câu d là (-15).(-8).125 nha mn

=-30

=-33

=600

=15000

a) \(=300\)

b) \(=374\)

c) \(=4747\)

d) \(=180000\)

a)300

b)374

gõ latex đi dễ nhầm phân số 

c,

\(\dfrac{x^2}{2x-10}+\dfrac{25-10x}{2x-10}\\ =\dfrac{x^2-10x+5^2}{2\left(x-5\right)}=\dfrac{\left(x-5\right)\left(x-5\right)}{2\left(x-5\right)}\\ =\dfrac{x-5}{2}\)

d,

\(=\dfrac{2x}{x\left(x+2\right)}-\dfrac{8}{\left(x-2\right)\left(x+2\right)}+\dfrac{2}{x-2}\)

\(=\dfrac{2x^2-4x}{x\left(x-2\right)\left(x+2\right)}-\dfrac{8x}{x\left(x-2\right)\left(x+2\right)}+\dfrac{2x^2+4x}{x\left(x-2\right)\left(x+2\right)}\)

\(=\dfrac{2x^2-4x-8x+2x^2+4x}{x\left(x-2\right)\left(x+2\right)}=\dfrac{4x^2-8x}{x\left(x-2\right)\left(x+2\right)}\)

\(=\dfrac{4x\left(x-2\right)}{x\left(x-2\right)\left(x+2\right)}=\dfrac{4x}{x\left(x+2\right)}\)

a) \(log_3\sqrt[3]{3}=\dfrac{1}{2}\)

b) \(log_{\dfrac{1}{2}}8=-3\)

c) \(\left(\dfrac{1}{25}\right)^{log_54}=\dfrac{1}{16}\)

a: \(=3^2+\left(3^4\right)^{-0.75}-5^{2\cdot0.5}\)

\(=9-5+3^{-3}=4+\dfrac{1}{27}=\dfrac{109}{27}\)

b: \(=2^{4-6\sqrt{7}}\cdot2^{6\sqrt{7}}=2^{4-6\sqrt{7}+6\sqrt{7}}=2^4=16\)

\(\Leftrightarrow A=\frac{2\cdot4}{3\cdot3}\cdot\frac{3\cdot5}{4.4}...\frac{49.51}{50.50}\)

\(\Rightarrow A=\frac{2\cdot4\cdot3\cdot5\cdot...\cdot49.51}{3\cdot3\cdot4\cdot4\cdot5\cdot5\cdot...\cdot50\cdot50}\)

\(\Rightarrow A=\frac{2\cdot51}{3\cdot50}\)

\(\Rightarrow A=\frac{17}{25}\)

17/25

a: =8 năm 15 tháng=9 năm 3 tháng

b: =505 phút-340 phút=165 phút

c: =97,38

d: =3,6

a,9 năm 3 tháng

b,2 giờ 35p

c,97,38

d,3,6

a: \(\frac{\left(-5\right)^{60}\cdot30^5}{15^5\cdot5^{61}}\)

\(=\frac{5^{60}}{5^{61}}\cdot\left(\frac{30}{15}\right)^5\)

\(=\frac{2^5}{5}=\frac{32}{5}\)

b: \(\frac{\left(-3\right)^{10}\cdot15^5}{25^3\cdot\left(-9\right)^7}=\frac{3^{10}\cdot3^5\cdot5^5}{5^6\cdot\left(-1\right)\cdot3^{14}}=\frac{-3^{15}}{3^{14}}\cdot\frac15=-\frac35\)

c: \(4^6\cdot9^5+6^9\cdot120\)

\(=2^{12}\cdot3^{10}+2^9\cdot3^9\cdot2^3\cdot3\cdot5\)

\(=2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5=2^{12}\cdot3^{10}\cdot6=2^{13}\cdot3^{11}\)

\(8^4\cdot3^{12}-6^{11}\)

\(=2^{12}\cdot3^{12}-2^{11}\cdot3^{11}\)

\(=2^{11}\cdot3^{11}\left(2\cdot3-1\right)=2^{11}\cdot3^{11}\cdot5\)

Ta có: \(\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)

\(=\frac{2^{13}\cdot3^{11}}{2^{11}\cdot3^{11}\cdot5}=\frac{2^2}{5}=\frac45\)

d: \(4^2\cdot25^2+32\cdot125\)

\(=2^4\cdot5^4+2^5\cdot5^3\)

\(=2^4\cdot5^3\left(5+2\right)=2^4\cdot5^3\cdot7\)

\(\frac{4^2\cdot25^2+32\cdot125}{2^3\cdot5^2}\)

\(=\frac{2^4\cdot5^3\cdot7}{2^3\cdot5^2}=2\cdot5\cdot7=10\cdot7=70\)