\(\dfrac{10^2+11^2+12^2}{13^2+14^2}=\dfrac{100+121+144}{169+196}\)

\(=\dfrac{365}{365}=1\)

D=(102+112+122):(132+142)

D =(100+121+144) / (169+196)

D =365 / 365

D = 1

Đề là \(D=\left(10^2+11^2+12^2\right):\left(13^2+14^2\right)\) cậu thêm mũ vào nhé.

( 100 + 121 + 144 ) : ( 169 + 196 )

= 365 : 365 = 1

\(\left(10^2+11^2+12^2\right):\left(13^2+14^2\right)\)

\(=\left(100+121+144\right):\left(169+196\right)\)

\(=\left(221+144\right):365\)

\(=365:365\)

\(=1\)Vậy kết quả = 1

a: \(\left(10^2+11^2+12^2\right):\left(13^2+14^2\right)\)

\(=\frac{100+121+144}{169+196}=\frac{365}{365}=1\)

b: \(1\cdot2\cdot3\cdot\ldots\cdot9-1\cdot2\cdot3\cdot\ldots\cdot8-1\cdot2\cdot3\cdot\ldots\cdot7\cdot8^2\)

\(=1\cdot2\cdot3\cdot\ldots\cdot8\cdot\left(9-1-8\right)\)

=0

c: \(\frac{\left(3\cdot4\cdot2^{16}\right)^2}{11\cdot2^{13}\cdot4^{11}-16^9}=\frac{\left(3\cdot2^{18}\right)^2}{11\cdot2^{13}\cdot2^{22}-2^{36}}=\frac{3^2\cdot2^{36}}{2^{35}\cdot\left(11-2\right)}=2\)

d: 1152-(374+1152)+(-65+374)

=1152-374-1152-65+374

=-65

\(\left(10^2+11^2+12^2\right):\left(13^2+14^2\right)\)

\(=\left(100+121+144\right):\left(169+196\right)\)

\(=365:365\)

\(=1\)

\(\left(10^2+11^2+12^2\right):\left(13^2+14^2\right)\)

\(=\left(100+121+144\right):\left(169+196\right)\)

\(=\frac{365}{365}=1\)

(10² + 11² + 12²) : (13² + 14²)

= (100 + 121 + 144) : (169 + 196)

= 365 : 365

= 1

Ủng hộ mk nha ^_-

a) =\(\left[\left(12+1\right)^2+\left(12+2\right)^2\right]:\left(13^2+14^2\right)\)

   =1

b)=(1.2.3....8).(9-1-8)

   =(1.2.3....8).0

   =0

mik chỉ giải được zậy thôi.

t mik nha.

a,(10^2+11^2+12^2):(13^2+14^2)

=(100+121+144);(169+196)

=365:365

=1

b,1.2.3...9-1.2.3...8-1.2.3...8^2=0

a)=(100+121+144):(169+196)=365:365=1

b)=1.2.3...8.(9-1-8)=1.2.3...8.0=0

k mk nhaa

\(a,\dfrac{121.75.130.169}{39.60.11.198}=\dfrac{11.11.25.3.13.10.169}{13.3.6.10.11.11.18}=\dfrac{25.169}{6.18}\)

còn bài tính hợp lí và tính nhanh thì sao bạn