Dãy \(1;4;7;10;13;...;451;454;454\)

Có số số hạng là : \(\left(454-1\right):3+1=152\)

Mà gộp thành các cặp nên có số cặp là \(152:2=76\)

Bài này mk có giải rùi mà 

A=3.(1/1.2+1/2.3+1/3.4+.....+1/399.400)

A=3.(1/1-1/2+1/2-1/3+......+1/399-1/400)

A=3.(1-1/400)

A=3.399/400

A=1197/400

A=3.(1/1.2+1/2.3+1/3.4+.....+1/399.400)

A=3.(1/1-1/2+1/2-1/3+......+1/399-1/400)

A=3.(1-1/400)

A=3.399/400

A=1197/400

Bài 1: Tính nhanh:

A = 3/1*2 + 3/2*3 + 3/3*4 + ... + 3/399*400

=>3A = 1/1*2 + 1/2*3 + 1/3*4 + ... + 1/399*400

    3A = 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/399 - 1/400

    3A = 1 - 1/400

      3A = 400/400 - 1/400

      3A = 399/400

        A = 399/400 : 3

        A = 399/400 . 1/3

        A = 133/400.

Có gì ko hiểu bn ib mk nha.^^

\(A=\frac{3}{1.2}+\frac{3}{2.3}+\frac{3}{3.4}+...+\frac{3}{399.400}\)

\(A=3.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{399.400}\right)\)

\(A=3.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{399}-\frac{1}{400}\right)\)

\(A=3.\left(1-\frac{1}{400}\right)\)

\(A=3.\frac{399}{400}\)

\(A=\frac{1197}{400}\)

\(B=\frac{5}{1.2}+\frac{5}{2.3}+\frac{5}{3.4}+...+\frac{5}{399.400}\)

\(B=5.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{399.400}\right)\)

\(B=5.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{399}-\frac{1}{400}\right)\)

\(B=5.\left(1-\frac{1}{400}\right)\)

\(B=5.\frac{399}{400}\)

\(B=\frac{399}{80}\)

\(C=\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+...+\frac{2}{149.151}\)

\(C=\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+...+\frac{1}{149}-\frac{1}{151}\)

\(C=\frac{1}{5}-\frac{1}{151}\)

\(C=\frac{146}{755}\)

\(D=\frac{3}{5.7}+\frac{3}{7.9}+\frac{3}{9.11}+...+\frac{3}{149.151}\)

\(D=\frac{3}{2}.\left(\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+...+\frac{2}{149.151}\right)\)

\(D=\frac{3}{2}.\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+...+\frac{1}{149}-\frac{1}{151}\right)\)

\(D=\frac{3}{2}.\left(\frac{1}{5}-\frac{1}{151}\right)\)

\(D=\frac{3}{2}.\frac{146}{755}\)

\(D=\frac{219}{755}\)

\(E=\frac{11}{1.3}+\frac{11}{3.5}+\frac{11}{5.7}+...+\frac{11}{99.101}\)

\(E=\frac{11}{2}.\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{99.101}\right)\)

\(E=\frac{11}{2}.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{99}-\frac{1}{101}\right)\)

\(E=\frac{11}{2}.\left(1-\frac{1}{101}\right)\)

\(E=\frac{11}{2}.\frac{100}{101}\)

\(E=\frac{550}{101}\)

_Chúc bạn học tốt_

a,[(79+1).27]/2=1080

b,[(155+15).71]/2=6035

c,[(115+15).11]/2=715

d,[(24+126).103]/2=7725

tick nha

\(\frac{a}{b}=\frac{1}{51}+\frac{1}{52}+\frac{1}{53}+...+\frac{1}{100}\)

\(\frac{a}{b}=\left(\frac{1}{51}+\frac{1}{100}\right)+\left(\frac{1}{52}+\frac{1}{99}\right)+...+\left(\frac{1}{75}+\frac{1}{76}\right)\)

\(\frac{a}{b}=\frac{151}{51.100}+\frac{151}{50.99}+...+\frac{151}{75.76}\)

Chọn mẫu chung = 51.52.53...100

Gọi các thừa số phụ lần lượt là: k₁; k₂; ...; k₂₅

=> \(\frac{a}{b}=\frac{151.\left(k_1+k_2+...+k_{25}\right)}{51.52...100}\)

Do 151 là số nguyên tố mà tích 51.52...100 không chứa thừa số 151 => 51.52....100 không chia hết cho 151

=> đến khi phân số a/b tối giản thì a vẫn chia hết cho 151 (đpcm)

Mik rút gọn cho bn nha

\(\frac{a}{b}=\frac{1}{51.100}+\frac{1}{52.99}+..........+\frac{1}{100.51}\)

\(151.\frac{a}{b}=\frac{1}{51}+\frac{1}{100}+\frac{1}{52}+\frac{1}{99}+......+\frac{1}{100}+\frac{1}{51}\)

\(\Rightarrow\left(151.\frac{a}{b}\right):2=\frac{1}{51}+\frac{1}{52}+\frac{1}{53}+.........+\frac{1}{100}\)

\(\Rightarrow\frac{a}{b}=\frac{2}{151}.\left(\frac{1}{51}+\frac{1}{52}+\frac{1}{53}+.........+\frac{1}{100}\right)\)

Chúc bn hok tốt

a/ \(5^{98}\left(1+5+5^2\right)=5^{98}.31\) chia hết cho 31

b/ \(7^{150}\left(7^2-1+7\right)=7^{150}.55\) chia hết cho 55

Thanks bạn nhiều

-225 nha bn