0,25 * 0,125 * 2011/2012 * 8 * 4 = ( 0,25 * 4 ) * ( 0,125 * 8 ) * 2011/2012 = 2011/2012

\(\frac{1}{2}:0,5-\frac{1}{4}:0,25+\frac{1}{8}:0,125-\frac{1}{10}:0,1\)

\(=\frac{1}{2}\times2-\frac{1}{4}\times4+\frac{1}{8}\times8-\frac{1}{10}\times10\)

\(=1-1+1-1\)

\(=0\)

\(1,\\ a,=\left(\dfrac{1}{4}\right)^3\cdot32=\dfrac{1}{64}\cdot32=\dfrac{1}{2}\\ b,=\left(\dfrac{1}{8}\right)^3\cdot512=\dfrac{1}{512}\cdot512=1\\ c,=\dfrac{2^6\cdot2^{10}}{2^{20}}=\dfrac{1}{2^4}=\dfrac{1}{16}\\ d,=\dfrac{3^{44}\cdot3^{17}}{3^{30}\cdot3^{30}}=3\\ 2,\\ a,A=\left|x-\dfrac{3}{4}\right|\ge0\\ A_{min}=0\Leftrightarrow x=\dfrac{3}{4}\\ b,B=1,5+\left|2-x\right|\ge1,5\\ A_{min}=1,5\Leftrightarrow x=2\\ c,A=\left|2x-\dfrac{1}{3}\right|+107\ge107\\ A_{min}=107\Leftrightarrow2x=\dfrac{1}{3}\Leftrightarrow x=\dfrac{1}{6}\)

\(d,M=5\left|1-4x\right|-1\ge-1\\ M_{min}=-1\Leftrightarrow4x=1\Leftrightarrow x=\dfrac{1}{4}\\ 3,\\ a,C=-\left|x-2\right|\le0\\ C_{max}=0\Leftrightarrow x=2\\ b,D=1-\left|2x-3\right|\le1\\ D_{max}=1\Leftrightarrow x=\dfrac{3}{2}\\ c,D=-\left|x+\dfrac{5}{2}\right|\le0\\ D_{max}=0\Leftrightarrow x=-\dfrac{5}{2}\)

1/2:0,5 - 1/4 ; 0,25 + 1/8 : 0,125 - 1/10 ; 0,1

= 0,5 : 0,5 - 0,25 : 0,25 + 0,125 : 0,125 - 0,1 : 0,1

= 1 - 1 + 1 - 1

= 0 + 1 - 1

= 1 - 1

= 0

Lời giải:
$=\frac{1}{2}\times 2-\frac{1}{4}\times 4+\frac{1}{8}\times 8-\frac{1}{10}\times 10$

$=1-1+1-1=0$

=5/27-5/27+7/17+7/17+1/4

=14/17+1/4

=56/68+17/68

=73/68

Ta có: \(19,8:0,2\times44,44\times2\times13,2:0,25\)

\(=19,8\times5\times44,44\times2\times13,2\times4\)

\(=19,8\times10\times44,4\times13,2\times4=198\times4\times13,2\times44,4\)

Ta có: \(3,3\times88,88:0,5\times6,6:0,125:0,2\)

\(=3,3\times88,88\times2\times6,6\times8\times5\)

\(=3,3\times8\times10\times6,6\times88,88=3,3\times8\times66\times88,8\)

Ta có: \(\frac{19,8:0,2\times44,44\times2\times13,2:0,25}{3,3\times88,88:0,5\times6,6:0,125:0,2}\)

\(=\frac{198\times4\times13,2\times44,4}{3,3\times8\times66\times88,8}=\frac{44.4}{88.8}\times\frac{13.2}{3.3}\times\frac{198}{66}\times\frac48\)

\(=\frac12\times4\times\frac12\times3=3\)

Ta có : A = 0.25 . 12 : 0,5 - ( 5,1 - 10,2 . 0,5 ) : 0,125 

               = 1/4 . 12 .2 - ( 51/10 - 51/5 . 1/2 ) . 8

               = 6 - ( 51/10 - 51/10 ) .8

                = 6 - 0 .8

               = 6

Vậy A = 6

A = 0,25*12:0,5-(5,1-10,2*0,5):0,125

A = 6