đáp án là:−12800

a: 86+357+14

=100+357

=457

b: \(3\cdot52-16:22\)

\(=156-\dfrac{8}{11}=\dfrac{1708}{11}\)

a: =(34-34)+(100-100)=0

b: =-3000-2000=-5000

a, 10 . 27 - 27 : 9 

= 270 - 3

= 263

b, 7² . 33 + 7² . 67

= 7² ( 33 + 67 )

= 7² . 100

= 49 . 100

= 4900

c, 490 - [ ( 128 + 22 ) : 3 . 2² ] - 7 

= 490 - ( 150 : 3 . 4 ) - 7 

= 490 - ( 50 . 4 ) - 7 

= 490 - 200 - 7

= 290 - 7

= 283

27 x 31 + 31 x 73

= 31 x ( 27 x 73 )

= 31 x 100

= 3100

16 x 98 + 16 x 2

= 16 x ( 98 + 2 )

= 16 x 100

= 1600

31*(27+73)=31*100=3100

16*(98+2)=16*100=1600

k mik

Bài 1:

a: \(A=15\cdot31\cdot2+5\cdot27\cdot6+10\cdot42\cdot3\)

\(=30\cdot31+30\cdot27+30\cdot42\)

\(=30\left(31+27+42\right)\)

\(=30\cdot100=3000\)

b: \(B=3\cdot5^2+160:\left(9-5\right)^2\)

\(=3\cdot25+160:4^2\)

=75+160:16

=75+10

=85

c: \(C=10^3\cdot\left\lbrace540-\left\lbrack6^3+\left(5\cdot4^2+104\right)\right\rbrack\right\rbrace\)

\(=1000\cdot\left\lbrace540-\left\lbrack216+5\cdot16+104\right\rbrack\right\rbrace\)

=1000{540-[216+80+104]

=1000*{540-400}

=1000*140

=140000

a: \(17\cdot85+15\cdot17-120\)

\(=17\left(85+15\right)-120\)

=1700-120

=1580

b: \(2^3\cdot17-2^3\cdot14\)

\(=2^3\left(17-14\right)\)

\(=8\cdot3=24\)

c: \(20-\left\lbrack30-\frac{\left(5-1\right)^2}{2}\right\rbrack\)

\(=20-30+\frac{4^2}{2}\)

\(=-10+\frac{16}{2}=-10+8=-2\)

d: \(80-\left(4\cdot5^2-3\cdot2^2\right)\)

\(=80-\left(4\cdot25-3\cdot4\right)\)

=80-100+12

=92-100

=-8

e: \(27\cdot77+24\cdot27-27\)

\(=27\left(77+24-1\right)\)

\(=27\cdot100=2700\)

f: \(174:\left\lbrace2\cdot\left\lbrack36+\left(4^2-23\right)\right\rbrack\right\rbrace\)

\(=\frac{174}{2\cdot\left(36+16-23\right)}=\frac{87}{52-23}=\frac{87}{29}=3\)

Có sai đề ko v ạ :)?

ko sai nha

BÀi 1:

a: (-243+345)-(257+(-55)-129)

=-243+345-257+55+129

=(-243-257)+(345+55)+129

=-500+400+129

=-100+129

=29

b: \(\left(-2\right)^3-45:\left(-3\right)^2-\left(-2019\right)^0\cdot\left(-1\right)^{2019}\)

\(=-8-\frac{45}{9}-1\cdot\left(-1\right)\)

=-8-5+1

=-13+1

=-12

c: \(\left\lbrack27\cdot\left(-67\right)+33\cdot\left(-27\right)\right\rbrack:\left(-30\right)\)

\(=\frac{-27\left(67+33\right)}{-30}\)

\(=\frac{9}{10}\cdot100=90\)

d: \(\left(1^2+2^2+\cdots+100^2\right)\left(3^4-9^2\right)\)

\(=\left(1^2+2^2+\cdots+100^2\right)\left(81-81\right)\)

=0

e: \(53\cdot47+53^2-2021^0\)

\(=53\left(53+47\right)-1\)

=5300-1

=5299

i: 38+(-21)+(-58)+(-6)

=(38-58)+(-21-6)

=-20-27

=-47

h: (2020+27)-[2020+(-73)]-129

=2020+27-2020+73-129

=100-129

=-29