Tìm x biết
5x+25=125
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\(5x+5x^2=43x^3\\ \Rightarrow43x^3-5x^2-5x=0\\ \Rightarrow x\left(43x^2-5x-5\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=0\\43x^2-5x-5=0\left(1\right)\end{matrix}\right.\\ \Delta\left(1\right)=25+4.5.43=885\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{5+\sqrt{885}}{86}\\x=\dfrac{5-\sqrt{885}}{86}\end{matrix}\right.\)
Bài 10:
a: x-5=-1
=>x=-1+5
=>x=4
b: x+30=-4
=>x=-4-30
=>x=-34
c: x-(-24)=3
=>x+24=3
=>x=3-24
=>x=-21
d: 22-(-x)=12
=>22+x=12
=>x=12-22
=>x=-10
e: (x+5)+(x-9)=x+2
=>x+5+x-9=x+2
=>2x-4=x+2
=>2x-x=4+2
=>x=6
f: (27-x)+(15+x)=x-24
=>x-24=27-x+15+x=42
=>x=42+24
=>x=66
Bài 9:
a: 15-(4-x)=6
=>4-x=15-6=9
=>x=4-9=-5
b: -30+(25-x)=-1
=>-30+25-x=-1
=>-5-x=-1
=>x+5=1
=>x=1-5
=>x=-4
c: x-(12-25)=-8
=>x-(-13)=-8
=>x+13=-8
=>x=-8-13
=>x=-21
d: (x-29)-(17-38)=-9
=>x-29-(-21)=-9
=>x-29+21=-9
=>x-8=-9
=>x=-9+8
=>x=-1
Bài 8:
a: (17-229)+(17-25+229)
=17-229+17-25+229
=34-25
=9
b: (125-679+145)-(125-679)
=125-679+145-125+679
=145
\(x^3\) + 125 + (\(x\) + 5)(\(x\) - 25) = 0
(\(x^3\) + 53) + (\(x\) + 5)(\(x\) - 25) = 0
(\(x\) + 5)(\(x^2\) - 5\(x\) + 25) + (\(x\) + 5)(\(x\) - 25) =0
(\(x\) + 5)(\(x^2\) - 5\(x\) + 25 + \(x\) - 25) = 0
(\(x\) + 5)(\(x^2\) - 4\(x\)) = 0
\(x\)(\(x\) + 5)(\(x\) - 4) = 0
\(\left[{}\begin{matrix}x=0\\x+5=0\\x-4=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=0\\x=-5\\x=4\end{matrix}\right.\)
\(\left(x+5\right)+\left(x+10\right)+...+\left(x+25\right)-125=150\)
\(\Leftrightarrow x+5+x+10+...+x+25-125=150\)
\(\Leftrightarrow5x-50=150\)
\(\Leftrightarrow5x=100\)
\(\Leftrightarrow x=\dfrac{100}{5}=20\)
Vậy \(x=20\)
\(x\times125-x\times25=37800\\ \Rightarrow x\times\left(125-25\right)=37800\\ \Rightarrow x\times100=37800\\ x=378\)
x + x + 25 = 125
ta có : 2x + 25 = 125
2x = 125 - 25
2x = 100
x = 50
k mik nha
x + x + 25 = 125
=>2x+25=125
=>2x=125-25
=>2x=100
=>x=100:2
=>x=50
k nha
5x + 25 = 125
5x = 125 - 25
5x = 100
x = 100 : 5
x = 20
Vậy x = 20
5x + 25 = 125
5x = 125 - 25
5x = 100
x = 20
vậy x = 20