`3xx(x-1/6)-2xx(x-1/3)=2/3`

`3x-1/2-2x+2/3=2/3`

`x=2/3-2/3+1/2`

`x=1/2`

`3x(x-1/6)-2x(x-1/3)=2/3`

`3x^2 - 1/2 x- 2x^2 + 2/3x = 2/3`

`x^2+1/6 x =2/3`

`x=(-1 \pm \sqrt97)/12`

\(\dfrac{2x+1}{3}-\dfrac{x-1}{2}< 3\)

\(\Leftrightarrow\dfrac{2\left(2x+1\right)-3\left(x-1\right)}{6}< \dfrac{18}{6}\)

\(\Leftrightarrow2\left(2x+1\right)-3\left(x-1\right)< 18\)

\(\Leftrightarrow4x+2-3x+3< 18\)

\(\Leftrightarrow x< 13\)

Vậy \(S=\left\{x|x< 13\right\}\)

\(8:x^2\)+3 >0

8+\(3^2\)>0

\(3^2\)>8

\(x^2\)>8/3

X>căn 8/3

Đúng ko bạn????

\(2^{x+1}=32\)

\(2^{x+1}=2^5\)

\(\Rightarrow x+1=5\)

\(\Rightarrow x=5-1\)

\(\Rightarrow x=4\)

bn cần ghi rõ đề hơn nha 

2^{x + 1} = 32

2^{x + 1} = 2⁵

=> x + 1 = 5

           x = 5 - 1 

           x = 4

\(a,\dfrac{4}{15}:\dfrac{4}{7}< x< \dfrac{2}{5}\times\dfrac{10}{3}\\ \Leftrightarrow\dfrac{7}{15}< x< \dfrac{4}{3}\\ \Leftrightarrow x=1\)

\(b,\dfrac{3}{5}\times\dfrac{3}{7}+\dfrac{2}{5}\times\dfrac{4}{7}=\dfrac{9}{35}+\dfrac{8}{35}=\dfrac{17}{35}\)

a: \(\frac{4}{15}:\frac47

=>\(\frac{4}{15}\times\frac74

=>\(\frac{7}{15}

b: Cách 1: \(\frac35\times\frac37+\frac25\times\frac47\)

\(=\frac{3\times3+2\times4}{5\times7}=\frac{9+8}{35}=\frac{17}{35}\)

Cách 2:

Ta có: \(\frac35\times\frac37+\frac25\times\frac47\)

\(=\frac15\times\frac17\times\left(3\times3+2\times4\right)\)

\(=\frac{1}{35}\times\left(9+8\right)=\frac{17}{35}\)

(x-1)^2=25 <=> (x-1)^2=5^2 <=>x-1=5 <=> x=6

giải ra luôn đó nha

*= x²- 1²=5²

=>x - 1 = 5

=> x = 5 + 1 =6

(x+1)+(x+2)+(x+3)+.......+(x+99)+(x+100)=5750

(x+x+x+...+x)+(1+2+3+...+100) = 5750

100x+5050 = 5750

100x = 5750-5050

100x = 700

x = 700 : 100

x = 7