TÌM x biết (14 - x : 6 ) x 7 = 84
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
( 14 - x : 6 ) x 7 = 84
14 - x : 6 = 84 : 7
14 - x : 6 = 12
x : 6 = 14 - 12
x : 6 = 2
x = 2 x 6
x = 12
( 14 - x : 6 ) : 7 = 84
( 14 - x : 6 ) = 84 x 7 =588
x : 6 = 14 - 588 = -574
x = - 574 x 6
x = - 3444
14 - x :6 = 84 nhân 7
14 - x : 6 = 588
x : 6 mà bằng 588 suy ra x phải lớn hơn 588 6 lần, suy ra x cũng lớn hơn 14
Vậy đề cho 14-x suy ra x ko có kết quả thỏa mãn đề bài
a, -14 - 7 + x = -12
\(\Leftrightarrow-21+x=-12\)
\(\Leftrightarrow x=-12+21\)
\(\Leftrightarrow x=9\)
b, \(x+\left(-15\right)-\left(-6\right)=11\)
\(\Leftrightarrow x-15+6=11\)
\(\Leftrightarrow x-\left(15-6\right)=11\)
\(\Leftrightarrow x-9=11\)
\(\Leftrightarrow x=11+9\)
\(\Leftrightarrow x=20\)
c, \(x-\left[18+\left(-7\right)\right]=15\)
\(\Leftrightarrow x-\left(18-7\right)=15\)
\(\Leftrightarrow x-11=15\)
\(\Leftrightarrow x=15+11\)
\(\Leftrightarrow x=26\)
d, \(-84-\left(-18-6\right)=x+\left(-20\right)\)
\(\Leftrightarrow-84-\left(-24\right)=x+\left(-20\right)\)
\(\Leftrightarrow-84+24=x+\left(-20\right)\)
\(\Leftrightarrow-60=x+\left(-20\right)\)
\(\Leftrightarrow x=-20+60\)
\(\Leftrightarrow x=40\)
a,-14-7+x=-12 b,x+(-15)-(-6)=11 c,x-[18+(-7)]=15 d,-84-(-18-6)=x+(-20)
-21+x=-12 x+(-15)+6=11 x-11=15 -84-(-12)+x+(-20)
x=-12-(-21) x+(-9)=11 x=15+11 x+(-20)=-84+12
x=-12+21 x=11-(-9) x=26 x+(-20)=-62
x=9 x=11+9 x=-62-(-20)
x=20 x=-62+20
x=-42
a)0,12.X-2=4
=>0,12.X=4+2
=>0,12.X=6
=>X=6:0,12
=>X=50
b)231-(X-6)=1339:13
=>231-(X-6)=103
=>X-6=231-103
=>X-6=128
=>X=128+6
=>X=134
c)7,99.X+X.2+X:100=7,9
=>X.(7,99+2+1/100)=7,9
=>X.10=7,9
=>X=7,9:10
=>X=0,79
d)(14-X:6).7=84
=>14-X:6=84:7
=>14-X:6=12
=>X:6=14-12
=>X:6=2
=>X=2.6
=>X=12
a: Ta có: \(150=5^2\cdot2\cdot3;84=2^2\cdot3\cdot7;30=2\cdot3\cdot5\)
Do đó: ƯCLN(150;84;30)\(=2\cdot3=6\)
150⋮x; 84⋮x; 30⋮x
=>x∈ƯC(150;84;30)
=>x∈Ư(6)
mà x<16
nên x∈{1;-1;2;-2;3;-3;6;-6}
b: \(15=3\cdot5;14=2\cdot7;20=2^2\cdot5\)
Do đó: BCNN(15;14;20)\(=2^2\cdot3\cdot5\cdot7=4\cdot3\cdot5\cdot7=12\cdot35=420\)
x⋮15; x⋮14; x⋮20
=>x∈BC(15;14;20)
=>x∈B(420)
mà 400<=x<=1200
nên x∈{420;840}
c: 9⋮x+1
=>x+1∈{1;-1;3;-3;9;-9}
=>x∈{0;-2;2;-4;8;-10}
d: 2x+7⋮x-2
=>2x-4+11⋮x-2
=>11⋮x-2
=>x-2∈{1;-1;11;-11}
=>x∈{3;1;13;-9}
a: Ta có: \(150=5^2\cdot2\cdot3;84=2^2\cdot3\cdot7;30=2\cdot3\cdot5\)
Do đó: ƯCLN(150;84;30)\(=2\cdot3=6\)
150⋮x; 84⋮x; 30⋮x
=>x∈ƯC(150;84;30)
=>x∈Ư(6)
mà x<16
nên x∈{1;-1;2;-2;3;-3;6;-6}
b: \(15=3\cdot5;14=2\cdot7;20=2^2\cdot5\)
Do đó: BCNN(15;14;20)\(=2^2\cdot3\cdot5\cdot7=4\cdot3\cdot5\cdot7=12\cdot35=420\)
x⋮15; x⋮14; x⋮20
=>x∈BC(15;14;20)
=>x∈B(420)
mà 400<=x<=1200
nên x∈{420;840}
c: 9⋮x+1
=>x+1∈{1;-1;3;-3;9;-9}
=>x∈{0;-2;2;-4;8;-10}
d: 2x+7⋮x-2
=>2x-4+11⋮x-2
=>11⋮x-2
=>x-2∈{1;-1;11;-11}
=>x∈{3;1;13;-9}
( 14 - x : 6 ) x 7 = 84
14 - x : 6 = 84 : 7
14 - x : 6 = 12
x : 6 = 14 - 12
x : 6 = 2
x = 2 x 6
x = 12
( 14 - x : 6 ) x 7 = 84
14 - x : 6 = 84 : 7
14 - x : 6 = 12
x : 6 = 14 - 12
x : 6 = 2
x = 2 x 6
x = 12