Ta có

\(C=\left(x^2+2.x.2y+\left(2y\right)^2\right)-\left(2x+4y\right)+10\)

\(\Rightarrow C=\left(x+2y\right)^2-2\left(x+2y\right)+10\)

\(\Rightarrow C=5^2-2.5+10\)

\(\Rightarrow C=25-10+10=25\)

\(C=x^2+4y^2-2x+10+4xy-4y\)

    \(=\left[x^2+2.x.2y+\left(2y\right)^2\right]-\left(2x+4y\right)+10\)

    \(=\left(x+2y\right)^2-2\left(x+2\right)+10\)

    \(=5^2-2.5+10\)

    \(=5^2-10+10\)

    \(=25-10+10\)

    \(=25\)

CHÚC BẠN HỌC TỐT !!!

=25 nha nhớ tích

A=(x^2+4xy+4y^2)-(2x+4y)+10

A=(x+2y)^2-2(x+2y)+1+9

A=(x+2y-1)^2+9

A=(5-1)^2+9=16+9=25

tích đúng mình làm cho

là sao ạk
giải giùm mình với ạk

(x²+4xy+4y²)-(2x+4y)+10=(x+2y)²-2(x+2y)+10=5²-10+10=25 :333

:333 là biểu cảm nhé

​

\(C=x^2+4y^2-2x+10+4xy-4y\)

\(=\left(x^2+4xy+4y^2\right)-2\left(x+2y\right)+10\)

\(=5^2-2\cdot5+10=25-10+10=25\)

a: \(A=x\left(x+2\right)+y\left(y-2\right)-2xy\)

\(=x^2+2x+y^2-2y-2xy\)

\(=\left(x^2-2xy+y^2\right)+2\left(x-y\right)\)

\(=\left(x-y\right)^2+2\left(x-y\right)=7^2+2\cdot7=49+14=63\)

\(B=x^3-3xy\left(x-y\right)-y^3-x^2+2xy-y^2\)

\(=x^3-3x^2y+3xy^2-y^3-\left(x^2-2xy+y^2\right)\)

\(=\left(x-y\right)^3-\left(x-y\right)^2\)

\(=7^3-7^2=343-49=294\)

b: \(C=x^2+4y^2-2x+10+4xy-4y\)

\(=x^2+4xy+4y^2-2\left(x+2y\right)+10\)

\(=\left(x+2y\right)^2-2\left(x+2y\right)+10=5^2-2\cdot5+10=25\)

a)  \(A=x^2+2xy+y^2-4x-4y+1\)

\(=\left(x+y\right)^2-4\left(x+y\right)+1\)

\(=3^2-4.3+1=-2\)

b)  \(B=x\left(x+2\right)+y\left(y-2\right)-2xy+37\)

\(=x^2+2x+y^2-2y-2xy+37\)

\(=\left(x-y\right)^2+2\left(x-y\right)+37\)

\(=7^2+2.7+37=100\)

c)  \(C=x^2+4y^2-2x+10+4xy-4y\)

\(=\left(x+2y\right)^2-2\left(x+2y\right)+10\)

\(=5^2-2.5+10=25\)

a) \(A=x^2+2xy+y^2-4x-4v+1\)

\(=\left(x+y\right)^2-4\left(x+y\right)+1\)

\(=3^2-4.3+1=-2\)

\(A=x^2+4y^2-2x+10+4xy-4y=\left(x^2+4xy+4y^2\right)-\left(2x+4y\right)+10=\left(x+2y\right)^2-2\left(x+2y\right)+10=5^2-2\cdot5+10=25-10+10=25\)