1-wool

2-cotton

3-metal

4-letter

5-glass(cs thể th vì nó thừa)

6-wood 

Mình nghĩ nó thế này:

2. cotton

4.leather

5.wool

6.wood

Còn 1 với 3 mình không biết

1. across : băng qua

2. turn right : rẽ phải

3. turn left : rẽ trái

4.straight on : đi thẳng

5. go pass : đi qua

6. go along : đi dọc theo

7. at the corner of : tại góc

cotton: 3,4,8

wood: 2,5,6

leather: 1,7,9

Câu I:

1) Ta có: \(P=\left(\dfrac{\sqrt{x}}{\sqrt{x}-1}+\dfrac{\sqrt{x}+2}{\sqrt{x}}-\dfrac{x+\sqrt{x}-4}{x-\sqrt{x}}\right):\left(\dfrac{1}{\sqrt{x}+1}+\dfrac{2}{x-1}\right)\)

\(=\left(\dfrac{x}{\sqrt{x}\left(\sqrt{x}-1\right)}+\dfrac{\left(\sqrt{x}+2\right)\left(\sqrt{x}-1\right)}{\sqrt{x}\left(\sqrt{x}-1\right)}-\dfrac{x+\sqrt{x}-4}{\sqrt{x}\left(\sqrt{x}-1\right)}\right):\left(\dfrac{\sqrt{x}-1+2}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\right)\)

\(=\dfrac{x+x+\sqrt{x}-2-x-\sqrt{x}+4}{\sqrt{x}\left(\sqrt{x}-1\right)}:\dfrac{\sqrt{x}+1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)

\(=\dfrac{x+2}{\sqrt{x}\left(\sqrt{x}-1\right)}\cdot\dfrac{\sqrt{x}-1}{1}\)

\(=\dfrac{x+2}{\sqrt{x}}\)

2) Để P=3 thì \(\dfrac{x+2}{\sqrt{x}}=3\)

\(\Leftrightarrow x+2=3\sqrt{x}\)

\(\Leftrightarrow x-3\sqrt{x}+2=0\)

\(\Leftrightarrow x-\sqrt{x}-2\sqrt{x}+2=0\)

\(\Leftrightarrow\sqrt{x}\cdot\left(\sqrt{x}-1\right)-2\left(\sqrt{x}-1\right)=0\)

\(\Leftrightarrow\left(\sqrt{x}-2\right)\left(\sqrt{x}-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}\sqrt{x}-2=0\\\sqrt{x}-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\sqrt{x}=2\\\sqrt{x}=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\left(nhận\right)\\x=1\left(loại\right)\end{matrix}\right.\)
Vậy: Để P=3 thì x=4

start with " C " 

Animals    food & drink             sport

CAT         chilli Caju amigo        Chess boxing

Start with D

Animals       food & drink                sport

duck        dewberry Daiquiri            darts

Start with S

animals            food & drink            sport 

Snake         sausage Salty dog     swimming

Start with M

animals                food drink                sport

monkey         Mackerel Mango sour         miniten

Thấy gì đâu??

._.?

Ai giúp mình zới, khó quá huhuhuhuhuh

Bài 22:

a: \(\frac{x}{x-1}-\frac{2}{x+1}-\frac{2}{x^2-1}\)

\(=\frac{x\left(x+1\right)-2\left(x-1\right)-2}{\left(x-1\right)\left(x+1\right)}\)

\(=\frac{x^2-x-2x+2-2}{\left(x-1\right)\left(x+1\right)}\)

\(=\frac{x^2-3x}{x^2-1}\)

b: \(\frac{1}{3x-2}-\frac{4}{3x+2}-\frac{3x-6}{4-9x^2}\)

\(=\frac{1}{3x-2}-\frac{4}{3x+2}+\frac{3x-6}{\left(3x-2\right)\left(3x+2\right)}\)

\(=\frac{3x+2-4\left(3x-2\right)+3x-6}{\left(3x-2\right)\left(3x+2\right)}=\frac{6x-4-12x+8}{\left(3x-2\right)\left(3x+2\right)}\)

\(=\frac{-6x+4}{\left(3x-2\right)\left(3x+2\right)}=\frac{-2\left(3x-2\right)}{\left(3x-2\right)\left(3x+2\right)}=\frac{-2}{3x+2}\)

c: \(\frac{x^2}{x^2-x}-\frac{x^2}{x+1}-\frac{2x}{x^2-1}\)

\(=\frac{x}{x-1}-\frac{x^2}{x+1}-\frac{2x}{\left(x-1\right)\left(x+1\right)}\)

