Bài 5: Làm tính nhân
a) 4x4.( 7xn-1+x-5)
b) 2xn-2.(14xn+1-10x2)
c) 2n-1.(xn-1+2)
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a: \(x^{n}\cdot y^{n+2}\left(xy+x^2y+1\right)\)
\(=x^{n}\cdot y^{n+2}\cdot xy+x^{n}\cdot y^{n+2}\cdot x^2y+x^{n}y^{n+2}\)
\(=x^{n+1}\cdot y^{n+3}+x^{n+2}\cdot y^{n+3}+x^{n}y^{n+2}\)
b: \(\left(4x^{n-2}+x^{n+1}\right)\cdot x^{n}\)
\(=4x^{n-2}\cdot x^{n}+x^{n+1}\cdot x^{n}\)
\(=4x^{2n-2}+x^{2n+1}\)
c: \(4xy\left(x^{n-2}y^{n+1}+x^{n}y^{n+1}\right)\)
\(=4xy\cdot x^{n-2}\cdot y^{n+1}+4xy\cdot x^{n}y^{n+1}\)
\(=4x^{n-1}y^{n+2}+4x^{n+1}\cdot y^{n+2}\)
a)=1x2x3x4x5/2x3x4x5x6 =1/6
b)=1x2x3x4x5x6x7x8x9/10x9x8x7x6x5x4x3 x2=1/10
Bài 1:
\(a,6x^2-15x^3y\\ b,=-\dfrac{2}{3}x^2y^3+\dfrac{2}{3}x^4y-\dfrac{8}{3}xy\)
Bài 2:
\(a,=20x^3-10x^2+5x-20x^3+10x^2+4x=9x\\ b,=3x^2-6x-5x+5x^2-8x^2+24=24-11x\\ c,=x^5+x^3-2x^3-2x=x^5-x^3-2x\)
Bài 3:
b. $B=(x+y)(2x-y)+(xy^4-x^2y^2):(xy^2)$
$=(2x^2-xy+2xy-y^2)+(y^2-x)$
$=2x^2+xy-y^2+y^2-x=2x^2+xy-x$
Bài 4:
a. $25x^3-10x^2+x=x(25x^2-10x+1)=x(5x-1)^2$
b. $x^2-9x+9y-y^2=(x^2-y^2)-(9x-9y)=(x-y)(x+y)-9(x-y)=(x-y)(x+y-9)$
c. $16-x^2-4y^2-4xy=16-(x^2+4y^2+4xy)$
$=4^2-(x+2y)^2=(4-x-2y)(4+x+2y)$
a2/4x4/7= 2/7 b 10/21:5/7=2/3 c10/21:2/3=5/7 d1/5x1/3=1/15
e1/15:1/5=1/3 g 1/15:1/5= 1/3 h 1/15:1/3= 105
k mình nhé bạn
a)\(\left(\dfrac{5}{6}+\dfrac{3}{8}\right)\times\dfrac{2}{7}\)
\(=\dfrac{29}{24}\times\dfrac{2}{7}\)
\(=\) \(\dfrac{29}{84}\)
b) \(\dfrac{6}{7}\times\dfrac{2}{3}\div\dfrac{5}{7}\)
= \(\dfrac{4}{7}\div\) \(\dfrac{5}{7}\)
= \(\dfrac{4}{5}\)
c) \(\dfrac{8}{9}+\dfrac{3}{4}\times\dfrac{4}{9}\)
= \(\dfrac{8}{9}+\dfrac{1}{3}\)
= \(\dfrac{5}{9}\)
Cô tích xanh cho lisa blackpink vì câu a, b đúng. Còn câu c thì em làm như sau:
c, \(\dfrac{8}{9}\) + \(\dfrac{3}{4}\) \(\times\) \(\dfrac{4}{9}\)
= \(\dfrac{8}{9}\) + \(\dfrac{1}{3}\)
= \(\dfrac{8}{9}\) + \(\dfrac{3}{9}\)
= \(\dfrac{11}{9}\)
a) 4x⁴.(xⁿ⁻¹ + x - 5)
= 4xⁿ⁺³ + 4x⁵ - 20x⁴
b) 2xⁿ⁻².(14xⁿ⁺¹ - 10x²)
= 28x²ⁿ⁻¹ - 20xⁿ
c) 2ⁿ⁻¹.(xⁿ⁻¹ + 2)
= (2x)ⁿ⁻¹ + 2ⁿ