Tìm x:
a) x+15=105
b) 12:x+33=39
c) (x+249):3=197
d) x.98:5=29988
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1,
a,\(2020-\left(249+2020\right)+\left(249-573\right)\)
\(=2020-249-2020+249-573\)
\(=-573\)
b,\(\left|-257\right|+\left(-3\right)^0-\left(18+257\right)\)
\(=257+1-18-257\)
\(=1-18=-17\)
\(c,25.\left(85-47\right)-85.\left(47+25\right)\)
\(=25.85-25.47-47.85+85.25\)
\(=85.\left(25-47+25\right)-25.47\)
\(=85.3-25.47\)
\(=-920\)
2,
\(a,15-5.\left(x+2\right)=-30\)
\(=>5.\left(x+2\right)=15+30=45\)
\(=>x+2=\frac{45}{5}=9\)
\(=>x=7\)
\(b,\left(x+2\right)^2+5=105\)
\(=>\left(x+2\right)^2=100\)
\(=>\left(x+2\right)^2=10^2\)
\(=>x+2=10\)
\(=>x=8\)
\(c,\left|2x-5\right|-\left(-6\right)=11\)
\(=>\left|2x-5\right|=11-6=5\)
\(=>\orbr{\begin{cases}2x-5=5\\2x-5=-5\end{cases}}\)
\(=>\orbr{\begin{cases}2x=5-5=0\\2x=-5+5=0\end{cases}=>x=0}\)
Bài 2:
a: =>x-35=-23
=>x=12
b: =>|x-8|=13
=>x-8=13 hoặc x-8=-13
=>x=21 hoặc x=-5
Bài 1:
a: =42-98-42+12-12=-98
b: =10x4x3x(-25)=40x(-25)x3=-1000x3=-3000
a) 21 - ( 29 + x ) = - 12
= 21 - 29 - x = -12
= -8 - x = -12
-> -x = -12 + 8 = -4
=> x = -(-4) = 4.
b) 14 - ( x - 17 ) = - 31
= 14 - x + 17 = -31
= - x + 31 = -31
-> -x = -31 - 31= -62
=> x = -(-62) = 62.
c) 3 . ( x - 8 ) + 15 = 105
= 3x - 24 + 15 = 105
= 3x - 9 = 105
= 3x = 114
-> x = 38.
d) 2 . ( x + 4 ) - 16 = 98 + x
= 2x + 8 - 16 = 98 + x
= 2x - 8 = 98 + x
= 2x - x = 98 + 8
-> x = 106
Bài 15:
a: 2x+x=45
=>3x=45
=>\(x=\frac{45}{3}=15\)
b: 2x+7x=918
=>\(x\cdot\left(7+2\right)=918\)
=>9x=918
=>\(x=\frac{918}{9}=102\)
c: 2x+3x=60+5
=>5x=65
=>\(x=\frac{65}{5}=13\)
d: \(11x+22x=33\cdot2\)
=>33x=66
=>\(x=\frac{66}{33}=2\)
Bài 14:
a: (12-x)(2-x)=0
=>\(\left[\begin{array}{l}12-x=0\\ 2-x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=12\\ x=2\end{array}\right.\)
b: (x-33)(11-x)=0
=>\(\left[\begin{array}{l}x-33=0\\ 11-x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=33\\ x=11\end{array}\right.\)
c: (21-x)(12-x)=0
=>\(\left[\begin{array}{l}21-x=0\\ 12-x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=21\\ x=12\end{array}\right.\)
d: (50-x)(x-150)=0
=>\(\left[\begin{array}{l}50-x=0\\ x-150=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=50\\ x=150\end{array}\right.\)
Bài 13:
a: (x-2)(x-3)=0
=>\(\left[\begin{array}{l}x-2=0\\ x-3=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=2\\ x=3\end{array}\right.\)
b: (x-3)(x-4)=0
=>\(\left[\begin{array}{l}x-3=0\\ x-4=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=3\\ x=4\end{array}\right.\)
c: (x-7)(6-x)=0
=>\(\left[\begin{array}{l}x-7=0\\ 6-x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=7\\ x=6\end{array}\right.\)
d: (x-3)(x-13)=0
=>\(\left[\begin{array}{l}x-3=0\\ x-13=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=3\\ x=13\end{array}\right.\)
a, 100 - 7 x ( x - 5 ) = 58
7 x ( x - 5 ) = 100 - 58
7 x ( x - 5 ) = 42
( x - 5 ) = 42 : 7
x - 5 = 6
x = 6 + 5
x = 11
b, 24 + 5 * x = 49
5 * x = 49 - 24
5 * x = 25
x = 25 : 5
x = 5
c, x - 105 : 21 = 15
x - 5 = 15
x = 15 + 5
x = 20
d, ( x - 105 ) : 21 = 15
( x - 105 ) = 15 x 21
x - 105 = 315
x = 315 + 105
x = 420
a> x+15=105
x=105-15
x=90
b> 12:x+33=39
12:x=39-33
12:x=6
x=12:6
x=2
c> (x+249):3=197
x+249 =197x3
x+249=591
x =591-249
x=342
d> Xx98:5=29988
Xx98=29988x5
Xx98=149940
X 149940 :98
X=1530
chúc cậu bạn học giỏi nha
a) x + 15 =105
x = 105-15
x = 90