a: 5x-9=5+3x

=>5x-3x=5+9

=>2x=14

=>\(x=\frac{14}{2}=7\)

b: \(2^3+0,5x=1,5\)

=>0,5x+8=1,5

=>0,5x=1,5-8=-6,5

=>\(x=-6,5:0,5=-13\)

c: \(\left(5x+1\right)^2=\frac{36}{49}\)

=>\(\left[\begin{array}{l}5x+1=\frac67\\ 5x+1=-\frac67\end{array}\right.\Rightarrow\left[\begin{array}{l}5x=\frac67-1=\frac17\\ 5x=-\frac67-1=-\frac{13}{7}\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac17:5=\frac{1}{35}\\ x=-\frac{13}{7}:5=-\frac{13}{35}\end{array}\right.\)

d: \(\left(-\frac{3}{81}\right)^{x}=-27\)

=>\(\left(-\frac{1}{27}\right)^{x}=-27\)

=>\(x=-1\)

e: \(2^{x-1}=16\)

=>\(2^{x-1}=2^4\)

=>x-1=4

=>x=4+1=5(nhận)

Bài 1:

\(\dfrac{\left(\dfrac{2}{5}\right)^7\cdot5^7+\left(\dfrac{9}{4}\right)^3:\left(\dfrac{3}{16}\right)^3}{2^7\cdot5^2+512}\)

\(=\dfrac{\left(\dfrac{2}{5}\cdot5\right)^7+\left(\dfrac{9}{4}:\dfrac{3}{16}\right)^3}{2^7\cdot5^2+512}\)

\(=\dfrac{2^7+12^3}{2^7\cdot5^2+512}\)

\(=\dfrac{1856}{3712}\)

\(=0,5\)

Bài 2:

\(\left(5x+1\right)^2=\dfrac{36}{49}\)

\(\Rightarrow5x+1=\dfrac{6}{7}\)

\(\Rightarrow5x=\dfrac{-1}{7}\)

\(\Rightarrow x=\dfrac{-1}{35}\)

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Bài này có cần phải tính nhanh ko vậy bn?
Nếu ko thì lấy máy tính mà tính cũng đc mà

`(5x+1)=36/49`

`<=> 5x = 36/49-1`

`<=> 5x = -13/49`.

`<=> x = -13/245.`

Vậy `x = -13/245`.

`b, x-2/9 = 2/3`.

`<=> x = 2/3 + 2/9`

`<=> x = 8/9`.

Vậy `x = 8/9`.

c: (8x-1)^(2x+1)=5^(2x+1)

=>8x-1=5

=>8x=6

=>x=3/4

d: Sửa đề: (x-3,5)^2+(y-1/10)^4=0

=>x-3,5=0 và y-0,1=0

=>x=3,5 và y=0,1

a) 27^x : 3^x = 9

(27 : 3)^x = 9

9^x = 9¹

x = 1

b) 25 : 5^x =5

5^x = 25 : 5

5^x = 5¹

x = 1

c) 2 : (x + 2)² = \(\dfrac{1}{18}\)

(x + 2)² = 2 : \(\dfrac{1}{18}\)

(x + 2)² = 36

\(\Rightarrow\left[{}\begin{matrix}x+2=6\\x+2=-6\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=4\\x=-8\end{matrix}\right.\)

d) (5x - 1)² = \(\dfrac{36}{49}\)

(5x - 1)² = \(\left(\dfrac{6}{7}\right)^2\)

Bạn làm tiếp nha, mình có việc bận :v

7 x 8 = 56       16 : 2 = 8       36 : 6 = 6       49 : 7 = 7

2 x 5 = 10       72 : 8 = 9       9 x 3 = 27       63 : 7 = 9

6 x 4 = 24       25 : 5 = 5       4 x 8 = 32       7 x 5 = 35

7 x 8 = 56

2 x 5 = 10

6 x 4 = 24

16 : 2 = 8 

72 : 8 = 9

25 : 5 = 5

36 : 6 = 6

9 x 3 = 27

4 x 8 = 32

49 : 7 = 7

63 : 7 = 9

7 x 5 = 35

a: \(\Leftrightarrow7^x\cdot49+7^x\cdot\dfrac{2}{7}=345\)

\(\Leftrightarrow7^x=7\)

hay x=1

c: \(\left(\dfrac{1}{3}-\dfrac{1}{2}\right)^{x-1}=\dfrac{1}{36}\)

\(\Leftrightarrow\left(-\dfrac{1}{6}\right)^{x-1}=\left(-\dfrac{1}{6}\right)^2\)

=>x-1=2

hay x=3

d: \(\dfrac{25}{5^x}=\dfrac{1}{125}\)

\(\Leftrightarrow5^x=5^2\cdot5^3=5^5\)

hay x=5