x4 – 2x2

(Có x2 là nhân tử chung)

= x2(x2 – 2)

x 4 - 2 x 3 - 2 x 2 - 2 x - 3 =   ( x 4   −   1 )   −   ( 2 x 3   +   2 x 2 )   −   ( 2 x   +   2 ) =   ( x 2   +   1   ) ( x 2   −   1 )   −   2 x 2 ( x   +   1 )   − 2 ( x   +   1 ) =   ( x 2   +   1 ) ( x   −   1 ) ( x   +   1 )   −   2 x 2 ( x   +   1 )   − 2 ( x   +   1 ) =   ( x   +   1 ) ( x 2   +   1 ) ( x   −   1 )   −   2 x 2   –   2 =   ( x   +   1 ) (   x 2   +   1 ) ( x   −   1 )   −   2 ( x 2   +   1 ) =   ( x   +   1 ) (   x 2   +   1 ) ( x   –   1   −   2 ) =   ( x   +   1 ) (   x 2   +   1 ) ( x   −   3 )

x^4 - 2x^3 - 2x^2 - 2x - 3 

= x^4 - 1 - 2x^3 - 2x^2 - 2x -2 

= ( x - 1 ) ( x + 1 ) ( x^2 + 1 ) - 2x^2 ( x + 1 ) - 2 ( x + 1 ) 

= ( x + 1 ) [ ( x - 1 ) ( x^2 + 1 ) - 2x^2 - 2 ] 

= ( x + 1 ) [ ( x - 1 ) ( x^2 + 1 - 2 ( x^2 - 1 ) ] 

= ( x + 1 ) [ ( x - 1 ) ( x^2 + 1 ) - 2 ( x - 1 ) ( x + 1 ) ] 

= ( x + 1 ) ( x - 1 ) [ ( x^2 + 1 ) - 2 ( x +1 ) 

= ( x + 1 ) ( x - 1 ) ( x^2 +1 - 2x - 2 ) 

= ( x + 1 ) ( x - 1 ) ( x^2 - 2x - 1 ) 

bạn có chơi bang bang ko va

tui đã viết dề sai

câu đúng x4+x3+2x2+x+1

a: \(x^4+2x^3+3x^2+2x+1\)

\(=x^4+x^3+x^2+x^3+x^2+x+x^2+x+1\)

\(=x^2\left(x^2+x+1\right)+x\left(x^2+x+1\right)+\left(x^2+x+1\right)\)

\(=\left(x^2+x+1\right)\left(x^2+x+1\right)=\left(x^2+x+1\right)^2\)

b: \(x^4-4x^3+2x^2+4x+1\)

\(=x^4-2x^3-x^2-2x^3+4x^2+2x-x^2+2x+1\)

\(=x^2\left(x^2-2x-1\right)-2x\left(x^2-2x-1\right)-\left(x^2-2x-1\right)\)

\(=\left(x^2-2x-1\right)\left(x^2-2x-1\right)=\left(x^2-2x-1\right)^2\)

c: \(x^4+x^3+2x^2+2x+4\)

\(=x^4-x^3+2x^2+2x^3-2x^2+4x+2x^2-2x+4\)

\(=x^2\left(x^2-x+2\right)+2x\left(x^2-x+2\right)+2\left(x^2-x+2\right)\)

\(=\left(x^2-x+2\right)\left(x^2+2x+2\right)\)

a: \(3x^3y^2-12x^2y^3\)

\(=3x^2y^2\cdot x-3x^2y^2\cdot4y\)

\(=3x^2y^2\left(x-4y\right)\)

b: \(x^2-5x+xy-5y\)

=x(x-5)+y(x-5)

=(x-5)(x+y)

d: \(2x^2-4xy+2y^2-18\)

\(=2\left(x^2-2xy+y^2-9\right)\)

\(=2\left\lbrack\left(x-y\right)^2-3\right\rbrack\)

=2(x-y-3)(x-y+3)

e: \(x^3-2020x_{}^2+2020x-2019\)

\(=x^3-x^2+x-2019x^2+2019x-2019\)

\(=x\left(x^2-x+1\right)-2019\left(x^2-x+1\right)=\left(x^2-x+1\right)\left(x-2019\right)\)