(103+104+1252):53
(723.542):1084
(310.11+310.5):(39.24)
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Đáp án là C
Ta có: ( 10 3 + 10 4 + 125 2 ): 5 3
= (1000 + 10000 + 15625):125
= 26625:125 = 213
Đáp án là C
Ta có: ( 10 3 + 10 4 + 125 2 ): 5 3
= (1000 + 10000 + 15625):125
= 26625:125 = 213
\(a,\dfrac{3^{43}+3^4}{3^{39}+1}\)
\(=\dfrac{3^4\cdot\left(3^{39}+1\right)}{3^{39}+1}\)
\(=3^4\)
\(=81\)
\(4^{10}.8^{15}=2^{20}.2^{45}=2^{65}\)
\(4^{15}.5^{30}=2^{30}.5^{30}=10^{30}\)
\(27^{16}:9^{10}=3^{48}:3^{20}=3^{28}\)
\(72^3.54^2=2^9.3^6.2^2.3^6=2^{11}.3^{12}\)
\(108^4=2^8.3^{12}\)
\(3^{10}.11+3^{10}.5=3^{10}.\left(11+5\right)=3^{10}.16\)
\(3^9.2^4=3^9.2^4\)
`@` `\text {Ans}`
`\downarrow`
`4^10*8^15`
`= (2^2)^10 * (2^3)^15`
`= 2^20 * 2^45`
`=`\(2^{20+45}=2^{65}\)
`4^15 * 5^30`
`= (2^2)^15 * 5^30`
`= 2^30 * 5^30`
`= (2*5)^30`
`= 10^30`
`27^16 \div 9^10`
`= (3^3)^16 \div (3^2)^10`
`= 3^48 \div 3^20`
`=`\(3^{48-20}=3^{28}\)
`A = `\(72^3\cdot54^2\cdot108^4\)
`= 2^9 * 3^6 * 3^4 * 3^2 * 2^2 * 3^8 * 3^4 * 2^4 * 2^4`
`=`\(\left(2^9\cdot2^2\cdot2^4\cdot2^4\right)\cdot\left(3^6\cdot3^4\cdot3^2\cdot3^8\cdot3^4\right)\)
`= 2^19 * 3^24`
`B = 3^10 * 11 + 3^10 * 5 + 3^9 * 2^4`
`= 3^9 * (11*3 + 5*3 + 2^4)`
`= 3^9 * (33 + 15 + 16)`
`= 3^9 * 64`
`= 27^3 * 4^3`
`= (27 * 4)^3`
`= 108^3`
-101+102-103+104+...-299+300 ( 202 số )
= -101+102+ ( - 103 ) + 104+...+ ( - 299 )+300
= - 1 + ( - 1 ) + .......... + ( - 1 ) ( có 101 số - 1 )
= - 1 . 101
= - 101
Bài 1:
a: \(A=15\cdot31\cdot2+5\cdot27\cdot6+10\cdot42\cdot3\)
\(=30\cdot31+30\cdot27+30\cdot42\)
\(=30\left(31+27+42\right)\)
\(=30\cdot100=3000\)
b: \(B=3\cdot5^2+160:\left(9-5\right)^2\)
\(=3\cdot25+160:4^2\)
=75+160:16
=75+10
=85
c: \(C=10^3\cdot\left\lbrace540-\left\lbrack6^3+\left(5\cdot4^2+104\right)\right\rbrack\right\rbrace\)
\(=1000\cdot\left\lbrace540-\left\lbrack216+5\cdot16+104\right\rbrack\right\rbrace\)
=1000{540-[216+80+104]
=1000*{540-400}
=1000*140
=140000
49 x 37 = 37 x 49
(214 x 25) x 4 = 214 x (25 x 4)
103 x 18 + 103 x 12 = 103 x (18 + 12)