16:Sửa đề: \(\frac12x+\frac16\left(x-2\right)=\frac34-2x\)

=>\(\frac12x+\frac16x-\frac26=\frac34-2x\)

=>\(\frac46x-\frac13=\frac34-2x\)

=>\(\frac23x+2x=\frac34+\frac13\)

=>\(\frac83x=\frac{9}{12}+\frac{4}{12}=\frac{13}{12}\)

=>\(x=\frac{13}{12}:\frac83=\frac{13}{12}\times\frac38=\frac{13}{4\times8}=\frac{13}{32}\)

19: \(\frac{5}{12}x+3=\frac13-\frac{7}{12}x\)

=>\(\frac{5}{12}x+\frac{7}{12}x=\frac13-3\)

=>\(\frac{12}{12}x=\frac13-\frac93=-\frac83\)

=>\(x=-\frac83\)

20: \(\frac12x+\frac52=\frac72x-\frac34\)

=>\(\frac12x-\frac72x=-\frac34-\frac52\)

=>\(-3x=-\frac34-\frac{10}{4}=-\frac{13}{4}\)

=>\(3x=\frac{13}{4}\)

=>\(x=\frac{13}{4}:3=\frac{13}{12}\)

a) 

(1/3-1/5)x1/4 = 1/3x1/4-1/5x1/4=1/12-1/20=1/30

(1/3-1/5)x1/4 = 2/15x1/4=1/30

b)

2/5 x 3/7 + 2/5 x 4/7= 6/35 + 8/35 = 14/35 = 2/5

2/5 x 3/7 + 2/5 x 4/7= (3/7+4/7) x 2/5 = 1 x 2/5 = 2/5

a: C1: (1/3-1/5)*1/4

=2/15*1/4=2/60=1/30

C2: (1/3-1/5)*1/4

=1/3*1/4-1/5*1/4

=1/12-1/20=1/30

b: C1: 2/5*3/7+2/5*4/7

=6/35+8/35=14/35=2/5

C2: 2/5*3/7+2/5*4/7

=2/5(3/7+4/7)

=2/5*1=2/5

Các bạn giúp mình với ạ

Bài 2a:

Tìm x

5/3x + 2/3 = 1/4

5/3x = 1/4 - 2/3

5/3x = 3/12 - 8/12

5/3x = - 5/12

x = -5/12 : 5/3

x = -5/12 x 3/5

x = - 1/4

Vậy x = -1/ 4

\(a,=\dfrac{x^3-\left(x-1\right)\left(x^2+x+1\right)}{1-x}=\dfrac{x^3-x^3+1}{1-x}=\dfrac{1}{1-x}\\ b,=\dfrac{2x+x^2+3x+2+2-x}{\left(x+2\right)^2}=\dfrac{\left(x+2\right)^2}{\left(x+2\right)^2}=1\)

Thank bạn <3

Câu a:

xem lại đề bài

Câu b:

5 2/8x - 1/9 = 4 3/5

42/8x - 1/9 = 23/5

21/4x = 23/5 + 1/9

21/4x = 207/45 + 5/45

21/4x = 212/45

x = 212/45: 21/4

x = 212/45 x 4/21

x = 848/945

Vậy: x = 848/945

Câu c:

45%x - 2/3x = 75%

9/20x - 2/3x = 3/4

x(9/20 - 2/3) = 3/4

x(27/60 - 40/60) = 3/4

x.(-13/60) = 3/4

x = 3/4 : (-13/60)

x = 3/4 x (-60/13)

x = - 45/13

Vậy x = - 45/13

hình như đề sai vì x + (-2/3) không thể bằng x + 1/4 đúng k nhỉ :)

Ko nhưng đề được giao nó là như thế còn mình chịu