8\)

Ta có \(y^2\ge0\Leftrightarrow\left(x+y\right)^2+6\left(x+y\right)\le-8\)

\(\Leftrightarrow\left(x+y\right)^2+6\left(x+y\right)+9\le1\\ \Leftrightarrow\left(x+y+3\right)^2\le1\\ \Leftrightarrow\left|x+y+3\right|\le1\\ \Leftrightarrow-1\le x+y+3\le1\\ \Leftrightarrow2012\le B\le2014\)

\(B_{min}=2012\Leftrightarrow\left\{{}\begin{matrix}x+y+2016=2012\\y=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-4\\y=0\end{matrix}\right.\)

\(B_{max}=2014\Leftrightarrow\left\{{}\begin{matrix}x+y+2016=2014\\y=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-2\\y=0\end{matrix}\right.\)

có đk j ko bn

Mình thì nghĩ nó là GTNN 

Chúc học giỏi !!!