Bài toán 4: Viết các số sau dưới dạng tổng các luỹ thừa của 10. 
213 = 2 . 100 + 1 . 10 +3 = 2. 10^2 + 1.10 + 3 . 10^0

421=4.100 + 2.10 + 1 = 4.10^2 + 2.10 + 1. 10^0

2009; = 2. 1000 + 9 = 2. 10^3 + 9 . 10^0

abc = a . 100 + b . 10 + c = a.10^2 + b.10 + c.10^0

abcde = a.10000 + b . 1000 + c . 100  + d . 10 + e = a . 10^4 + b. 10^3 + c.10^2 + d .10 + e . 10 ^0 

thanks bn

a: \(280-\left(x-140\right):35=270\)

=>(x-140):35=280-270=10

=>x-140=350

=>x=350+140

=>x=490

b: \(\left(190-2x\right):35-32=16\)

=>\(\left(190-2x\right):35=32+16=48\)

=>\(190-2x=35\cdot48=1680\)

=>2x=190-1680=-1490

=>x=-745

c: \(720:\left\lbrack41-\left(2x-5\right)\right\rbrack=2^3\cdot5\)

=>\(720:\left\lbrack41-\left(2x-5\right)\right\rbrack=8\cdot5=40\)

=>41-(2x-5)=720:40=18

=>2x-5=41-18=23

=>2x=28

=>x=14

d: \(\left(x:23+45\right)\cdot37-22=2^4\cdot105\)

=>\(\left(\frac{x}{23}+45\right)\cdot37=16\cdot105+22=1702\)

=>\(\frac{x}{23}+45=46\)

=>\(\frac{x}{23}=1\)

=>x=23

e: \(\left(3x-4\right)\left(x-1\right)^3=0\)

=>\(\left[\begin{array}{l}3x-4=0\\ x-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac43\\ x=1\end{array}\right.\)

f: \(2^{2x-1}:4=8^3\)

=>\(2^{2x-1-2}=2^9\)

=>2x-3=9

=>2x=12

=>x=6

g: \(x^{17}=x\)

=>\(x^{17}-x=0\)

=>\(x\left(x^{16}-1\right)=0\)

=>\(\left[\begin{array}{l}x=0\\ x^{16}-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x^{16}=1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x=1\\ x=-1\end{array}\right.\)

h: \(\left(x-5\right)^4=\left(x-5\right)^6\)

=>\(\left(x-5\right)^6-\left(x-5\right)^4=0\)

=>\(\left(x-5\right)^4\cdot\left\lbrack\left(x-5\right)^2-1\right\rbrack=0\)

=>\(\left(x-5\right)^4\cdot\left(x-4\right)\left(x-6\right)=0\)

=>x∈{4;5;6}

i: \(\left(x+2\right)^5=2^{10}\)

=>\(\left(x+2\right)^5=\left(2^2\right)^5=4^5\)

=>x+2=4

=>x=2

k: 1+2+3+...+x=78

=>\(\frac{x\left(x+1\right)}{2}=78\)

=>x(x+1)=156

=>\(x^2+x-156=0\)

=>(x+13)(x-12)=0

=>x=-13(loại) hoặc x=12(nhận)

l: \(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)

=>\(3x-16=2\cdot\frac{7^4}{7^3}=2\cdot7=14\)

=>3x=16+14=30

=>\(x=\frac{30}{3}=10\)

n: \(5^{x}:5^2=125\)

=>\(5^{x-2}=5^3\)

=>x-2=3

=>x=5

m: \(\left(x+1\right)^2=\left(x+1\right)^0\)

=>\(\left(x+1\right)^2=1\)

=>\(\left[\begin{array}{l}x+1=1\\ x+1=-1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x=-2\end{array}\right.\)

o: Số số hạng của dãy số 2;4;..;52 là:

(52-2):2+1=50:2+1=25+1=26(số)

Tổng của dãy số 2;4;...;52 là:

\(\left(52+2\right)\cdot\frac{26}{2}=54\cdot13=702\)

(2+x)+(4+x)+...+(52+x)=780

=>26x+702=780

=>26x=78

=>x=3

p: \(70=2\cdot5\cdot7;80=2^4\cdot5\)

=>ƯCLN(70;80)=\(2\cdot5=10\)

70⋮x; 80⋮x

=>x∈ƯC(70;80)

=>x∈Ư(10)

mà x>8

nên x=10

q: \(12=2^2\cdot3;25=5^2;30=2\cdot3\cdot5\)

=>BCNN(12;25;30)=\(2^2\cdot3\cdot5^2=300\)

x⋮12; x⋮25; x⋮30

=>x∈BC(12;25;30)

=>x∈B(300)

mà 0<x<500

nên x=300

b) 32<2ⁿ<128

==> 2⁵<2ⁿ<2⁷

==> 5<n<7

==> n=6

Câu a có sai đề không vậy bn

a. 64

b. 52

c. 37

d.1,0

bạn giải rõ lời hộ mình với. Ths!!

16) M = (-32 + 215) - (-30 + 215)

= -32 + 215 + 30 - 215

= (215 - 215) + (30 - 32)

= 0 - 2 = -2

17) N = -5 + (-37 - 45 + 151) - (-37 + 151)

= -5 - 37 - 45 + 151 + 37 - 151

= (151 - 151) - (5+45) + (37 - 37)

= 0 - 50 + 0 = -50

1)\(x-105:21=15\)

\(x-5=15\)

\(x=15+5\)

\(x=20\)

Vậy \(x=20.\)

2)\(\left(x-105\right):21=15\)

\(\left(x-105\right)=15.21\)

\(x-105=315\)

\(x=315+105\)

\(x=420\)

Vậy \(x=412.\)

4)\(1818:\left(6x-37\right)=18\)

\(6x-37=1818:18\)

\(6x-37=101\)

\(6x=101+37\)

\(6x=138\)

\(x=138:6\)

\(x=23\)

Vậy \(x=23.\)

mk quên,còn phần 3) nữa:

3)\(\left(32+x\right):17=x\)

\(32+x=x.17\)

\(\Leftrightarrow x=2\)

Vậy \(x=2.\)