a: B(6)={6;12;18;24;...}

B(9)={9;18;27;...}

B(12)={12;24;36;...}

Ư(30)={1;-1;2;-2;3;-3;5;-5;6;-6;10;-10;15;-15;30;-30}

Ư(45)={1;-1;3;-3;5;-5;9;-9;15;-15;45;-45}

Ư(60)={1;-1;2;-2;3;-3;4;-4;5;-5;6;-6;10;-10;12;-12;15;-15;20;-20;30;-30;60;-60}

b: \(36=2^2\cdot3^2;48=2^4\cdot3\)

=>ƯCLN(36;48)=\(2^2\cdot3=12\)

\(24=2^3\cdot3;28=2^2\cdot7;36=2^2\cdot3^2\)

=>ƯCLN(24;28;36)=\(2^2=4\)

c: \(6=3\cdot2;8=2^3\)

=>BCNN(6;8)=\(2^3\cdot3=8\cdot3=24\)

\(8=2^3;9=3^2;72=2^3\cdot3^2\)

=>BCNN(8;9;72)=\(2^3\cdot3^2=72\)

d: \(15=3\cdot5;54=3^3\cdot2\)

=>BCNN(15;54)=\(3^3\cdot2\cdot5=27\cdot10=270\)

=>BC(15;54)={270;540;810;1080;...}

=>Các bội chung nhỏ hơn 1000 của 15 và 54 là 270;540;810

a) ƯCLN(21, 98) = 7

 BCNN(21, 98) = 294

b) ƯCLN(36, 54) =  18

 BCNN(36, 54) = 108

a) Ta có:
21 = 3 . 7
98 = 2 . 7^2
Do đó:
ƯCLN(21, 98) = 7.
BCNN(21, 98) = 3 . 2 . 7^2= 294.

b) Ta có:
36 = 2^2 . 3^2
54 = 2 . 33
Do đó:
ƯCLN(36, 54) = 2 . 3^2 = 18.
BCNN(36, 54) = 2^2 . 33 = 108.

a) Ta có: 21 = 3.7;  98 = 2.7²

=> ƯCLN(21, 98) = 7 ; BCNN(21, 98) = 2.3.7² = 294

b) Ta có: 36 = 2².3², 54 = 2.3³

ƯCLN(36, 54) = 2.3² = 18; BCNN(36, 54) = 2².3³ = 108.

a) Ta có:

\(21=3\cdot7\\98=2\cdot7^2\)

Khi đó, ta được: 

\( UCLN(21,98)=7\)

\(BCNN(21,98)=2\cdot3\cdot7^2=294\)

b) Ta có:

\(36=2^2\cdot3^2\\54=2\cdot3^3\)

Khi đó, ta được:

\(UCLN\left(36,54\right)=2\cdot3^2=18\)

\(BCNN\left(36,54\right)=2^2\cdot3^3=108\)

\(36=2^2\cdot3^2\)

\(48=3\cdot2^4\)

=>\(ƯCLN\left(36;48\right)=2^2\cdot3=12\)

\(BCNN\left(36;48\right)=2^4\cdot3^2=16\cdot9=144\)

\(36=2^2.3^2\)

\(48=2^4.3\)

\(ƯCLN=2^2.3=12\)

\(BCNN=2^4.3^2=144\)

\(18=2.3^2\)

\(45=3^2.5\)

\(54=2.3^3\)

\(ƯCLN=3^2=9\)

\(BCNN=2.3^3.5=270\)

15=3.5

36=2².3²

60=2².3.5

⇒ƯCLN(15,36,60)=3

⇒BCNN(15,36,60)=2².3².5=180

ai gíui mik đi

15=3.5

36=2².3²

60=2².3.5

⇒ƯCLN(15,36,60)=3

⇒BCNN(15,36,60)=2².3².5=180

UCLN=3

BCNN=180