\(=\frac{x\left(x+1\right)-x^2\left(x-1\right)-2x}{\left(x-1\right)\left(x+1\right)}=\frac{x^2+x-x^3+x^2-2x}{\left(x-1\right)\left(x+1\right)}\)

\(=\frac{-x^3+2x^2-x}{\left(x-1\right)\left(x+1\right)}=\frac{-x\left(x^2-2x+1\right)}{\left(x-1\right)\left(x+1\right)}\)

\(=\frac{-x\left(x-1\right)^2}{\left(x-1\right)\left(x+1\right)}=\frac{-x\left(x-1\right)}{x+1}\)

d: \(\frac{4x^2-3x+5}{x^3-1}-\frac{1-2x}{x^2+x+1}-\frac{6}{x-1}\)

\(=\frac{4x^2-3x+5+\left(2x-1\right)\left(x-1\right)-6\left(x^2+x+1\right)}{\left(x-1\right)\left(x^2+x+1\right)}\)

\(=\frac{4x^2-3x+5+2x^2-3x+1-6x^2-6x-6}{\left(x-1\right)\left(x^2+x+1\right)}=\frac{-12x}{x^3-1}\)

e: \(\frac{5}{2x^2+6x}-\frac{4-3x^2}{x^2-9}-3\)

\(=\frac{5}{2x\left(x+3\right)}+\frac{3x^2-4}{\left(x-3\right)\left(x+3\right)}-3\)

\(=\frac{5\left(x-3\right)+2x\left(3x^2-4\right)-3\cdot2x\left(x-3\right)\left(x+3\right)}{2x\left(x-3\right)\left(x+3\right)}\)

\(=\frac{5x-15+6x^3-8x-6x\left(x^2-9\right)}{2x\left(x-3\right)\left(x+3\right)}=\frac{6x^3-3x-15-6x^3+54x}{2x\left(x-3\right)\left(x+3\right)}\)

\(=\frac{51x-15}{2x\left(x-3\right)\left(x+3\right)}\)

f: \(\frac{5}{x+1}-\frac{10}{x-x^2-1}-\frac{15}{x^3+1}\)

\(=\frac{5}{x+1}+\frac{10}{x^2-x+1}-\frac{15}{\left(x+1\right)\left(x^2-x+1\right)}\)

\(=\frac{5\left(x^2-x+1\right)+10\left(x+1\right)-15}{\left(x+1\right)\left(x^2-x+1\right)}=\frac{5x^2-5x+5+10x+10-15}{\left(x+1\right)\left(x^2-x+1\right)}\)

\(=\frac{5x^2+5x}{\left(x+1\right)\left(x^2-x+1\right)}=\frac{5x}{x^2-x+1}\)

Bài 24:

\(\frac{1}{x}-\frac{1}{x+1}\)

\(=\frac{x+1-x}{x\left(x+1\right)}=\frac{1}{x\left(x+1\right)}\)

a: \(\frac{1}{x\left(x+1\right)}+\frac{1}{\left(x+1\right)\left(x+2\right)}+\frac{1}{\left(x+2\right)\left(x+3\right)}+\frac{1}{\left(x+3\right)\left(x+4\right)}\)

\(=\frac{1}{x}-\frac{1}{x+1}+\frac{1}{x+1}-\frac{1}{x+2}+\frac{1}{x+2}-\frac{1}{x+3}+\frac{1}{x+3}-\frac{1}{x+4}\)

\(=\frac{1}{x}-\frac{1}{x+4}=\frac{x+4-x}{x\left(x+4\right)}=\frac{4}{x\left(x+4\right)}\)

b: \(\frac{1}{x^2+x}+\frac{1}{x^2+3x+2}+\frac{1}{x^2+5x+6}+\frac{1}{x^2+7x+12}+\frac{1}{x^2+9x+20}+\frac{1}{x+5}\)

\(=\frac{1}{x\left(x+1\right)}+\frac{1}{\left(x+1\right)\left(x+2\right)}+\frac{1}{\left(x+2\right)\left(x+3\right)}+\frac{1}{\left(x+3\right)\left(x+4\right)}+\frac{1}{\left(x+4\right)\left(x+5\right)}+\frac{1}{x+5}\)

\(=\frac{1}{x}-\frac{1}{x+1}+\frac{1}{x+1}-\frac{1}{x+2}+\frac{1}{x+2}-\frac{1}{x+3}+\frac{1}{x+3}-\frac{1}{x+4}+\frac{1}{x+4}-\frac{1}{x+5}+\frac{1}{x+5}\)

\(=\frac{1}{x}\)