1. Tính nhanh dùng ( hằng đẳng thức )
a) 10032 - 6 x 1003 +9
b) 9982 +4 x 999
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a: \(\left(a-2b\right)^2-4b^2\)
\(=\left(a-2b\right)^2-\left(2b\right)^2\)
=(a-2b-2b)(a-2b+2b)
=a(a-4b)
b: \(\left(a-b\right)^2-c^2=\left(a-b-c\right)\left(a-b+c\right)\)
c: \(\left(a+b\right)^2-4=\left(a+b\right)^2-2^2=\left(a+b+2\right)\left(a+b-2\right)\)
d: \(\left(a+3b\right)^2-9b^2\)
\(=\left(a+3b\right)^2-\left(3b\right)^2\)
=(a+3b-3b)(a+3b+3b)=a(a+6b)
e: \(\left(x-3\right)^3-27\)
\(=\left(x-3-3\right)\left\lbrack\left(x-3\right)^2+3\left(x-3\right)+9\right\rbrack\)
\(=\left(x-6\right)\left(x^2-6x+9+3x-9+9\right)=\left(x-6\right)\left(x^2-3x+9\right)\)
f: \(\left(x+1\right)^3-125\)
\(=\left(x+1-5\right)\left\lbrack\left(x+1\right)^2+5\left(x+1\right)+25\right\rbrack\)
\(=\left(x-4\right)\left(x^2+2x+1+5x+5+25\right)=\left(x-4\right)\left(x^2+7x+31\right)\)
\(\left(a-x-y\right)^3-\left(a+x-y\right)^3\)
\(=\left[\left(a-x-y\right)-\left(a+x-y\right)\right]\left[\left(a-x-y\right)^2+\left(a-x-y\right)\left(a+x-y\right)+\left(a+x-y\right)^2\right]\)
\(=-2x.\left[a^2+x^2+y^2-2ax+2xy-2ay+\left(a-y\right)^2-x^2+a^2+x^2+y^2+2ax-2xy-2ay\right]\)
\(=-2x\left[a^2+x^2+y^2-2ax+2xy-2ay+a^2-2ay+y^2-x^2+a^2+x^2+y^2+2ax-2xy-2ay\right]\)
\(=-2x\left(3a^2+x^2+3y^2-4ay\right)\)
a) x6 + 1
= (x2)3 + 13
=(x2 +1)(x4 - x2 + 1)
b) x6 - y6
= (x2)3 - (y2)3
=(x2 -y2)(x4 + x2y2 + y4)
= (x-y)(x+y)[ x4 + 2.x2y2 + y4 - x2y2 ]
=(x-y)(x+y) [(x2 +y2)2 - (xy)2 ]
=(x-y)(x+y)(x2 - xy + y2)(x2 + xy + y2)
c) x9 +1
= (x3)3 + 13
=(x3 +1)(x6 - x3 -1)
= (x+1)(x2 - x +1)(x6 - x3-1)
1) \(x^6+1\)
\(=x^6+x^4-x^4+x^2-x^2+1\)
\(=\left(x^6-x^4+x^2\right)+\left(x^4-x^2+1\right)\)
\(=x^2\left(x^4-x^2+1\right)+\left(x^4-x^2+1\right)\)
\(=\left(x^2+1\right)\left(x^4-x^2+1\right)\)
2) \(x^6-y^6\)
\(=\left(x^3+y^3\right)\left(x^3-y^3\right)\)
\(=\left(x+y\right)\left(x^2-xy+y^2\right)\left(x-y\right)\left(x^2+xy+y^2\right)\)
a) = 1003 2 - 2.3.1003 + 32
= (1003 - 3)2 = 10002 = 1000000
b) = 9982 + 4. (998 + 1)
= 9982 + 2.2.998 + 22
= (998 + 2)2 = 10002 = 1000000
a) = 10032 - 2.3.1003 + 32
= (1003 - 3)2 = 10002 = 1000000
b) = 9982 + 4. (998 + 1)
= 9982 + 2.2.998 + 22
= (998 + 2)2 = 10002 = 1000000