((25.9 - 25.17))(( - 8.80 - 8.10)) ) và  ((48.12 - 48.15))(( - 3.270 - 3.30)) ). hãy so sánh 2 phân số trên

Câu a:

\(\frac{3939-101}{3.2929+505}\)

= \(\frac{101.\left(39-1\right)}{101.\left(3.29+5\right)}\)

= \(\frac{38}{87+5}\)

= \(\frac{38}{92}\)

= \(\frac{19}{46}\)

Câu c:

\(\frac{6.9-2.17}{63.3-119}\)

= \(\frac{2.\left(3.9-17\right)}{7.\left(9.3-17\right)}\)

= \(\frac27\)

Câu 1:

A = \(\frac{25.9-25.17}{-8.80-8.10}\)

A = \(\frac{25.\left(9-17\right)}{-8.10\left(8+1\right)}\)

A = \(\frac{5.5.\left(-8\right)}{-8.10.9}\)

A = \(\frac{5.5.2.4}{2.4.5.2.9}\)

A = \(\frac{5}{18}\)

B = \(\frac{48.12-48.15}{-3.270-3.30}\)

B = \(\frac{48.\left(12-15\right)}{-3.30\left(9+1\right)}\)

B = \(\frac{6.8.\left(-3\right)}{-3.30.10}\)

B = \(\frac{6.2.4.\left(-3\right)}{-3.5.6.2.5}\)

B = \(\frac{4}{25}\) = \(\frac{20}{125}\) < \(\frac{20}{72}\) = \(\frac{5}{18}\)

A > B

Câu 2:

A = \(\frac{2^5.7+2^5}{2^5-2^5.3}\)

A = \(\frac{2^5.\left(7+1\right)}{2^5-2^5.3}\)

A = \(\frac{2^5.8}{2^5.\left(1-3\right)}\)

A = \(\frac{8}{-2}\)

A = -4

B = \(\frac{3^4.5-3^6}{3^4.13+3^4}\)

B = \(\frac{3^4.\left(1-3^2\right)}{3^4.\left(13+1\right)}\)

B = \(\frac{1-9}{14}\)

B = \(\frac{-8}{14}\)

B = \(\frac{-4}{7}\) > - 4

Vậy A < B

\(\dfrac{25.9-25.17}{-8.80-8.10}=\dfrac{-200}{-720}=\dfrac{5}{18}\)

\(\dfrac{48.12-48.15}{-3.270-3.30}=\dfrac{-144}{-900}=\dfrac{4}{25}\)

a, Quy đồng

\(\dfrac{5}{18}=\dfrac{5\times25}{18\times25}=\dfrac{125}{450}\)

\(\dfrac{4}{25}=\dfrac{4.18}{25.18}=\dfrac{72}{450}\)

\(\dfrac{25.9-25.17}{-8.80-8.10}=\dfrac{25.\left(9-17\right)}{-8.\left(80+10\right)}=\dfrac{25.\left(-8\right)}{-8.90}=\dfrac{25}{90}=\dfrac{5}{18}\)

\(\dfrac{48.12-48.15}{-3.270-3.30}=\dfrac{48.\left(12-15\right)}{-3.\left(270+30\right)}=\dfrac{48.\left(-3\right)}{-3.300}=\dfrac{48}{300}=\dfrac{4}{25}\)

MC = 450

\(\dfrac{5}{18}=\dfrac{5.25}{18.25}=\dfrac{125}{450}\)

\(\dfrac{4}{25}=\dfrac{4.18}{25.18}=\dfrac{72}{450}\)

$\frac{25.9-25.17}{-8.80-8.10}=\frac{25.\left(9-17\right)}{-8.\left(80+10\right)}=\frac{25.\left(-8\right)}{-8.90}=\frac{25}{90}=\frac{5}{18}$

$\frac{48.12-48.15}{-3.270-3.30}=\frac{48.\left(12-15\right)}{-3.\left(270+30\right)}=\frac{48.\left(-3\right)}{-3.300}=\frac{48}{}$

a) \(\frac{25.9-25.17}{-8.80-8.10}=\frac{25.\left(9-17\right)}{-8.\left(80+10\right)}=\frac{25.\left(-8\right)}{-8.90}=\frac{5}{18}\)

b) \(\frac{48.12-48.15}{-3.270-3.30}=\frac{48.\left(12-15\right)}{-3.\left(270+30\right)}=\frac{48.\left(-3\right)}{-3.300}=\frac{4}{25}\)

c) \(\frac{2^5.7+2^5}{2^5.5^2-2^5.3}=\frac{2^5.\left(7+1\right)}{2^5.\left(5^2-3\right)}=\frac{2^5.8}{2^5.\left(25-3\right)}=\frac{2^5.8}{2^5.22}=\frac{4}{11}\)

d) \(\frac{3^4.5-3^6}{3^4.13+3^4}=\frac{3^4.\left(5-3^2\right)}{3^4.\left(13+1\right)}=\frac{3^4.\left(5-9\right)}{3^4.14}=\frac{3^4.\left(-4\right)}{3^4.14}=\frac{-2}{7}\)

Nguyễn Lương Bảo Tiên tại sao 

3^4 × 5 - 3^6 lại = 3^4 (5 - 3^2) vậy

phần d ý

a/\(\frac{3939-101}{3.2929+505}=\frac{39.101-101}{8787+505}=\frac{101.\left(39-1\right)}{87.101+5.101}=\frac{101.38}{101.\left(87+5\right)}=\frac{38}{92}\)

\(=\frac{38}{92}\)

b/\(\frac{6.4+6.7}{6.5+12}=\frac{4+1.7}{1.5+2}=\frac{4+7}{5+2}=\frac{11}{7}\)