Tính nhanh :
1978×1979+1980×21+1958
Mong mọi người giúp !
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Ta có: \(1978\times1979+21\times1980+1958\)
\(=1978\times\left(1978+1\right)+21\times\left(1978+2\right)+1958\)
\(=1978\times1978+1978+21\times1978+42+1958\)
=1978x1978+21x1978+1978+42+1958
=1978x(1978+21)+1978+2000
=1978x1999+3978
=(1979-1)x(1979+20)+3978
=1979x1979+19x1979-20+3978
=1979x1979+19x1979+3958
=1979x(1979+19+2)
=1979x2000
Ta có: 1980x1979-1978x1979
=1979x(1980-1978)=1979x2
Ta có: \(\frac{1978\times1979+21\times1980+1958}{1980\times1979-1978\times1979}\)
\(=\frac{1979\times2000}{1979\times2}=\frac{2000}{2}=1000\)
cọc a ko bik làm :)))
b) 1980 x 1979 - 1978 x 1979
= ( 1980 - 1978 ) x 1979
= 2 x 1979
= 3958
Chúc bạn hok tốt!~~~
b) 1980 . 1979 - 1978 . 1979
= 1979 ( 1980 - 1978 )
=1979 . 2
= 3958
=))
1000 đó bạn ơi chuẩn 10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000%luôn đó bạn
a ) ( 1978 x 1979 + 1980 x 21 + 1958 ) / ( 1980 x 1979 - 1978 x 1979 ) = 1978 x 1979 + 1980 / 1979 . ( 1980 - 1978 )
= 0/1979
\(\frac{1978\cdot1979+1980\cdot21+1958}{1980\cdot1979-1978\cdot1979}=\frac{1978\cdot1979+\left(1979+1\right)\cdot21+1958}{1979\cdot\left(1980-1978\right)}\)
\(=\frac{1978\cdot1979+1979\cdot21+21+1958}{1979\cdot2}=\frac{1979\cdot\left(1978+21+1\right)}{1979\cdot2}=\frac{2000}{2}=1000\)
= 3958000