812 -x :11=46
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\(812-x:11=46\)
\(x:11=812-46\)
\(x:11=766\)
\(x=766x11\)
\(x=8426\)
Vậy x=8426
812 - x : 11 = 46
812 - x = 46 x 11
812 - x = 506
x = 812 - 506
x = 306
812 - X = 46 x 11
812 - X = 506
X = 812 - 506
X = 306
xin cậu đấy tk mình đi
a: \(3^2\cdot\frac{1}{243}\cdot81^2\cdot\frac{1}{3^2}\)
\(=\frac{3^2}{3^5}\cdot\frac{3^8}{3^2}=\frac{1}{3^3}\cdot3^6=3^3=27\)
b: \(4^6\cdot256^2\cdot2^4=\left(2^2\right)^6\cdot\left(2^8\right)^2\cdot2^4\)
\(=2^{12}\cdot2^{16}\cdot2^4=2^{12}\cdot2^{20}=2^{32}\)
c: \(4^6\cdot9^5+6^9\cdot120\)
\(=2^{12}\cdot3^{10}+2^9\cdot3^9\cdot2^3\cdot3\cdot5\)
\(=2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5\)
\(=2^{12}\cdot3^{10}\cdot6=2^{13}\cdot3^{11}\)
Ta có \(8^4\cdot3^{12}-6^{11}\)
\(=2^{12}\cdot3^{12}-2^{11}\cdot3^{11}\)
\(=2^{11}\cdot3^{11}\left(2\cdot3-1\right)=2^{11}\cdot3^{11}\cdot5\)
Ta có: \(A=\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)
\(=\frac{2^{13}\cdot3^{11}}{2^{11}\cdot3^{11}\cdot5}=\frac{2^2}{5}=\frac45\)
d: \(4^2\cdot25^2+32\cdot125\)
\(=2^4\cdot5^4+2^5\cdot5^3\)
\(=2^4\cdot5^3\left(5+2\right)=2^4\cdot5^3\cdot7\)
\(B=\frac{4^2\cdot25^2+32\cdot125}{2^3\cdot5^2}\)
\(=\frac{2^4\cdot5^3\cdot7}{2^3\cdot5^2}=2\cdot5\cdot7=70\)
a) =(-4).(-25).125.(-8).(-11)
= 100.(-1000).(-11)
= (-100000).(-11)
= 1100000
b) =(-823)+823 . 812-812.823
=(-823)+(823.812-812.823)
= (-823) +0
=-823
k giùm mình nha!
Hok tốt!
Bài 1:
a.
$-12-(-46)=-12+46=46-12=34$
b.
$-(-8)-54=8-54=-(54-8)=-46$
c.
$-15-(-72)=-15+72=72-15=57$
Bài 2:
a. $(156-812)-(156-12)=156-812-156+12$
$=(156-156)-(812-12)=0-800=-800$
b.
$-(-72+83)-(72+17)=72-83-72-17=(72-72)-(83+17)$
$=0-100=-100$
c.
$-(-23-78)+(77-178)=23+78+77-178$
$=(23+77)-(178-78)=100-100=0$
d.
$(-213-156)-(-213+44)=-213-156+213-44=(-213+213)-(156+44)$
$=0-200=-200$
\(812-x:11=46\)
\(-x:11=46-812\)
\(-x:11=-766\)
\(-x=\left(-766\right)\times11\)
\(-x=-8426\)
\(x=8426\)
812 - x : 11 = 46
=> x : 11 = 812 - 46
=> x : 11 = 766
=> x = 766 * 11
=> x = 8426
Đáp số : x = 8427