244

nha

122+122=244

14884

122 x 122 = 14884.

Kết bạn nha

1.1.1.1.1.1.1.1.1.1.1.1..a+122=122

1.a+122=122

1.a=122-122

1.a=0

a=0:1

a=0

học tốt! k mình nha!!!!!!!!!!!!!!!!!!

1.1.1.1.1.1.1.1.1.1.1.1..a+122=122

=>1.a+122=122

=>a+122=122

=>a=0

122 x 122 = 14884

chuẩn

122 + 122 = 244

Mình nhanh nhất!

122 + 122 = 244

35678

150548

136884

35678

150548

1369084

k nha

215 + 43 - 15 - 23

= (215 - 15) + (43 - 23)

= 200 + 20

= 220

2022 - (122 + 2022) + (122 - 325)

= 2022 - 122 - 2022 + 122 - 325

= (2022 - 2022) - (122 - 122) - 325

= 0 - 0  - 325

= - 325 

12.(-137) + 12.136

= 12.( -137 + 136)

= 12.(-1)

= - 12

Ta có: \(\frac{1}{2^2}<\frac{1}{1\cdot2}=1-\frac12\)

\(\frac{1}{3^2}<\frac{1}{2\cdot3}=\frac12-\frac13\)

...

\(\frac{1}{10^2}<\frac{1}{9\cdot10}=\frac19-\frac{1}{10}\)

Do đó: \(\frac{1}{2^2}+\frac{1}{3^2}+\cdots+\frac{1}{10^2}<1-\frac12+\frac12-\frac13+\cdots+\frac19-\frac{1}{10}\)

=>\(A<1-\frac{1}{10}\)

=>A<1

Ta có: \(S=\frac{1}{2^2}-\frac{1}{2^4}+\frac{1}{2^6}-\frac{1}{2^8}+\cdots+\frac{1}{2^{2002}}-\frac{1}{2^{2004}}\)

=>4S=\(1-\frac{1}{2^2}+\frac{1}{2^4}-\frac{1}{2^6}+\cdots+\frac{1}{2^{2000}}-\frac{1}{2^{2002}}\)

=>4S+S=\(1-\frac{1}{2^2}+\frac{1}{2^4}-\frac{1}{2^6}+\cdots+\frac{1}{2^{2000}}-\frac{1}{2^{2002}}+1-\frac{1}{2^2}+\frac{1}{2^4}-\frac{1}{2^6}+\cdots+\frac{1}{2^{2000}}-\frac{1}{2^{2002}}\)

=>5S=\(1-\frac{1}{2^{2002}}\)

=>5S<1

=>S<0,2