Với x = 2023 

<=> x + 1 = 2024

Khi đó P(2023) = x²⁰²³ - (x + 1).x²⁰²² + ... + (x + 1).x - 1

= x²⁰²³ - x²⁰²³ - x²⁰²² + .. + x² + x - 1

= x - 1 = 2023 - 1 = 2022

x-7=-5

=>x=-5+7=2

x+2=0

=>x=0-2=-2

\(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)

=>\(3x-16=\frac{2\cdot7^4}{7^3}=2\cdot7=14\)

=>3x=16+14=30

=>x=30/3=10

|x-5|=|-7|

=>x-5=7 hoặc x-5=-7

=>x=12 hoặc x=-2

x-[42+(-28)]=-8

=>x-14=-8

=>x=-8+14

=>x=6

128-3(x+4)=23

=>3(x+4)=128-23=105

=>x+4=35

=>x=35-4=31

4-(7-x)=x-(13-4)

=>4-7+x=x-9

=>x-3=x-9

=>-3=-9(vô lý)

=>x∈∅

Bài 2:

S1=1+2+...+999

\(=\frac{999\left(999+1\right)}{2}=999\cdot\frac{1000}{2}\)

\(=999\cdot500=499500\)

S1=10+12+...+2010

Số số hạng của dãy là:

(2010-10):2+1=2000:2+1=1001(số)

Tổng của dãy số là:

\(S_1=\left(2010+10\right)\cdot\frac{1001}{2}=2020\cdot\frac{1001}{2}=1001\cdot1010=1011010\)

kết quả là 1022 nhé bạn

Tính nhanh : 

a) 25² - 15² = (25 + 15)(25 - 15) = 40 . 10 = 400

b) 87² + 73² - 27² - 13² = (87² - 13²) + (73² - 27²)

= (87 + 13)(87 - 13) + (73 + 27)(73 - 27)

= 100 . 74 + 100 . 26 = 100 . (74 + 26) = 100 . 100 = 10000

Bài 1:

a)\(\left(x+y\right)^2-\left(x-y\right)^2=\left(x+y+x-y\right)\left(x+y-x+y\right)=2x\cdot2y=2\left(x+y\right)\)

b) \(\left(3x+1\right)^2-\left(x+1\right)^2=\left(3x+1+x+1\right)\left(3x+1-x-1\right)\\ =\left(4x+2\right)\cdot2x=4x\left(2x+1\right)\)

Bài 2:

a) \(25^2-15^2=\left(25-15\right)\left(25+15\right)=10\cdot40=400\)

b) \(87^2+73^2-27^2-13^2=\left(87^2-27^2\right)+\left(73^2-13^2\right)\\ =\left(87-27\right)\left(87+27\right)+\left(73-13\right)\left(73+13\right)\)

\(=60\cdot114+60\cdot86=60\cdot\left(114+86\right)=60\cdot200=12000\)

Bài 2:

a) \(x^3-0,25\cdot x=0\)

\(\Leftrightarrow x^2\left(x-0,25\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x-0,25=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x=0,25\end{array}\right.\)

b) \(x^2-10=-25\)

\(\Leftrightarrow x^2=-15\) (vô nghiệm0

c) \(4x^2-4x=-1\)

\(\Leftrightarrow4x^2-4x+1=0\)

\(\Leftrightarrow\left(2x-1\right)^2=0\)

\(\Leftrightarrow2x-1=0\Leftrightarrow x=\frac{1}{2}\)

d) \(8x^3+12x^2+6x+1=0\)

\(\Leftrightarrow\left(2x+1\right)^3=0\)

\(\Leftrightarrow2x+1=0\Leftrightarrow x=-\frac{1}{2}\)

(1-1/2) x (1-1/3) x .... x (1-1/100) 

= 1/2 x 2/3 x ... x 99/100 

= 1x2x...x99/2x3x..x100 

= 1/ 100 

a, \(\frac{3}{5}+25-\frac{1}{5}\)

\(=\left(\frac{3}{5}-\frac{1}{5}\right)+25\)

\(=\frac{2}{5}+25\)

\(=25\frac{2}{5}\)

\(=25,4\)

b, \(13.3.32,27+67,63.39\)

\(=39.32,27+67,63.39\)

\(=39\left(32,37+67,63\right)\)

\(=39.100\)

\(=3900\)

c, \(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right)....\left(1-\frac{1}{100}\right)\)

\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}......\frac{99}{100}\)

\(=\frac{1}{100}\)

y^? thế em 

y^2

nhe cj

\(x+\left(x+1\right)+\left(x+2\right)+...+2023+2024=2024\)

\(\Rightarrow2023x+4090506=2024-2024-20232023\)

\(\Rightarrow x+4090506=-2023\)

\(\Rightarrow2023x=-2023-4090506\)

\(\Rightarrow2023x=-4092529\)

\(\Rightarrow x=-2023\).

1011

lấy máy tính ra bấm, không rảnh!!!!!!!

lớp 1 đã học cái này rồi à ?

x+(x-1)-(x-2)+(x-3)-(x-4)+...+(x-2023)-(x-2024)=0

=>x+(x-1-x+2)+(x-3-x+4)+...+(x-2023-x+2024)=0

=>x+1+1+...+1=0

=>x+1012=0

=>x=-1012

=>Chọn C