giúpvs ạ cảm ơn nhiều gấp mn ơii 
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a: Ta có: \(\sin^2a+cos^2a=1\)
=>\(cos^2a=1-0,6^2=0,64=0,8^2\)
=>cosa=0,8
\(\tan a=\frac{\sin a}{cosa}=\frac{0.6}{0.8}=\frac34\)
\(\cot a=\frac{1}{\tan a}=1:\frac34=\frac43\)
\(\sin\left(90^0-a\right)=cosa=0,8\)
\(cos\left(90^0-a\right)=\sin a=0,6\)
b: \(\sin^2a+cos^2a=1\)
=>\(sin^2a=1-\left(\frac{1}{\sqrt5}\right)^2=1-\frac15=\frac45\)
=>\(\sin a=\frac{2}{\sqrt5}\)
tan a=\(\frac{\sin a}{cosa}=\frac{2}{\sqrt5}:\frac{1}{\sqrt5}=2\)
cot a=1/tana=1/2
\(\tan\left(90^0-a\right)=\cot a=\frac12\)
\(\cot\left(90^0-a\right)=\tan a=2\)
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It rained hard; moreover, lightening flashed and thunder boomed.
The baby fell asleep; then, the doorbell rang.
The law does not permit drinking and driving anytime; otherwise, there would be many more accidents.
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Mn giải giúp mik vs ạ 🥺 mình đang cần gấp. Cảm ơn mn nhiều


Bài 3:
\(a,\dfrac{2}{-7}=\dfrac{2.\left(-11\right)}{\left(-7\right).\left(-11\right)}=\dfrac{-22}{77}\)
\(\dfrac{-3}{11}=\dfrac{-3.7}{11.7}=\dfrac{-21}{77}\)
Vì \(\dfrac{-22}{77}< \dfrac{-21}{77}\) nên \(\dfrac{2}{-7}< \dfrac{-3}{11}\)
\(b,\dfrac{2}{5}=\dfrac{2.13}{5.13}=\dfrac{26}{65}\)
\(\dfrac{6}{13}=\dfrac{6.5}{13.5}=\dfrac{30}{65}\)
Vì \(\dfrac{26}{65}< \dfrac{30}{65}\) nên \(\dfrac{2}{5}< \dfrac{6}{13}\)