72–7(13–x)=14
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\(72-7\left(13-x\right)=14\)
\(7\left(13-x\right)=58\)
\(13-x=\dfrac{58}{7}\)
\(x=13-\dfrac{58}{7}\)
\(x=\dfrac{91}{7}-\dfrac{58}{7}\)
\(x=\dfrac{33}{7}\)
`72-7(13-x)=14`
`=>7(13-x)=72-14`
`=>7(13-x)=58`
`=>13-x=58:7`
`=>13-x=58/7`
`=>x=13-58/7`
`=>x=33/7`
(82 - 5.x) : 13 - 4 = 0
(82 - 5.x) : 13 = 0 + 4
(82 - 5.x) : 13 = 4
(82 - 5.x) = 4 . 13
(82 - 5.x) = 52
5.x = 82 - 52
5.x = 30
x = 30 : 5 = 6
(32 . 45) : 2 = (x + 70) : 14 - 40
720 = (x + 70) : 14 - 40
(x + 70) : 14 = 720 + 40
(x + 70) : 14 = 760
(x + 70) = 760 . 14
(x + 70) = 10640
x = 10640 - 70
x = 10570
Bai 2 :
\(\hept{\begin{cases}x+y=7\\x-7=13\end{cases}\Leftrightarrow\hept{\begin{cases}x+y=7\\x=20\end{cases}}}\)
Thay x vào phương trình đầu ta có :
\(20+y=7\Leftrightarrow y=-13\)
Vậy \(\left\{x;y\right\}=\left\{20;-13\right\}\)
Thử \(20-13=7\); \(20-7=13\)( thỏa mãn )
1: Ta có: \(2155-\left(174+2155\right)+\left(-68+174\right)\)
\(=2155-174-2155-68+174\)
=-68
2) Ta có: \(-25\cdot72+25\cdot21-49\cdot25\)
\(=-25\cdot\left(72-21+49\right)\)
\(=-25\cdot100=-2500\)
a: Ta có: \(3^{2020}=3^{2018}\cdot3^2=3^{2018}\cdot9\)
mà 9<10
nên \(3^{2020}< 10\cdot3^{2018}\)
Câu a:
- |- 5 + 3 - 7| - |- 5 + 7|
= -|- 2 - 7| - |2|
= - |-9| - 2
= - 9 - 2
= -11
Câu b:
24 - (72 - 13 + 24) - (72 - 13)
= 24 - 72 + 13 - 24 - 72 + 13
= (24 - 24) - (72 + 72) + (13 + 13)
= 0 - 144 + 26
= - 118
Câu c:
|4 - 9 - 5| - (4 - 9 - 5) - 15 + 9
=|- 5 - 5| - (- 5 - 5) - 15 + 9
= |-10| - (-10) - 15 + 9
= 10 + 10 - 15 + 9
= 20 - 15+ 9
= 5 +9
= 14
Câu d:
- 20 - (25 - 11 + 8) +(25 - 8 + 20)
= - 20 - 25 + 11 - 8 + 25 - 8 + 20
= (-20 + 20) + (25 - 25) + (11 - 8- 8)
= 0 + 0+ 3 - 8
= -5
Câu a:
- |- 5 + 3 - 7| - |- 5 + 7|
= -|- 2 - 7| - |2|
= - |-9| - 2
= - 9 - 2
= -11
Câu b:
24 - (72 - 13 + 24) - (72 - 13)
= 24 - 72 + 13 - 24 - 72 + 13
= (24 - 24) - (72 + 72) + (13 + 13)
= 0 - 144 + 26
= - 118
Câu c:
|4 - 9 - 5| - (4 - 9 - 5) - 15 + 9
=|- 5 - 5| - (- 5 - 5) - 15 + 9
= |-10| - (-10) - 15 + 9
= 10 + 10 - 15 + 9
= 20 - 15+ 9
= 5 +9
= 14
Câu d:
- 20 - (25 - 11 + 8) +(25 - 8 + 20)
= - 20 - 25 + 11 - 8 + 25 - 8 + 20
= (-20 + 20) + (25 - 25) + (11 - 8- 8)
= 0 + 0+ 3 - 8
= -5
c: \(78\cdot31+78\cdot24+78\cdot17+72\cdot22\)
\(=78\cdot\left(31+24+17\right)+72\cdot22\)
\(=72\cdot78+72\cdot22=72\cdot100=7200\)
d: \(\left(456\cdot11+912\right)\cdot37:13:74\)
\(=\frac{456\left(11+2\right)}{13}\cdot\frac{37}{74}=456\cdot\frac12=\frac{456}{2}=228\)
e: [\(\left(315+372\right)\cdot3+\left(372+315\right)\cdot7\) ]:\(\left(26\cdot13+74\cdot14\right)\)
\(=687\cdot\left(3+7\right):\left\lbrack26\cdot13+74\cdot13+74\right\rbrack\)
=687*10:[1300+74]
=687*10:1374
=5
72-7.(13-x)=14
=>7.(13-x)=72-14
=>7.(13-x)=58
=>13-x=58:7
=>13-x=\(\dfrac{58}{7}\)
\(=>x=13-\dfrac{58}{7}\)
\(=>x=\dfrac{33}{7}\)
Vậy ................
\(72-7(13-x)=14\)
\(7(13-x)=72-14\)
\(7(13-x)=58\)
\(13-x=58:7\)
\(13-x=\) \(\dfrac{58}{7}\)
\(x=13-\dfrac{58}{7}\)
\(x=\dfrac{33}{7}\)