a: \(5x^2\left(3x^3-2x^2+x+2\right)\)

\(=15x^5-10x^4+5x^3+10x^2\)

b: \(3x^4\left(-2x^3+5x^2-\dfrac{2}{3}x+\dfrac{1}{3}\right)\)

\(=-6x^7+15x^6-2x^5+x^4\)

Giải:

A=5/9+2/15-6/9

   =(5/9-6/9)+2/15

   = -1/9 + 2/15

   = 1/45

B=2/7-3/8+4/7+1/7-5/8+5/15

   = (2/7+4/7+1/7) + (-3/8-5/8) +1/3

   = 1+ (-1) +1/3

   =1/3

C=3/5+1/15+1/57+1/3-2/9-3/4-1/36

   =9/15+1/15+1/57+19/57-8/36-27/36-1/36

   =(9/15+1/15)+(1/57+19/57)+(-8/36-27/36-1/36)

   =2/3+20/57+(-1)

   =58/57+(-1)

   =1/57

D=1/1.2+1/2.3+1/3.4+...+1/99.100

   =1/1-1/2+1/2-1/3+1/3-1/4+...+1/99-1/100

   =1/1-1/100

   =99/100

Câu E mình ko biết làm nhé!

=26/15=1,733333333

ủa có mẫu r thì bn dựa vào mẫu mà lm

đợi mik lm cho

a: \(A=\dfrac{5}{7}-\dfrac{2}{7}+\dfrac{8}{11}+\dfrac{3}{11}+\dfrac{1}{2}=\dfrac{3}{7}+\dfrac{1}{2}+1=\dfrac{6+7+14}{14}=\dfrac{27}{14}\)

b: \(B=\dfrac{11}{17}+\dfrac{6}{17}-\dfrac{8}{19}-\dfrac{30}{19}+\dfrac{-3}{4}=1-2-\dfrac{3}{4}=-1-\dfrac{3}{4}=-\dfrac{7}{4}\)

c: \(C=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{49}-\dfrac{1}{50}=\dfrac{49}{50}\)

Bài 1:

a: \(\frac{5\times7}{15}=\frac{35}{15}=\frac73\)

b: \(8:\frac{16}{23}=8\times\frac{23}{16}=\frac{8}{16}\times23=23\times\frac12=\frac{23}{2}\)

c: \(\frac{8}{15}:5=\frac{8}{15\times5}=\frac{8}{75}\)

d: \(\frac{15}{19}\times3=\frac{15\times3}{19}=\frac{45}{19}\)

Bài 2:

a: \(3\times\frac49+\frac23-\frac{7}{18}\)

\(=\frac43+\frac23-\frac{7}{18}\)

\(=\frac63-\frac{7}{18}=2-\frac{7}{18}=\frac{36}{18}-\frac{7}{18}=\frac{29}{18}\)

b: \(\frac{7}{10}\times\frac23-\frac14=\frac{14}{30}-\frac14=\frac{28}{60}-\frac{15}{60}=\frac{28-15}{60}=\frac{13}{60}\)

c: \(\frac98-\frac78:\frac56=\frac98-\frac78\times\frac65\)

\(=\frac98-\frac{42}{40}=\frac{45}{40}-\frac{42}{40}=\frac{3}{40}\)

d: \(\frac23+\frac12:\frac32-\frac{11}{24}\)

\(=\frac23+\frac12\times\frac23-\frac{11}{24}\)

\(=\frac23+\frac13-\frac{11}{24}=1-\frac{11}{24}=\frac{13}{24}\)

Bài 3:

Độ dài đáy tương ứng với chiều cao là: \(\frac35\times2=\frac65\left(m\right)\)

Chu vi hình bình hành là:

\(\left(\frac65+\frac45\right)\times2=\frac{10}{5}\times2=2\times2=4\left(m\right)\)

Diện tích bình hành là;

\(\frac65\times\frac35=\frac{18}{25}\left(m^2\right)\)

Ta có: \(\frac{5-4}{2\times3}+\frac{6-5}{3\times4}+\frac{8-7}{4\times5}+\frac{9-8}{5\times6}\)

\(=\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+\frac{1}{5\times6}\)

\(=\frac12-\frac13+\frac13-\frac14+\frac14-\frac15+\frac15-\frac16=\frac12-\frac16=\frac13\)

=(24/100+60/100+76/100+25/100).(26/7+9/7)
=37/20.5
=37/4
k cho mình nha

à quên đề bài là " TÍNH "