Tinh bang cach gop li
\(\frac{1}{2}\left(\frac{2}{9}+\frac{3}{7}-\frac{5}{27}\right)\)
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a)(1/4+3/4)-(5/13+8/13)+2/11=1-1+2/11=2/11
b)(21/31+10/31)-16/7+(44/53+9/53)=1+1-16/7=14/7-16/7=-2/7
$A=\dfrac{\left(\dfrac15-\dfrac27\right)\cdot\dfrac34-\dfrac34\cdot\left(\dfrac13-\dfrac27\right)}{\dfrac15\cdot\dfrac27-\dfrac13\cdot\left(\dfrac27+\dfrac39\right)+\dfrac39+\dfrac15}$
$=\dfrac{\dfrac34\left[\left(\dfrac15-\dfrac27\right)-\left(\dfrac13-\dfrac27\right)\right]}{\dfrac2{35}-\dfrac13\left(\dfrac27+\dfrac13\right)+\dfrac13+\dfrac15}$
$=\dfrac{\dfrac34\left(\dfrac15-\dfrac13\right)}{\dfrac2{35}-\dfrac13\cdot\dfrac{13}{21}+\dfrac13+\dfrac15}$
$=\dfrac{\dfrac34\cdot\left(-\dfrac2{15}\right)}{\dfrac2{35}-\dfrac{13}{63}+\dfrac{8}{15}}$
$=\dfrac{-\dfrac1{10}}{\dfrac{18-65+168}{315}}$
$=\dfrac{-\dfrac1{10}}{\dfrac{121}{315}}$
$=-\dfrac1{10}\cdot\dfrac{315}{121}$
$=-\dfrac{63}{242}.$
\(\frac{-5}{7}+\frac{3}{4}+\frac{-1}{5}+\frac{-2}{7}+\frac{1}{4}\)
\(=\left(\frac{-5}{7}+\frac{-2}{7}\right)+\left(\frac{3}{4}+\frac{1}{4}\right)+\frac{-1}{5}\)
\(=-1+1+\frac{-1}{5}\)
\(=-\frac{1}{5}\)
$A=\dfrac{\left(\dfrac15-\dfrac27\right)\cdot\dfrac34-\dfrac34\cdot\left(\dfrac13-\dfrac27\right)}{\dfrac15\cdot\dfrac27-\dfrac13\cdot\left(\dfrac27+\dfrac39\right)+\dfrac39+\dfrac15}$
$=\dfrac{\dfrac34\left[\left(\dfrac15-\dfrac27\right)-\left(\dfrac13-\dfrac27\right)\right]}{\dfrac2{35}-\dfrac13\cdot\left(\dfrac27+\dfrac13\right)+\dfrac13+\dfrac15}$
$=\dfrac{\dfrac34\left(\dfrac15-\dfrac13\right)}{\dfrac2{35}-\dfrac13\cdot\dfrac{13}{21}+\dfrac13+\dfrac15}$
$=\dfrac{\dfrac34\cdot\left(-\dfrac2{15}\right)}{\dfrac2{35}-\dfrac{13}{63}+\dfrac13+\dfrac15}$
$=\dfrac{-\dfrac1{10}}{\dfrac{18-65+105+63}{315}}$
$=\dfrac{-\dfrac1{10}}{\dfrac{121}{315}}$
$=-\dfrac1{10}\cdot\dfrac{315}{121}$
$=-\dfrac{63}{242}.$
a) Hình tròn tâm O,bán kính 3cm
a) Hình tròn tâm O,bán kính 3cm
a) Hình tròn tâm O,bán kính 3cm
1/2 . ( 2/9 + 3/7 - 5/27 )
=1/2 . ( 2/9-5/27)+3/7
=1/2 . (1/27+3/7)
=1/2 .
=1/2x88/189=44/189